Visualizing complex functions $f: mathbbC rightarrow mathbbC$
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The graph of a complex function $f: mathbbC rightarrow mathbbC$ is a 3-dimensional object in a 4-dimensional space and thus hard to visualize, even when it's a smooth 3-dimensional surface.
A natural way to visualize it is by two graphs of two functions $r: mathbbR^2rightarrow mathbbR, i: mathbbR^2rightarrow mathbbR$ with $r(z) = textRe(f(z)), i(z) = textIm(f(z))$. These functions define - under appropriate circumstances - two 2-dimensional objects $colorredS^f_r$ and $colorgreenS^f_i$ in a 3-dimensional space and can be visualized in $mathbbR^3$, at least when they are smooth 2-dimensional surfaces.
In general these two surfaces may or may not
- intersect with each other at some points in $mathbbR^3$ giving a 1-dimensional object $colorblueC^f= colorredS^f_r cap colorgreenS^f_i$ which lives in $mathbbR^3$
- intersect with the plane $mathbbR^2$ giving two 1-dimensional objects $colorredC^f_r = colorredS^f_r cap mathbbR^2$ and $colorgreenC^f_i = colorgreenS^f_i cap mathbbR^2$ which live in $mathbbR^2$
These 1-dimensional objects can be straight lines (or sets of straight lines), circles (or sets of circles), arbitrary open or closed curves (or sets of those).
One thing is obvious: There are $z_0 in mathbbC$ with $f(z) = 0$ (i.e. $f$ has roots) iff $colorredC^f_r cap colorgreenC^f_i neq emptyset$. Knowing that each complex polynomial has roots (the fundamental theorem of algebra), we know that $colorredC^P_r cap colorgreenC^P_i neq emptyset$ for all polynomials $P$. (We know even more: $colorredC^P_r cap colorgreenC^P_i$ is a point set of size less or equal the degree of $P$.)
Example 1:
$P(z) = z^2 -1, r(x,y) = x^2 - y^2 - 1 , i(x,y) = 2xy$
$colorredC^P_r = x^2 - y^2 = 1 $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (1,0) vee z = (-1,0)$
Example 2:
$P(z) = z^2 + 1, r(x,y) = x^2 - y^2 + 1 , i(x,y) = 2xy$
$colorredC^P_r = (x,y) $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (0,1) vee z = (0,-1)$
What I'd like to know:
What can - beyond the fundamental theorem - be said about the shapes and the positions of $colorredC^P_r$ and
$colorgreenC^P_i$ for polynomials $P$ in general terms (depending
on the degree of $P$)? May (or even does) the fundamental theorem
result from the characterizations of $colorredC^P_r$ and
$colorgreenC^P_i$?
How may holomorphic functions (= analytic complex functions) be characterized in terms of $colorblueC^f, colorredC^f_r, colorgreenC^f_i$?
- Like this: "For a holomorphic function $f$ the set $colorblueC^f$ must be non-empty and such-and-such"?
- Like that: "When a curve $C$ is such-and-such there is a holomorphic function $f$ with $C = colorblueC^f$"?
- Might a
holomorphic function $f$ possibly be fixed by its $colorblueC^f$
alone or by the pair $(colorredC^f_r, colorgreenC^f_i)$?
For the learned mathematician the answers to these question may seem obvious ("How can you ask?"), for me they are not, sorry.
complex-analysis holomorphic-functions visualization
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up vote
1
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The graph of a complex function $f: mathbbC rightarrow mathbbC$ is a 3-dimensional object in a 4-dimensional space and thus hard to visualize, even when it's a smooth 3-dimensional surface.
A natural way to visualize it is by two graphs of two functions $r: mathbbR^2rightarrow mathbbR, i: mathbbR^2rightarrow mathbbR$ with $r(z) = textRe(f(z)), i(z) = textIm(f(z))$. These functions define - under appropriate circumstances - two 2-dimensional objects $colorredS^f_r$ and $colorgreenS^f_i$ in a 3-dimensional space and can be visualized in $mathbbR^3$, at least when they are smooth 2-dimensional surfaces.
In general these two surfaces may or may not
- intersect with each other at some points in $mathbbR^3$ giving a 1-dimensional object $colorblueC^f= colorredS^f_r cap colorgreenS^f_i$ which lives in $mathbbR^3$
- intersect with the plane $mathbbR^2$ giving two 1-dimensional objects $colorredC^f_r = colorredS^f_r cap mathbbR^2$ and $colorgreenC^f_i = colorgreenS^f_i cap mathbbR^2$ which live in $mathbbR^2$
These 1-dimensional objects can be straight lines (or sets of straight lines), circles (or sets of circles), arbitrary open or closed curves (or sets of those).
