How would I go about answering this question about functions?
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Hey so I have this exercise and I don't know how to tackle it or present my answer;
For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.
Determine the function $g circ f : A to C$.
Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.
Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?
functions discrete-mathematics
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Hey so I have this exercise and I don't know how to tackle it or present my answer;
For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.
Determine the function $g circ f : A to C$.
Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.
Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?
functions discrete-mathematics
Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
â Bill Wallis
Aug 22 at 8:09
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Hey so I have this exercise and I don't know how to tackle it or present my answer;
For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.
Determine the function $g circ f : A to C$.
Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.
Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?
functions discrete-mathematics
Hey so I have this exercise and I don't know how to tackle it or present my answer;
For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.
Determine the function $g circ f : A to C$.
Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.
Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?
functions discrete-mathematics
edited Aug 22 at 9:00
Arnaud D.
14.8k52141
14.8k52141
asked Aug 22 at 8:06
ValentineJ
51
51
Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
â Bill Wallis
Aug 22 at 8:09
add a comment |Â
Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
â Bill Wallis
Aug 22 at 8:09
Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
â Bill Wallis
Aug 22 at 8:09
Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
â Bill Wallis
Aug 22 at 8:09
add a comment |Â
2 Answers
2
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oldest
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2
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Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$
with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule
$$(gcirc f)(1) = g(f(1))$$
and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
add a comment |Â
up vote
0
down vote
Take some element of $A$, for instance $1$.
Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.
Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.
This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.
This can be rephrased by saying that $(1,1)in gcirc f$.
Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
Yes, that is correct.
â drhab
Aug 22 at 8:25
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$
with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule
$$(gcirc f)(1) = g(f(1))$$
and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
add a comment |Â
up vote
2
down vote
accepted
Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$
with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule
$$(gcirc f)(1) = g(f(1))$$
and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
add a comment |Â
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$
with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule
$$(gcirc f)(1) = g(f(1))$$
and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.
Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$
with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule
$$(gcirc f)(1) = g(f(1))$$
and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.
answered Aug 22 at 8:10
5xum
82.5k383147
82.5k383147
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
add a comment |Â
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:21
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
@ValentineJ That's exactly it!
â 5xum
Aug 22 at 8:30
add a comment |Â
up vote
0
down vote
Take some element of $A$, for instance $1$.
Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.
Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.
This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.
This can be rephrased by saying that $(1,1)in gcirc f$.
Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
Yes, that is correct.
â drhab
Aug 22 at 8:25
add a comment |Â
up vote
0
down vote
Take some element of $A$, for instance $1$.
Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.
Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.
This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.
This can be rephrased by saying that $(1,1)in gcirc f$.
Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
Yes, that is correct.
â drhab
Aug 22 at 8:25
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Take some element of $A$, for instance $1$.
Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.
Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.
This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.
This can be rephrased by saying that $(1,1)in gcirc f$.
Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$
Take some element of $A$, for instance $1$.
Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.
Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.
This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.
This can be rephrased by saying that $(1,1)in gcirc f$.
Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$
answered Aug 22 at 8:15
drhab
88k541120
88k541120
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
Yes, that is correct.
â drhab
Aug 22 at 8:25
add a comment |Â
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
Yes, that is correct.
â drhab
Aug 22 at 8:25
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
So my final answer would be; gâÂÂf=(1,1),(2,3),(3,2),(4,1). Is that correct?
â ValentineJ
Aug 22 at 8:23
Yes, that is correct.
â drhab
Aug 22 at 8:25
Yes, that is correct.
â drhab
Aug 22 at 8:25
add a comment |Â
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Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
â Bill Wallis
Aug 22 at 8:09