Simple way of denoting a condition on a long equation

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I have a few equations that are rather long. They are 0 if the long part would become negative. Let's say they look something like
$$ x =begincases a+b-cd &quad textif a+b-cd > 0\0 &quad textotherwise.endcases $$
Now I would prefer not to write the whole long part again. Is there a simple way of writing this? I was looking for something like
$$ x =begincases a+b-cd &quad textif x>0\0 &quad textotherwise.endcases$$
In my case there is no way of simplifying the expression $a+b-cd$.
Thanks for your help.




notation




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  • This notation doesn't work because the value of $x$ is still undefined when you compare it to $0$.
    – Yves Daoust
    Aug 13 at 9:11














up vote
2
down vote

favorite
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I have a few equations that are rather long. They are 0 if the long part would become negative. Let's say they look something like
$$ x =begincases a+b-cd &quad textif a+b-cd > 0\0 &quad textotherwise.endcases $$
Now I would prefer not to write the whole long part again. Is there a simple way of writing this? I was looking for something like
$$ x =begincases a+b-cd &quad textif x>0\0 &quad textotherwise.endcases$$
In my case there is no way of simplifying the expression $a+b-cd$.
Thanks for your help.




notation




share|cite|improve this question






















  • This notation doesn't work because the value of $x$ is still undefined when you compare it to $0$.
    – Yves Daoust
    Aug 13 at 9:11












up vote
2
down vote

favorite
1









up vote
2
down vote

favorite
1






1





I have a few equations that are rather long. They are 0 if the long part would become negative. Let's say they look something like
$$ x =begincases a+b-cd &quad textif a+b-cd > 0\0 &quad textotherwise.endcases $$
Now I would prefer not to write the whole long part again. Is there a simple way of writing this? I was looking for something like
$$ x =begincases a+b-cd &quad textif x>0\0 &quad textotherwise.endcases$$
In my case there is no way of simplifying the expression $a+b-cd$.
Thanks for your help.




notation




share|cite|improve this question














I have a few equations that are rather long. They are 0 if the long part would become negative. Let's say they look something like
$$ x =begincases a+b-cd &quad textif a+b-cd > 0\0 &quad textotherwise.endcases $$
Now I would prefer not to write the whole long part again. Is there a simple way of writing this? I was looking for something like
$$ x =begincases a+b-cd &quad textif x>0\0 &quad textotherwise.endcases$$
In my case there is no way of simplifying the expression $a+b-cd$.
Thanks for your help.





notation





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edited Aug 13 at 14:06

























asked Aug 13 at 8:49









user3460824

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  • This notation doesn't work because the value of $x$ is still undefined when you compare it to $0$.
    – Yves Daoust
    Aug 13 at 9:11
















  • This notation doesn't work because the value of $x$ is still undefined when you compare it to $0$.
    – Yves Daoust
    Aug 13 at 9:11















This notation doesn't work because the value of $x$ is still undefined when you compare it to $0$.
– Yves Daoust
Aug 13 at 9:11




This notation doesn't work because the value of $x$ is still undefined when you compare it to $0$.
– Yves Daoust
Aug 13 at 9:11










1 Answer
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Superscript $cdot^+$ is the way to go
$$
x = (a + b - cd)^+ := max(0, a + b - cd).
$$






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  • that's exactly the definition of superscript +, as indicated in my answer.
    – pointguard0
    Aug 13 at 9:13










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1 Answer
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active

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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes








up vote
3
down vote



accepted










Superscript $cdot^+$ is the way to go
$$
x = (a + b - cd)^+ := max(0, a + b - cd).
$$






share|cite|improve this answer




















  • that's exactly the definition of superscript +, as indicated in my answer.
    – pointguard0
    Aug 13 at 9:13














up vote
3
down vote



accepted










Superscript $cdot^+$ is the way to go
$$
x = (a + b - cd)^+ := max(0, a + b - cd).
$$






share|cite|improve this answer




















  • that's exactly the definition of superscript +, as indicated in my answer.
    – pointguard0
    Aug 13 at 9:13












up vote
3
down vote



accepted







up vote
3
down vote



accepted






Superscript $cdot^+$ is the way to go
$$
x = (a + b - cd)^+ := max(0, a + b - cd).
$$






share|cite|improve this answer












Superscript $cdot^+$ is the way to go
$$
x = (a + b - cd)^+ := max(0, a + b - cd).
$$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Aug 13 at 9:01









pointguard0

1,269821




1,269821











  • that's exactly the definition of superscript +, as indicated in my answer.
    – pointguard0
    Aug 13 at 9:13
















  • that's exactly the definition of superscript +, as indicated in my answer.
    – pointguard0
    Aug 13 at 9:13















that's exactly the definition of superscript +, as indicated in my answer.
– pointguard0
Aug 13 at 9:13




that's exactly the definition of superscript +, as indicated in my answer.
– pointguard0
Aug 13 at 9:13












 

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