One thing is obvious: There are $z_0 in mathbbC$ with $f(z) = 0$ (i.e. $f$ has roots) iff $colorredC^f_r cap colorgreenC^f_i neq emptyset$. Knowing that each complex polynomial has roots (the fundamental theorem of algebra), we know that $colorredC^P_r cap colorgreenC^P_i neq emptyset$ for all polynomials $P$. (We know even more: $colorredC^P_r cap colorgreenC^P_i$ is a point set of size less or equal the degree of $P$.)
Example 1:
$P(z) = z^2 -1, r(x,y) = x^2 - y^2 - 1 , i(x,y) = 2xy$
$colorredC^P_r = x^2 - y^2 = 1 $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (1,0) vee z = (-1,0)$
Example 2:
$P(z) = z^2 + 1, r(x,y) = x^2 - y^2 + 1 , i(x,y) = 2xy$
$colorredC^P_r = (x,y) $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (0,1) vee z = (0,-1)$
What I'd like to know:
What can - beyond the fundamental theorem - be said about the shapes and the positions of $colorredC^P_r$ and
$colorgreenC^P_i$ for polynomials $P$ in general terms (depending
on the degree of $P$)? May (or even does) the fundamental theorem
result from the characterizations of $colorredC^P_r$ and
$colorgreenC^P_i$?
How may holomorphic functions (= analytic complex functions) be characterized in terms of $colorblueC^f, colorredC^f_r, colorgreenC^f_i$?
- Like this: "For a holomorphic function $f$ the set $colorblueC^f$ must be non-empty and such-and-such"?
- Like that: "When a curve $C$ is such-and-such there is a holomorphic function $f$ with $C = colorblueC^f$"?
- Might a
holomorphic function $f$ possibly be fixed by its $colorblueC^f$
alone or by the pair $(colorredC^f_r, colorgreenC^f_i)$?
For the learned mathematician the answers to these question may seem obvious ("How can you ask?"), for me they are not, sorry.
complex-analysis holomorphic-functions visualization
If I may ask, why not to visualize $f$ as a displacement of one object in the plane to another in the plane too?
â dmtri
Aug 22 at 10:20
1
That's another way of visualization that might be helpful, but what will we see? First of all: a dense set of arrows. So one may start with arrows starting from points $mathbbZ^2$. This may yield some geometrical patterns or symmetries already.
â Hans Stricker
Aug 22 at 10:24
2
Riemann's Surfaces may be relevant in visualising multidimensional complex functions. This video reference might help - youtube.com/playlist?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF
â paulplusx
Aug 22 at 10:24
1
The most common way that I have seen to visualize complex functions (at least on wikipedia) is to color the complex plane such that each point has a color corresponding to the function value at that point. See, for instance, the Gamma function or the Riemann Zeta function (these also have the contour plot of $|f(z)|$ drawn in).
â Arthur
Aug 22 at 10:24
But the colors are hard to interpret, aren't they? Is the color out of a two-dimensional color space? If so, how could we tell the real and the imaginary part of a "color"?
â Hans Stricker
Aug 22 at 10:26
 |Â
show 2 more comments
up vote
1
down vote
favorite
up vote
1
down vote
favorite
The graph of a complex function $f: mathbbC rightarrow mathbbC$ is a 3-dimensional object in a 4-dimensional space and thus hard to visualize, even when it's a smooth 3-dimensional surface.
A natural way to visualize it is by two graphs of two functions $r: mathbbR^2rightarrow mathbbR, i: mathbbR^2rightarrow mathbbR$ with $r(z) = textRe(f(z)), i(z) = textIm(f(z))$. These functions define - under appropriate circumstances - two 2-dimensional objects $colorredS^f_r$ and $colorgreenS^f_i$ in a 3-dimensional space and can be visualized in $mathbbR^3$, at least when they are smooth 2-dimensional surfaces.
In general these two surfaces may or may not
- intersect with each other at some points in $mathbbR^3$ giving a 1-dimensional object $colorblueC^f= colorredS^f_r cap colorgreenS^f_i$ which lives in $mathbbR^3$
- intersect with the plane $mathbbR^2$ giving two 1-dimensional objects $colorredC^f_r = colorredS^f_r cap mathbbR^2$ and $colorgreenC^f_i = colorgreenS^f_i cap mathbbR^2$ which live in $mathbbR^2$
These 1-dimensional objects can be straight lines (or sets of straight lines), circles (or sets of circles), arbitrary open or closed curves (or sets of those).
