Asymptotic behavior of a function. Saddle point method.
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I have a question concerning the saddle point method of steepest decent. I know how tu use this method when the $lambdato infty$ in
$$int_C f(z)exp^lambda g(z),,$$
but i have no clue how to use it when the $lambdato infty$ in the following case
$$int_C f(z)exp^-lambda g(z).$$
In first case I am querying for the steepest descent method. But in the second should I choose the method of steepest ascent then?
asymptotics gamma-function bessel-functions
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up vote
-1
down vote
favorite
I have a question concerning the saddle point method of steepest decent. I know how tu use this method when the $lambdato infty$ in
$$int_C f(z)exp^lambda g(z),,$$
but i have no clue how to use it when the $lambdato infty$ in the following case
$$int_C f(z)exp^-lambda g(z).$$
In first case I am querying for the steepest descent method. But in the second should I choose the method of steepest ascent then?
asymptotics gamma-function bessel-functions
1
You should just define $h(z) = -g(z)$, then use the method as in the first case.
â Antonio Vargas
Sep 11 at 4:10
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I have a question concerning the saddle point method of steepest decent. I know how tu use this method when the $lambdato infty$ in
$$int_C f(z)exp^lambda g(z),,$$
but i have no clue how to use it when the $lambdato infty$ in the following case
$$int_C f(z)exp^-lambda g(z).$$
In first case I am querying for the steepest descent method. But in the second should I choose the method of steepest ascent then?
asymptotics gamma-function bessel-functions
I have a question concerning the saddle point method of steepest decent. I know how tu use this method when the $lambdato infty$ in
$$int_C f(z)exp^lambda g(z),,$$
but i have no clue how to use it when the $lambdato infty$ in the following case
$$int_C f(z)exp^-lambda g(z).$$
In first case I am querying for the steepest descent method. But in the second should I choose the method of steepest ascent then?
asymptotics gamma-function bessel-functions
asymptotics gamma-function bessel-functions
asked Sep 10 at 21:08
Sebastian Pinocy
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1
You should just define $h(z) = -g(z)$, then use the method as in the first case.
â Antonio Vargas
Sep 11 at 4:10
add a comment |Â
1
You should just define $h(z) = -g(z)$, then use the method as in the first case.
â Antonio Vargas
Sep 11 at 4:10
1
1
You should just define $h(z) = -g(z)$, then use the method as in the first case.
â Antonio Vargas
Sep 11 at 4:10
You should just define $h(z) = -g(z)$, then use the method as in the first case.
â Antonio Vargas
Sep 11 at 4:10
add a comment |Â
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1
You should just define $h(z) = -g(z)$, then use the method as in the first case.
â Antonio Vargas
Sep 11 at 4:10