Pushforward formula for Lebesgue Stieltjes Measure

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Problem
Let $F: mathbbRrightarrow mathbbR$ be an increasing, right continuous function, and let $phi :mathbbRrightarrow mathbbR$ be a continuous increasing invertible function. Let $mu_F$ and $mu_Fcirc phi$ be the Lebesgue-Stieljes measure associated to $F$ and $Fcirc phi$ respectively. Show that if $fin L^1(mu_F)$, then $fcirc phi in L^1(mu_Fcirc phi)$ and $$ int f dmu_F = int fcirc phi dmu_Fcirc phi$$ Hint: It is enough to consider non-negative $f$ and to prove the inequality $int fcirc phi dmu_Fcirc phileq int fmu_F$.




There were many situation I have studied this kind of problem and I was thinking of using simple function and generalize it to arbitrary $L^1$ functions. And I think the method just works here too. But I can not understand the hint on this problem. Because I started from simple, the hint for non negative function seems superfluous but makes sense. But I don't know how to use the hint for inequality. I will be happy with any kind of hint or comment on it. Thank you in advance!







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  • 1




    If you prove the hint for positive functions, you show that $fcirc phi in L^1(mu_Fcirc phi)$, since you are taking absolute values in any case. The change of variables formula is, indeed, proven using simple functions.
    – Dosidis
    Aug 16 at 3:25











  • @Dosidis That make sense! Thank you! But I still don't know how to use the inequality....
    – Lev Ban
    Aug 16 at 18:11














up vote
1
down vote

favorite












I got to have this problem in my hand.




Problem
Let $F: mathbbRrightarrow mathbbR$ be an increasing, right continuous function, and let $phi :mathbbRrightarrow mathbbR$ be a continuous increasing invertible function. Let $mu_F$ and $mu_Fcirc phi$ be the Lebesgue-Stieljes measure associated to $F$ and $Fcirc phi$ respectively. Show that if $fin L^1(mu_F)$, then $fcirc phi in L^1(mu_Fcirc phi)$ and $$ int f dmu_F = int fcirc phi dmu_Fcirc phi$$ Hint: It is enough to consider non-negative $f$ and to prove the inequality $int fcirc phi dmu_Fcirc phileq int fmu_F$.




There were many situation I have studied this kind of problem and I was thinking of using simple function and generalize it to arbitrary $L^1$ functions. And I think the method just works here too. But I can not understand the hint on this problem. Because I started from simple, the hint for non negative function seems superfluous but makes sense. But I don't know how to use the hint for inequality. I will be happy with any kind of hint or comment on it. Thank you in advance!







share|cite|improve this question


















  • 1




    If you prove the hint for positive functions, you show that $fcirc phi in L^1(mu_Fcirc phi)$, since you are taking absolute values in any case. The change of variables formula is, indeed, proven using simple functions.
    – Dosidis
    Aug 16 at 3:25











  • @Dosidis That make sense! Thank you! But I still don't know how to use the inequality....
    – Lev Ban
    Aug 16 at 18:11












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I got to have this problem in my hand.




Problem
Let $F: mathbbRrightarrow mathbbR$ be an increasing, right continuous function, and let $phi :mathbbRrightarrow mathbbR$ be a continuous increasing invertible function. Let $mu_F$ and $mu_Fcirc phi$ be the Lebesgue-Stieljes measure associated to $F$ and $Fcirc phi$ respectively. Show that if $fin L^1(mu_F)$, then $fcirc phi in L^1(mu_Fcirc phi)$ and $$ int f dmu_F = int fcirc phi dmu_Fcirc phi$$ Hint: It is enough to consider non-negative $f$ and to prove the inequality $int fcirc phi dmu_Fcirc phileq int fmu_F$.




There were many situation I have studied this kind of problem and I was thinking of using simple function and generalize it to arbitrary $L^1$ functions. And I think the method just works here too. But I can not understand the hint on this problem. Because I started from simple, the hint for non negative function seems superfluous but makes sense. But I don't know how to use the hint for inequality. I will be happy with any kind of hint or comment on it. Thank you in advance!







share|cite|improve this question














I got to have this problem in my hand.




Problem
Let $F: mathbbRrightarrow mathbbR$ be an increasing, right continuous function, and let $phi :mathbbRrightarrow mathbbR$ be a continuous increasing invertible function. Let $mu_F$ and $mu_Fcirc phi$ be the Lebesgue-Stieljes measure associated to $F$ and $Fcirc phi$ respectively. Show that if $fin L^1(mu_F)$, then $fcirc phi in L^1(mu_Fcirc phi)$ and $$ int f dmu_F = int fcirc phi dmu_Fcirc phi$$ Hint: It is enough to consider non-negative $f$ and to prove the inequality $int fcirc phi dmu_Fcirc phileq int fmu_F$.




There were many situation I have studied this kind of problem and I was thinking of using simple function and generalize it to arbitrary $L^1$ functions. And I think the method just works here too. But I can not understand the hint on this problem. Because I started from simple, the hint for non negative function seems superfluous but makes sense. But I don't know how to use the hint for inequality. I will be happy with any kind of hint or comment on it. Thank you in advance!









share|cite|improve this question













share|cite|improve this question




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edited Aug 16 at 11:46









Ethan Bolker

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asked Aug 16 at 2:44









Lev Ban

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  • 1




    If you prove the hint for positive functions, you show that $fcirc phi in L^1(mu_Fcirc phi)$, since you are taking absolute values in any case. The change of variables formula is, indeed, proven using simple functions.
    – Dosidis
    Aug 16 at 3:25











  • @Dosidis That make sense! Thank you! But I still don't know how to use the inequality....
    – Lev Ban
    Aug 16 at 18:11












  • 1




    If you prove the hint for positive functions, you show that $fcirc phi in L^1(mu_Fcirc phi)$, since you are taking absolute values in any case. The change of variables formula is, indeed, proven using simple functions.
    – Dosidis
    Aug 16 at 3:25











  • @Dosidis That make sense! Thank you! But I still don't know how to use the inequality....
    – Lev Ban
    Aug 16 at 18:11







1




1




If you prove the hint for positive functions, you show that $fcirc phi in L^1(mu_Fcirc phi)$, since you are taking absolute values in any case. The change of variables formula is, indeed, proven using simple functions.
– Dosidis
Aug 16 at 3:25





If you prove the hint for positive functions, you show that $fcirc phi in L^1(mu_Fcirc phi)$, since you are taking absolute values in any case. The change of variables formula is, indeed, proven using simple functions.
– Dosidis
Aug 16 at 3:25













@Dosidis That make sense! Thank you! But I still don't know how to use the inequality....
– Lev Ban
Aug 16 at 18:11




@Dosidis That make sense! Thank you! But I still don't know how to use the inequality....
– Lev Ban
Aug 16 at 18:11















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