One thing is obvious: There are $z_0 in mathbbC$ with $f(z) = 0$ (i.e. $f$ has roots) iff $colorredC^f_r cap colorgreenC^f_i neq emptyset$. Knowing that each complex polynomial has roots (the fundamental theorem of algebra), we know that $colorredC^P_r cap colorgreenC^P_i neq emptyset$ for all polynomials $P$. (We know even more: $colorredC^P_r cap colorgreenC^P_i$ is a point set of size less or equal the degree of $P$.)
Example 1:
$P(z) = z^2 -1, r(x,y) = x^2 - y^2 - 1 , i(x,y) = 2xy$
$colorredC^P_r = x^2 - y^2 = 1 $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (1,0) vee z = (-1,0)$
Example 2:
$P(z) = z^2 + 1, r(x,y) = x^2 - y^2 + 1 , i(x,y) = 2xy$
$colorredC^P_r = (x,y) $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (0,1) vee z = (0,-1)$
What I'd like to know:
What can - beyond the fundamental theorem - be said about the shapes and the positions of $colorredC^P_r$ and
$colorgreenC^P_i$ for polynomials $P$ in general terms (depending
on the degree of $P$)? May (or even does) the fundamental theorem
result from the characterizations of $colorredC^P_r$ and
$colorgreenC^P_i$?
How may holomorphic functions (= analytic complex functions) be characterized in terms of $colorblueC^f, colorredC^f_r, colorgreenC^f_i$?
- Like this: "For a holomorphic function $f$ the set $colorblueC^f$ must be non-empty and such-and-such"?
- Like that: "When a curve $C$ is such-and-such there is a holomorphic function $f$ with $C = colorblueC^f$"?
- Might a
holomorphic function $f$ possibly be fixed by its $colorblueC^f$
alone or by the pair $(colorredC^f_r, colorgreenC^f_i)$?
For the learned mathematician the answers to these question may seem obvious ("How can you ask?"), for me they are not, sorry.
complex-analysis holomorphic-functions visualization
The graph of a complex function $f: mathbbC rightarrow mathbbC$ is a 3-dimensional object in a 4-dimensional space and thus hard to visualize, even when it's a smooth 3-dimensional surface.
A natural way to visualize it is by two graphs of two functions $r: mathbbR^2rightarrow mathbbR, i: mathbbR^2rightarrow mathbbR$ with $r(z) = textRe(f(z)), i(z) = textIm(f(z))$. These functions define - under appropriate circumstances - two 2-dimensional objects $colorredS^f_r$ and $colorgreenS^f_i$ in a 3-dimensional space and can be visualized in $mathbbR^3$, at least when they are smooth 2-dimensional surfaces.
In general these two surfaces may or may not
- intersect with each other at some points in $mathbbR^3$ giving a 1-dimensional object $colorblueC^f= colorredS^f_r cap colorgreenS^f_i$ which lives in $mathbbR^3$
- intersect with the plane $mathbbR^2$ giving two 1-dimensional objects $colorredC^f_r = colorredS^f_r cap mathbbR^2$ and $colorgreenC^f_i = colorgreenS^f_i cap mathbbR^2$ which live in $mathbbR^2$
These 1-dimensional objects can be straight lines (or sets of straight lines), circles (or sets of circles), arbitrary open or closed curves (or sets of those).
One thing is obvious: There are $z_0 in mathbbC$ with $f(z) = 0$ (i.e. $f$ has roots) iff $colorredC^f_r cap colorgreenC^f_i neq emptyset$. Knowing that each complex polynomial has roots (the fundamental theorem of algebra), we know that $colorredC^P_r cap colorgreenC^P_i neq emptyset$ for all polynomials $P$. (We know even more: $colorredC^P_r cap colorgreenC^P_i$ is a point set of size less or equal the degree of $P$.)
