mean(=expectation) value of mixed random varibale(=sum of geometric distribution and exponential distribution) [closed]

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I wonder how I can obtain the mean value of the sum of joint distribution which is geometric distribution with success probability $p$ and exponential distribution which has density $lambda$.







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closed as unclear what you're asking by Did, Xander Henderson, Taroccoesbrocco, Jose Arnaldo Bebita Dris, Shailesh Aug 21 at 11:27


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • Do you mean $mathbb E(X+Y)$ where $X$ has geometric and $Y$ has exponential distribution? If so then use linearity of expectation.
    – drhab
    Aug 16 at 8:24






  • 1




    Define mixed random variable. You can mix distributions in many ways.
    – Kavi Rama Murthy
    Aug 16 at 8:25










  • No i mean the mean of joint distribution
    – romtae
    Aug 16 at 9:09










  • Could you please provide the definition of what you need?
    – metamorphy
    Aug 16 at 10:47














up vote
-1
down vote

favorite












I wonder how I can obtain the mean value of the sum of joint distribution which is geometric distribution with success probability $p$ and exponential distribution which has density $lambda$.







share|cite|improve this question














closed as unclear what you're asking by Did, Xander Henderson, Taroccoesbrocco, Jose Arnaldo Bebita Dris, Shailesh Aug 21 at 11:27


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.














  • Do you mean $mathbb E(X+Y)$ where $X$ has geometric and $Y$ has exponential distribution? If so then use linearity of expectation.
    – drhab
    Aug 16 at 8:24






  • 1




    Define mixed random variable. You can mix distributions in many ways.
    – Kavi Rama Murthy
    Aug 16 at 8:25










  • No i mean the mean of joint distribution
    – romtae
    Aug 16 at 9:09










  • Could you please provide the definition of what you need?
    – metamorphy
    Aug 16 at 10:47












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I wonder how I can obtain the mean value of the sum of joint distribution which is geometric distribution with success probability $p$ and exponential distribution which has density $lambda$.







share|cite|improve this question














I wonder how I can obtain the mean value of the sum of joint distribution which is geometric distribution with success probability $p$ and exponential distribution which has density $lambda$.









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 16 at 9:10

























asked Aug 16 at 8:19









romtae

11




11




closed as unclear what you're asking by Did, Xander Henderson, Taroccoesbrocco, Jose Arnaldo Bebita Dris, Shailesh Aug 21 at 11:27


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






closed as unclear what you're asking by Did, Xander Henderson, Taroccoesbrocco, Jose Arnaldo Bebita Dris, Shailesh Aug 21 at 11:27


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.













  • Do you mean $mathbb E(X+Y)$ where $X$ has geometric and $Y$ has exponential distribution? If so then use linearity of expectation.
    – drhab
    Aug 16 at 8:24






  • 1




    Define mixed random variable. You can mix distributions in many ways.
    – Kavi Rama Murthy
    Aug 16 at 8:25










  • No i mean the mean of joint distribution
    – romtae
    Aug 16 at 9:09










  • Could you please provide the definition of what you need?
    – metamorphy
    Aug 16 at 10:47
















  • Do you mean $mathbb E(X+Y)$ where $X$ has geometric and $Y$ has exponential distribution? If so then use linearity of expectation.
    – drhab
    Aug 16 at 8:24






  • 1




    Define mixed random variable. You can mix distributions in many ways.
    – Kavi Rama Murthy
    Aug 16 at 8:25










  • No i mean the mean of joint distribution
    – romtae
    Aug 16 at 9:09










  • Could you please provide the definition of what you need?
    – metamorphy
    Aug 16 at 10:47















Do you mean $mathbb E(X+Y)$ where $X$ has geometric and $Y$ has exponential distribution? If so then use linearity of expectation.
– drhab
Aug 16 at 8:24




Do you mean $mathbb E(X+Y)$ where $X$ has geometric and $Y$ has exponential distribution? If so then use linearity of expectation.
– drhab
Aug 16 at 8:24




1




1




Define mixed random variable. You can mix distributions in many ways.
– Kavi Rama Murthy
Aug 16 at 8:25




Define mixed random variable. You can mix distributions in many ways.
– Kavi Rama Murthy
Aug 16 at 8:25












No i mean the mean of joint distribution
– romtae
Aug 16 at 9:09




No i mean the mean of joint distribution
– romtae
Aug 16 at 9:09












Could you please provide the definition of what you need?
– metamorphy
Aug 16 at 10:47




Could you please provide the definition of what you need?
– metamorphy
Aug 16 at 10:47















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