Find an equation of the tangent line to the graph of [closed]

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Find an equation of the tangent line to the graph of $F(x)=x^2$ at



  1. $(3, 9)$


  2. $(-1, 1)$


  3. $(10, 100)$










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closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
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  • Have you any ideas what to do?
    – EuklidAlexandria
    Sep 10 at 19:42










  • Welcome to math.SE, could you tell us what you've tried, or what's your thought?
    – Yujie Zha
    Sep 10 at 19:42






  • 1




    Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
    – JMoravitz
    Sep 10 at 19:42














up vote
-1
down vote

favorite












Find an equation of the tangent line to the graph of $F(x)=x^2$ at



  1. $(3, 9)$


  2. $(-1, 1)$


  3. $(10, 100)$










share|cite|improve this question















closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
If this question can be reworded to fit the rules in the help center, please edit the question.












  • Have you any ideas what to do?
    – EuklidAlexandria
    Sep 10 at 19:42










  • Welcome to math.SE, could you tell us what you've tried, or what's your thought?
    – Yujie Zha
    Sep 10 at 19:42






  • 1




    Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
    – JMoravitz
    Sep 10 at 19:42












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











Find an equation of the tangent line to the graph of $F(x)=x^2$ at



  1. $(3, 9)$


  2. $(-1, 1)$


  3. $(10, 100)$










share|cite|improve this question















Find an equation of the tangent line to the graph of $F(x)=x^2$ at



  1. $(3, 9)$


  2. $(-1, 1)$


  3. $(10, 100)$







derivatives






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edited Sep 10 at 19:42









Yujie Zha

6,82811629




6,82811629










asked Sep 10 at 19:40









Beeze

33




33




closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
If this question can be reworded to fit the rules in the help center, please edit the question.











  • Have you any ideas what to do?
    – EuklidAlexandria
    Sep 10 at 19:42










  • Welcome to math.SE, could you tell us what you've tried, or what's your thought?
    – Yujie Zha
    Sep 10 at 19:42






  • 1




    Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
    – JMoravitz
    Sep 10 at 19:42
















  • Have you any ideas what to do?
    – EuklidAlexandria
    Sep 10 at 19:42










  • Welcome to math.SE, could you tell us what you've tried, or what's your thought?
    – Yujie Zha
    Sep 10 at 19:42






  • 1




    Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
    – JMoravitz
    Sep 10 at 19:42















Have you any ideas what to do?
– EuklidAlexandria
Sep 10 at 19:42




Have you any ideas what to do?
– EuklidAlexandria
Sep 10 at 19:42












Welcome to math.SE, could you tell us what you've tried, or what's your thought?
– Yujie Zha
Sep 10 at 19:42




Welcome to math.SE, could you tell us what you've tried, or what's your thought?
– Yujie Zha
Sep 10 at 19:42




1




1




Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
– JMoravitz
Sep 10 at 19:42




Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
– JMoravitz
Sep 10 at 19:42










1 Answer
1






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up vote
0
down vote



accepted










If I do the first one you can apply it to the other two.



The slope of the tangent line is the derivative of $x^2 = 2x$



At point $(3, 9)$ the slope is $6$



The equation of the line going through $(3, 9$) with slope $6$ is:



$y = 6x + b$ where $b$ is the y intercept



$9 = 6(3) + b$



$b = 9 - 18 = -9$



Equation is: $y = 6x - 9$






share|cite|improve this answer



























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    If I do the first one you can apply it to the other two.



    The slope of the tangent line is the derivative of $x^2 = 2x$



    At point $(3, 9)$ the slope is $6$



    The equation of the line going through $(3, 9$) with slope $6$ is:



    $y = 6x + b$ where $b$ is the y intercept



    $9 = 6(3) + b$



    $b = 9 - 18 = -9$



    Equation is: $y = 6x - 9$






    share|cite|improve this answer
























      up vote
      0
      down vote



      accepted










      If I do the first one you can apply it to the other two.



      The slope of the tangent line is the derivative of $x^2 = 2x$



      At point $(3, 9)$ the slope is $6$



      The equation of the line going through $(3, 9$) with slope $6$ is:



      $y = 6x + b$ where $b$ is the y intercept



      $9 = 6(3) + b$



      $b = 9 - 18 = -9$



      Equation is: $y = 6x - 9$






      share|cite|improve this answer






















        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        If I do the first one you can apply it to the other two.



        The slope of the tangent line is the derivative of $x^2 = 2x$



        At point $(3, 9)$ the slope is $6$



        The equation of the line going through $(3, 9$) with slope $6$ is:



        $y = 6x + b$ where $b$ is the y intercept



        $9 = 6(3) + b$



        $b = 9 - 18 = -9$



        Equation is: $y = 6x - 9$






        share|cite|improve this answer












        If I do the first one you can apply it to the other two.



        The slope of the tangent line is the derivative of $x^2 = 2x$



        At point $(3, 9)$ the slope is $6$



        The equation of the line going through $(3, 9$) with slope $6$ is:



        $y = 6x + b$ where $b$ is the y intercept



        $9 = 6(3) + b$



        $b = 9 - 18 = -9$



        Equation is: $y = 6x - 9$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Sep 10 at 22:59









        Phil H

        2,4582311




        2,4582311












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