Example 1:
$P(z) = z^2 -1, r(x,y) = x^2 - y^2 - 1 , i(x,y) = 2xy$
$colorredC^P_r = x^2 - y^2 = 1 $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (1,0) vee z = (-1,0)$
Example 2:
$P(z) = z^2 + 1, r(x,y) = x^2 - y^2 + 1 , i(x,y) = 2xy$
$colorredC^P_r = (x,y) $, $colorgreenC^P_i = x = 0 vee y = 0 $
$P(z) = 0 leftrightarrow z = (0,1) vee z = (0,-1)$
What I'd like to know:
What can - beyond the fundamental theorem - be said about the shapes and the positions of $colorredC^P_r$ and
$colorgreenC^P_i$ for polynomials $P$ in general terms (depending
on the degree of $P$)? May (or even does) the fundamental theorem
result from the characterizations of $colorredC^P_r$ and
$colorgreenC^P_i$?
How may holomorphic functions (= analytic complex functions) be characterized in terms of $colorblueC^f, colorredC^f_r, colorgreenC^f_i$?
- Like this: "For a holomorphic function $f$ the set $colorblueC^f$ must be non-empty and such-and-such"?
- Like that: "When a curve $C$ is such-and-such there is a holomorphic function $f$ with $C = colorblueC^f$"?
- Might a
holomorphic function $f$ possibly be fixed by its $colorblueC^f$
alone or by the pair $(colorredC^f_r, colorgreenC^f_i)$?
For the learned mathematician the answers to these question may seem obvious ("How can you ask?"), for me they are not, sorry.
complex-analysis holomorphic-functions visualization
edited Aug 22 at 15:57
asked Aug 22 at 10:06
Hans Stricker
4,35513574
4,35513574
If I may ask, why not to visualize $f$ as a displacement of one object in the plane to another in the plane too?
â dmtri
Aug 22 at 10:20
1
That's another way of visualization that might be helpful, but what will we see? First of all: a dense set of arrows. So one may start with arrows starting from points $mathbbZ^2$. This may yield some geometrical patterns or symmetries already.
â Hans Stricker
Aug 22 at 10:24
2
Riemann's Surfaces may be relevant in visualising multidimensional complex functions. This video reference might help - youtube.com/playlist?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF
â paulplusx
Aug 22 at 10:24
1
The most common way that I have seen to visualize complex functions (at least on wikipedia) is to color the complex plane such that each point has a color corresponding to the function value at that point. See, for instance, the Gamma function or the Riemann Zeta function (these also have the contour plot of $|f(z)|$ drawn in).
â Arthur
Aug 22 at 10:24
But the colors are hard to interpret, aren't they? Is the color out of a two-dimensional color space? If so, how could we tell the real and the imaginary part of a "color"?
â Hans Stricker
Aug 22 at 10:26
 |Â
show 2 more comments
If I may ask, why not to visualize $f$ as a displacement of one object in the plane to another in the plane too?
â dmtri
Aug 22 at 10:20
1
That's another way of visualization that might be helpful, but what will we see? First of all: a dense set of arrows. So one may start with arrows starting from points $mathbbZ^2$. This may yield some geometrical patterns or symmetries already.
â Hans Stricker
Aug 22 at 10:24
2
Riemann's Surfaces may be relevant in visualising multidimensional complex functions. This video reference might help - youtube.com/playlist?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF
â paulplusx
Aug 22 at 10:24
1
The most common way that I have seen to visualize complex functions (at least on wikipedia) is to color the complex plane such that each point has a color corresponding to the function value at that point. See, for instance, the Gamma function or the Riemann Zeta function (these also have the contour plot of $|f(z)|$ drawn in).
â Arthur
Aug 22 at 10:24
But the colors are hard to interpret, aren't they? Is the color out of a two-dimensional color space? If so, how could we tell the real and the imaginary part of a "color"?
â Hans Stricker
Aug 22 at 10:26
If I may ask, why not to visualize $f$ as a displacement of one object in the plane to another in the plane too?
â dmtri
Aug 22 at 10:20
If I may ask, why not to visualize $f$ as a displacement of one object in the plane to another in the plane too?
â dmtri
Aug 22 at 10:20
1
1
That's another way of visualization that might be helpful, but what will we see? First of all: a dense set of arrows. So one may start with arrows starting from points $mathbbZ^2$. This may yield some geometrical patterns or symmetries already.
â Hans Stricker
Aug 22 at 10:24
That's another way of visualization that might be helpful, but what will we see? First of all: a dense set of arrows. So one may start with arrows starting from points $mathbbZ^2$. This may yield some geometrical patterns or symmetries already.
