getting mean curvature with normal vector mapN(x,y,3)
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To be honest, it is a question for computer vision.
There is a normal vector map N(x,y,3) represents the normal vector(nx,ny,nz) on the point P(x,y). If the resolution is high enough(2448x2048), can we get the approximate mean curvature by this normal vector map?
I found a proof about the relationship between normal vector and curvature,
it says div(N)=K1+K2
http://willson.cm.utexas.edu/Research/Sub_Files/Surface_Phenomena/Spring%202000/surface_normal_proof.pdf
it is easy to get the part of x and y, but not z since there is no z coordinate.
surfaces curvature mean-curvature-flows
add a comment |Â
up vote
0
down vote
favorite
To be honest, it is a question for computer vision.
There is a normal vector map N(x,y,3) represents the normal vector(nx,ny,nz) on the point P(x,y). If the resolution is high enough(2448x2048), can we get the approximate mean curvature by this normal vector map?
I found a proof about the relationship between normal vector and curvature,
it says div(N)=K1+K2
http://willson.cm.utexas.edu/Research/Sub_Files/Surface_Phenomena/Spring%202000/surface_normal_proof.pdf
it is easy to get the part of x and y, but not z since there is no z coordinate.
surfaces curvature mean-curvature-flows
Is this a question about mathematics?
â Taroccoesbrocco
Aug 22 at 6:10
ya,it is about how to get the mean curvature
â å®Âå²³ç©Â
Aug 22 at 6:56
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
To be honest, it is a question for computer vision.
There is a normal vector map N(x,y,3) represents the normal vector(nx,ny,nz) on the point P(x,y). If the resolution is high enough(2448x2048), can we get the approximate mean curvature by this normal vector map?
I found a proof about the relationship between normal vector and curvature,
it says div(N)=K1+K2
http://willson.cm.utexas.edu/Research/Sub_Files/Surface_Phenomena/Spring%202000/surface_normal_proof.pdf
it is easy to get the part of x and y, but not z since there is no z coordinate.
surfaces curvature mean-curvature-flows
To be honest, it is a question for computer vision.
There is a normal vector map N(x,y,3) represents the normal vector(nx,ny,nz) on the point P(x,y). If the resolution is high enough(2448x2048), can we get the approximate mean curvature by this normal vector map?
I found a proof about the relationship between normal vector and curvature,
it says div(N)=K1+K2
http://willson.cm.utexas.edu/Research/Sub_Files/Surface_Phenomena/Spring%202000/surface_normal_proof.pdf
it is easy to get the part of x and y, but not z since there is no z coordinate.
surfaces curvature mean-curvature-flows
asked Aug 22 at 5:36
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1
Is this a question about mathematics?
â Taroccoesbrocco
Aug 22 at 6:10
ya,it is about how to get the mean curvature
â å®Âå²³ç©Â
Aug 22 at 6:56
add a comment |Â
Is this a question about mathematics?
â Taroccoesbrocco
Aug 22 at 6:10
ya,it is about how to get the mean curvature
â å®Âå²³ç©Â
Aug 22 at 6:56
Is this a question about mathematics?
â Taroccoesbrocco
Aug 22 at 6:10
Is this a question about mathematics?
â Taroccoesbrocco
Aug 22 at 6:10
ya,it is about how to get the mean curvature
â å®Âå²³ç©Â
Aug 22 at 6:56
ya,it is about how to get the mean curvature
â å®Âå²³ç©Â
Aug 22 at 6:56
add a comment |Â
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Is this a question about mathematics?
â Taroccoesbrocco
Aug 22 at 6:10
ya,it is about how to get the mean curvature
â å®Âå²³ç©Â
Aug 22 at 6:56