Find an equation of the tangent line to the graph of [closed]
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Find an equation of the tangent line to the graph of $F(x)=x^2$ at
$(3, 9)$
$(-1, 1)$
$(10, 100)$
derivatives
closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
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up vote
-1
down vote
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Find an equation of the tangent line to the graph of $F(x)=x^2$ at
$(3, 9)$
$(-1, 1)$
$(10, 100)$
derivatives
closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
Have you any ideas what to do?
â EuklidAlexandria
Sep 10 at 19:42
Welcome to math.SE, could you tell us what you've tried, or what's your thought?
â Yujie Zha
Sep 10 at 19:42
1
Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
â JMoravitz
Sep 10 at 19:42
add a comment |Â
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Find an equation of the tangent line to the graph of $F(x)=x^2$ at
$(3, 9)$
$(-1, 1)$
$(10, 100)$
derivatives
Find an equation of the tangent line to the graph of $F(x)=x^2$ at
$(3, 9)$
$(-1, 1)$
$(10, 100)$
derivatives
derivatives
edited Sep 10 at 19:42
Yujie Zha
6,82811629
6,82811629
asked Sep 10 at 19:40
Beeze
33
33
closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
closed as off-topic by JMoravitz, Theoretical Economist, amWhy, Leucippus, user99914 Sep 11 at 1:34
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." â JMoravitz, Theoretical Economist, amWhy, Leucippus, Community
Have you any ideas what to do?
â EuklidAlexandria
Sep 10 at 19:42
Welcome to math.SE, could you tell us what you've tried, or what's your thought?
â Yujie Zha
Sep 10 at 19:42
1
Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
â JMoravitz
Sep 10 at 19:42
add a comment |Â
Have you any ideas what to do?
â EuklidAlexandria
Sep 10 at 19:42
Welcome to math.SE, could you tell us what you've tried, or what's your thought?
â Yujie Zha
Sep 10 at 19:42
1
Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
â JMoravitz
Sep 10 at 19:42
Have you any ideas what to do?
â EuklidAlexandria
Sep 10 at 19:42
Have you any ideas what to do?
â EuklidAlexandria
Sep 10 at 19:42
Welcome to math.SE, could you tell us what you've tried, or what's your thought?
â Yujie Zha
Sep 10 at 19:42
Welcome to math.SE, could you tell us what you've tried, or what's your thought?
â Yujie Zha
Sep 10 at 19:42
1
1
Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
â JMoravitz
Sep 10 at 19:42
Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
â JMoravitz
Sep 10 at 19:42
add a comment |Â
1 Answer
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If I do the first one you can apply it to the other two.
The slope of the tangent line is the derivative of $x^2 = 2x$
At point $(3, 9)$ the slope is $6$
The equation of the line going through $(3, 9$) with slope $6$ is:
$y = 6x + b$ where $b$ is the y intercept
$9 = 6(3) + b$
$b = 9 - 18 = -9$
Equation is: $y = 6x - 9$
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
If I do the first one you can apply it to the other two.
The slope of the tangent line is the derivative of $x^2 = 2x$
At point $(3, 9)$ the slope is $6$
The equation of the line going through $(3, 9$) with slope $6$ is:
$y = 6x + b$ where $b$ is the y intercept
$9 = 6(3) + b$
$b = 9 - 18 = -9$
Equation is: $y = 6x - 9$
add a comment |Â
up vote
0
down vote
accepted
If I do the first one you can apply it to the other two.
The slope of the tangent line is the derivative of $x^2 = 2x$
At point $(3, 9)$ the slope is $6$
The equation of the line going through $(3, 9$) with slope $6$ is:
$y = 6x + b$ where $b$ is the y intercept
$9 = 6(3) + b$
$b = 9 - 18 = -9$
Equation is: $y = 6x - 9$
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
If I do the first one you can apply it to the other two.
The slope of the tangent line is the derivative of $x^2 = 2x$
At point $(3, 9)$ the slope is $6$
The equation of the line going through $(3, 9$) with slope $6$ is:
$y = 6x + b$ where $b$ is the y intercept
$9 = 6(3) + b$
$b = 9 - 18 = -9$
Equation is: $y = 6x - 9$
If I do the first one you can apply it to the other two.
The slope of the tangent line is the derivative of $x^2 = 2x$
At point $(3, 9)$ the slope is $6$
The equation of the line going through $(3, 9$) with slope $6$ is:
$y = 6x + b$ where $b$ is the y intercept
$9 = 6(3) + b$
$b = 9 - 18 = -9$
Equation is: $y = 6x - 9$
answered Sep 10 at 22:59
Phil H
2,4582311
2,4582311
add a comment |Â
add a comment |Â
Have you any ideas what to do?
â EuklidAlexandria
Sep 10 at 19:42
Welcome to math.SE, could you tell us what you've tried, or what's your thought?
â Yujie Zha
Sep 10 at 19:42
1
Step 1: Find the derivative of $F(x)=x^2$ with respect to $x$ as a function of $x$. Step 2: Interpret what the derivative represents. By plugging in specific values of $x$ into the derivative, you get the slope of the original function at that $x$-value. Step 3: Describe the line using what information you have (points and slopes).
â JMoravitz
Sep 10 at 19:42