â Hans Stricker
Aug 22 at 10:24
2
2
Riemann's Surfaces may be relevant in visualising multidimensional complex functions. This video reference might help - youtube.com/playlist?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF
â paulplusx
Aug 22 at 10:24
Riemann's Surfaces may be relevant in visualising multidimensional complex functions. This video reference might help - youtube.com/playlist?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF
â paulplusx
Aug 22 at 10:24
1
1
The most common way that I have seen to visualize complex functions (at least on wikipedia) is to color the complex plane such that each point has a color corresponding to the function value at that point. See, for instance, the Gamma function or the Riemann Zeta function (these also have the contour plot of $|f(z)|$ drawn in).
â Arthur
Aug 22 at 10:24
The most common way that I have seen to visualize complex functions (at least on wikipedia) is to color the complex plane such that each point has a color corresponding to the function value at that point. See, for instance, the Gamma function or the Riemann Zeta function (these also have the contour plot of $|f(z)|$ drawn in).
â Arthur
Aug 22 at 10:24
But the colors are hard to interpret, aren't they? Is the color out of a two-dimensional color space? If so, how could we tell the real and the imaginary part of a "color"?
â Hans Stricker
Aug 22 at 10:26
But the colors are hard to interpret, aren't they? Is the color out of a two-dimensional color space? If so, how could we tell the real and the imaginary part of a "color"?
â Hans Stricker
Aug 22 at 10:26
 |Â
show 2 more comments
1 Answer
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Riemann's Surfaces may be relevant in visualizing multi-dimensional (complex) functions. There is an excellent video series by welch labs in their playlist of Imaginary Numbers are Real.
Even though they start with the history and visualization of Complex functions, they move on to show 4-D Complex functions on 3-D Plane (not exactly the function, more like it's shadow) quite beautifully with computer animations. Take a look at it, it might help.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Riemann's Surfaces may be relevant in visualizing multi-dimensional (complex) functions. There is an excellent video series by welch labs in their playlist of Imaginary Numbers are Real.
Even though they start with the history and visualization of Complex functions, they move on to show 4-D Complex functions on 3-D Plane (not exactly the function, more like it's shadow) quite beautifully with computer animations. Take a look at it, it might help.
add a comment |Â
up vote
1
down vote
Riemann's Surfaces may be relevant in visualizing multi-dimensional (complex) functions. There is an excellent video series by welch labs in their playlist of Imaginary Numbers are Real.
Even though they start with the history and visualization of Complex functions, they move on to show 4-D Complex functions on 3-D Plane (not exactly the function, more like it's shadow) quite beautifully with computer animations. Take a look at it, it might help.
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Riemann's Surfaces may be relevant in visualizing multi-dimensional (complex) functions. There is an excellent video series by welch labs in their playlist of Imaginary Numbers are Real.
Even though they start with the history and visualization of Complex functions, they move on to show 4-D Complex functions on 3-D Plane (not exactly the function, more like it's shadow) quite beautifully with computer animations. Take a look at it, it might help.
Riemann's Surfaces may be relevant in visualizing multi-dimensional (complex) functions. There is an excellent video series by welch labs in their playlist of Imaginary Numbers are Real.
Even though they start with the history and visualization of Complex functions, they move on to show 4-D Complex functions on 3-D Plane (not exactly the function, more like it's shadow) quite beautifully with computer animations. Take a look at it, it might help.
edited Aug 22 at 15:01
answered Aug 22 at 10:43
paulplusx
18013
18013
add a comment |Â
add a comment |Â
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If I may ask, why not to visualize $f$ as a displacement of one object in the plane to another in the plane too?
â dmtri
Aug 22 at 10:20
1
That's another way of visualization that might be helpful, but what will we see? First of all: a dense set of arrows. So one may start with arrows starting from points $mathbbZ^2$. This may yield some geometrical patterns or symmetries already.
â Hans Stricker
Aug 22 at 10:24
2
Riemann's Surfaces may be relevant in visualising multidimensional complex functions. This video reference might help - youtube.com/playlist?list=PLiaHhY2iBX9g6KIvZ_703G3KJXapKkNaF
â paulplusx
Aug 22 at 10:24
1
The most common way that I have seen to visualize complex functions (at least on wikipedia) is to color the complex plane such that each point has a color corresponding to the function value at that point. See, for instance, the Gamma function or the Riemann Zeta function (these also have the contour plot of $|f(z)|$ drawn in).
â Arthur
Aug 22 at 10:24
But the colors are hard to interpret, aren't they? Is the color out of a two-dimensional color space? If so, how could we tell the real and the imaginary part of a "color"?
â Hans Stricker
Aug 22 at 10:26