Solution of the second-order ODE with polynomial coefficients $(a-x),x, y''(x)+left(fraca2-2 ,xright)y'(x)+lambda ,x^2y(x)=0$.

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I am searching for solutions of the following second order differential equation:




$$(a-x),x, y''(x)+left(fraca2-2 ,xright)y'(x)+lambda ,x^2y(x)=0,qquad (0<x<a)$$
with $y(a)=0$ and $y'(0)=0$.




As far as I know, there is no finite polynomial solution. In a book I have found a solution when the factor $x^2$ in the last term is replaced by 1.



EDIT: Boundedness of $y(x)$ for $xto 0$ is an alternative condition (instead of $y'(0)=0$).







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  • 2




    If the Wolfram Dev Platform doesn't give you a closed-form solution, there probably isn't one. If you have to have an exact solution, then a series method is your only option, most likely. Otherwise, of course, you could always go numerical.
    – Adrian Keister
    Aug 27 at 17:12






  • 1




    Even with series, the condition $y(a)=0$ would make the problem very difficult.
    – Claude Leibovici
    Aug 28 at 4:04










  • @Claude is there an alternative condition which brings out a closed form solution?
    – kaffeeauf
    Aug 28 at 5:27






  • 1




    Maple 2018.1 gives general solution with HeunC function adding boundary conditions: $y(a)=0$,$y'(0)=0$ spit up one solution: $y(x)=0$
    – Mariusz Iwaniuk
    Aug 28 at 10:22







  • 1




    $$y left( x right) =frac it _C1,rm e^sqrt lambdax sqrt x-ait HeunC left( 2,asqrt lambda,-1/2,-1/2,-lambda ,a^2,1/8,frac xa right) +frac it _C2,rm e^ sqrt lambdaxsqrt xsqrt x-ait HeunC left( 2,asqrt lambda,1/2,-1/2,-lambda,a^2,1/8,frac xa right) $$ where: $_C1$,$_C2$ integration constans.
    – Mariusz Iwaniuk
    Aug 28 at 16:38















up vote
2
down vote

favorite
1












I am searching for solutions of the following second order differential equation:




$$(a-x),x, y''(x)+left(fraca2-2 ,xright)y'(x)+lambda ,x^2y(x)=0,qquad (0<x<a)$$
with $y(a)=0$ and $y'(0)=0$.




As far as I know, there is no finite polynomial solution. In a book I have found a solution when the factor $x^2$ in the last term is replaced by 1.



EDIT: Boundedness of $y(x)$ for $xto 0$ is an alternative condition (instead of $y'(0)=0$).







share|cite|improve this question


















  • 2




    If the Wolfram Dev Platform doesn't give you a closed-form solution, there probably isn't one. If you have to have an exact solution, then a series method is your only option, most likely. Otherwise, of course, you could always go numerical.
    – Adrian Keister
    Aug 27 at 17:12






  • 1




    Even with series, the condition $y(a)=0$ would make the problem very difficult.
    – Claude Leibovici
    Aug 28 at 4:04










  • @Claude is there an alternative condition which brings out a closed form solution?
    – kaffeeauf
    Aug 28 at 5:27






  • 1




    Maple 2018.1 gives general solution with HeunC function adding boundary conditions: $y(a)=0$,$y'(0)=0$ spit up one solution: $y(x)=0$
    – Mariusz Iwaniuk
    Aug 28 at 10:22







  • 1




    $$y left( x right) =frac it _C1,rm e^sqrt lambdax sqrt x-ait HeunC left( 2,asqrt lambda,-1/2,-1/2,-lambda ,a^2,1/8,frac xa right) +frac it _C2,rm e^ sqrt lambdaxsqrt xsqrt x-ait HeunC left( 2,asqrt lambda,1/2,-1/2,-lambda,a^2,1/8,frac xa right) $$ where: $_C1$,$_C2$ integration constans.
    – Mariusz Iwaniuk
    Aug 28 at 16:38













up vote
2
down vote

favorite
1









up vote
2
down vote

favorite
1






1





I am searching for solutions of the following second order differential equation:




$$(a-x),x, y''(x)+left(fraca2-2 ,xright)y'(x)+lambda ,x^2y(x)=0,qquad (0<x<a)$$
with $y(a)=0$ and $y'(0)=0$.




As far as I know, there is no finite polynomial solution. In a book I have found a solution when the factor $x^2$ in the last term is replaced by 1.



EDIT: Boundedness of $y(x)$ for $xto 0$ is an alternative condition (instead of $y'(0)=0$).







share|cite|improve this question














I am searching for solutions of the following second order differential equation:




$$(a-x),x, y''(x)+left(fraca2-2 ,xright)y'(x)+lambda ,x^2y(x)=0,qquad (0<x<a)$$
with $y(a)=0$ and $y'(0)=0$.




As far as I know, there is no finite polynomial solution. In a book I have found a solution when the factor $x^2$ in the last term is replaced by 1.



EDIT: Boundedness of $y(x)$ for $xto 0$ is an alternative condition (instead of $y'(0)=0$).









