How would I go about answering this question about functions?

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Hey so I have this exercise and I don't know how to tackle it or present my answer;



For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.



Determine the function $g circ f : A to C$.



Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.



Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?







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  • Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
    – Bill Wallis
    Aug 22 at 8:09














up vote
0
down vote

favorite












Hey so I have this exercise and I don't know how to tackle it or present my answer;



For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.



Determine the function $g circ f : A to C$.



Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.



Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?







share|cite|improve this question






















  • Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
    – Bill Wallis
    Aug 22 at 8:09












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Hey so I have this exercise and I don't know how to tackle it or present my answer;



For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.



Determine the function $g circ f : A to C$.



Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.



Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?







share|cite|improve this question














Hey so I have this exercise and I don't know how to tackle it or present my answer;



For $A : = 1, 2, 3, 4$, $B := a, b, c, d$ and $C := 1, 2, 3$, let $f : A to B$ be the function $(1, a),(2, c),(3, b),(4, d)$, and let $g : B to C$ be the function $(a, 1),(b, 2),(c, 3),(d, 1)$.



Determine the function $g circ f : A to C$.



Can anyone give me some guidance? Please. I haven't really started it yet, because I don't know where.



Would it just be y $(g circ f)(x) = g(f(x))$ or do I have to write out the sets?









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edited Aug 22 at 9:00









Arnaud D.

14.8k52141




14.8k52141










asked Aug 22 at 8:06









ValentineJ

51




51











  • Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
    – Bill Wallis
    Aug 22 at 8:09
















  • Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
    – Bill Wallis
    Aug 22 at 8:09















Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
– Bill Wallis
Aug 22 at 8:09




Write out the sets. For example, you have $1 mapsto a$ by $f$, and then $a mapsto 1$ by $g$, so that $1 mapsto 1$ by the composition. Note that $(gcirc f)(x) = f(g(x))$.
– Bill Wallis
Aug 22 at 8:09










2 Answers
2






active

oldest

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up vote
2
down vote



accepted










Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$



with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule



$$(gcirc f)(1) = g(f(1))$$



and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.






share|cite|improve this answer




















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:21










  • @ValentineJ That's exactly it!
    – 5xum
    Aug 22 at 8:30

















up vote
0
down vote













Take some element of $A$, for instance $1$.



Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.



Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.



This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.



This can be rephrased by saying that $(1,1)in gcirc f$.



Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$






share|cite|improve this answer




















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:23










  • Yes, that is correct.
    – drhab
    Aug 22 at 8:25










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$



with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule



$$(gcirc f)(1) = g(f(1))$$



and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.






share|cite|improve this answer




















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:21










  • @ValentineJ That's exactly it!
    – 5xum
    Aug 22 at 8:30














up vote
2
down vote



accepted










Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$



with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule



$$(gcirc f)(1) = g(f(1))$$



and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.






share|cite|improve this answer




















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:21










  • @ValentineJ That's exactly it!
    – 5xum
    Aug 22 at 8:30












up vote
2
down vote



accepted







up vote
2
down vote



accepted






Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$



with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule



$$(gcirc f)(1) = g(f(1))$$



and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.






share|cite|improve this answer












Given that the task is quite basic, I believe you should write out the sets. That is, you should write out the function $gcirc f$ as $$gcirc f = (1, *), (2, *), (3, *), (4, *)$$



with appropriate values in place of the asterisks. To calculate what value should be put next to $1$, for example, you can use the rule



$$(gcirc f)(1) = g(f(1))$$



and first calculate $f(1)$, then calculate $g(*)$, where you put whatever $f(1)$ is in place of the asterisk.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Aug 22 at 8:10









5xum

82.5k383147




82.5k383147











  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:21










  • @ValentineJ That's exactly it!
    – 5xum
    Aug 22 at 8:30
















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:21










  • @ValentineJ That's exactly it!
    – 5xum
    Aug 22 at 8:30















So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
– ValentineJ
Aug 22 at 8:21




So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
– ValentineJ
Aug 22 at 8:21












@ValentineJ That's exactly it!
– 5xum
Aug 22 at 8:30




@ValentineJ That's exactly it!
– 5xum
Aug 22 at 8:30










up vote
0
down vote













Take some element of $A$, for instance $1$.



Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.



Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.



This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.



This can be rephrased by saying that $(1,1)in gcirc f$.



Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$






share|cite|improve this answer




















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:23










  • Yes, that is correct.
    – drhab
    Aug 22 at 8:25














up vote
0
down vote













Take some element of $A$, for instance $1$.



Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.



Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.



This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.



This can be rephrased by saying that $(1,1)in gcirc f$.



Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$






share|cite|improve this answer




















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:23










  • Yes, that is correct.
    – drhab
    Aug 22 at 8:25












up vote
0
down vote










up vote
0
down vote









Take some element of $A$, for instance $1$.



Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.



Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.



This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.



This can be rephrased by saying that $(1,1)in gcirc f$.



Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$






share|cite|improve this answer












Take some element of $A$, for instance $1$.



Observe that $f$ sends this element to $ain B$ because $(1,a)in f$.



Now observe that $g$ on its turn sends $a$ to element $1in C$ because $(a,1)in g$.



This means that $gcirc f$ will send the original element $1in A$ to element $1in C$.



This can be rephrased by saying that $(1,1)in gcirc f$.



Now do the same for the other elements of $A$ and you will end up with something like $$gcirc f=(1,1),(2,cdot),(3,cdot),(4,cdot)$$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Aug 22 at 8:15









drhab

88k541120




88k541120











  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:23










  • Yes, that is correct.
    – drhab
    Aug 22 at 8:25
















  • So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
    – ValentineJ
    Aug 22 at 8:23










  • Yes, that is correct.
    – drhab
    Aug 22 at 8:25















So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
– ValentineJ
Aug 22 at 8:23




So my final answer would be; g∘f=(1,1),(2,3),(3,2),(4,1). Is that correct?
– ValentineJ
Aug 22 at 8:23












Yes, that is correct.
– drhab
Aug 22 at 8:25




Yes, that is correct.
– drhab
Aug 22 at 8:25












 

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