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 28 at 16:26









Nosrati

21.9k51747




21.9k51747










asked Aug 27 at 17:04









kaffeeauf

1409




1409







  • 2




    If the Wolfram Dev Platform doesn't give you a closed-form solution, there probably isn't one. If you have to have an exact solution, then a series method is your only option, most likely. Otherwise, of course, you could always go numerical.
    – Adrian Keister
    Aug 27 at 17:12






  • 1




    Even with series, the condition $y(a)=0$ would make the problem very difficult.
    – Claude Leibovici
    Aug 28 at 4:04










  • @Claude is there an alternative condition which brings out a closed form solution?
    – kaffeeauf
    Aug 28 at 5:27






  • 1




    Maple 2018.1 gives general solution with HeunC function adding boundary conditions: $y(a)=0$,$y'(0)=0$ spit up one solution: $y(x)=0$
    – Mariusz Iwaniuk
    Aug 28 at 10:22







  • 1




    $$y left( x right) =frac it _C1,rm e^sqrt lambdax sqrt x-ait HeunC left( 2,asqrt lambda,-1/2,-1/2,-lambda ,a^2,1/8,frac xa right) +frac it _C2,rm e^ sqrt lambdaxsqrt xsqrt x-ait HeunC left( 2,asqrt lambda,1/2,-1/2,-lambda,a^2,1/8,frac xa right) $$ where: $_C1$,$_C2$ integration constans.
    – Mariusz Iwaniuk
    Aug 28 at 16:38













  • 2




    If the Wolfram Dev Platform doesn't give you a closed-form solution, there probably isn't one. If you have to have an exact solution, then a series method is your only option, most likely. Otherwise, of course, you could always go numerical.
    – Adrian Keister
    Aug 27 at 17:12






  • 1




    Even with series, the condition $y(a)=0$ would make the problem very difficult.
    – Claude Leibovici
    Aug 28 at 4:04










  • @Claude is there an alternative condition which brings out a closed form solution?
    – kaffeeauf
    Aug 28 at 5:27






  • 1




    Maple 2018.1 gives general solution with HeunC function adding boundary conditions: $y(a)=0$,$y'(0)=0$ spit up one solution: $y(x)=0$
    – Mariusz Iwaniuk
    Aug 28 at 10:22







  • 1




    $$y left( x right) =frac it _C1,rm e^sqrt lambdax sqrt x-ait HeunC left( 2,asqrt lambda,-1/2,-1/2,-lambda ,a^2,1/8,frac xa right) +frac it _C2,rm e^ sqrt lambdaxsqrt xsqrt x-ait HeunC left( 2,asqrt lambda,1/2,-1/2,-lambda,a^2,1/8,frac xa right) $$ where: $_C1$,$_C2$ integration constans.
    – Mariusz Iwaniuk
    Aug 28 at 16:38








2




2




If the Wolfram Dev Platform doesn't give you a closed-form solution, there probably isn't one. If you have to have an exact solution, then a series method is your only option, most likely. Otherwise, of course, you could always go numerical.
– Adrian Keister
Aug 27 at 17:12




If the Wolfram Dev Platform doesn't give you a closed-form solution, there probably isn't one. If you have to have an exact solution, then a series method is your only option, most likely. Otherwise, of course, you could always go numerical.
– Adrian Keister
Aug 27 at 17:12




1




1




Even with series, the condition $y(a)=0$ would make the problem very difficult.
– Claude Leibovici
Aug 28 at 4:04




Even with series, the condition $y(a)=0$ would make the problem very difficult.
– Claude Leibovici
Aug 28 at 4:04












@Claude is there an alternative condition which brings out a closed form solution?
– kaffeeauf
Aug 28 at 5:27




@Claude is there an alternative condition which brings out a closed form solution?
– kaffeeauf
Aug 28 at 5:27




1




1




Maple 2018.1 gives general solution with HeunC function adding boundary conditions: $y(a)=0$,$y'(0)=0$ spit up one solution: $y(x)=0$
– Mariusz Iwaniuk
Aug 28 at 10:22





Maple 2018.1 gives general solution with HeunC function adding boundary conditions: $y(a)=0$,$y'(0)=0$ spit up one solution: $y(x)=0$
– Mariusz Iwaniuk
Aug 28 at 10:22





1




1




$$y left( x right) =frac it _C1,rm e^sqrt lambdax sqrt x-ait HeunC left( 2,asqrt lambda,-1/2,-1/2,-lambda ,a^2,1/8,frac xa right) +frac it _C2,rm e^ sqrt lambdaxsqrt xsqrt x-ait HeunC left( 2,asqrt lambda,1/2,-1/2,-lambda,a^2,1/8,frac xa right) $$ where: $_C1$,$_C2$ integration constans.
– Mariusz Iwaniuk
Aug 28 at 16:38





$$y left( x right) =frac it _C1,rm e^sqrt lambdax sqrt x-ait HeunC left( 2,asqrt lambda,-1/2,-1/2,-lambda ,a^2,1/8,frac xa right) +frac it _C2,rm e^ sqrt lambdaxsqrt xsqrt x-ait HeunC left( 2,asqrt lambda,1/2,-1/2,-lambda,a^2,1/8,frac xa right) $$ where: $_C1$,$_C2$ integration constans.
– Mariusz Iwaniuk
Aug 28 at 16:38
















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