If $|c|>2$ and $z_n=z_n-1^2+c$ with $z_0=0$ then $z_n rightarrow infty$

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite
1












Let $c in mathbbC$ and $f(z)=z^2+c$. Then define a sequence: $z_0=0$, $z_n=f(z_n-1)$ for all $n in mathbbN$. Show that $|c|>2 Rightarrow z_n rightarrow infty$. I had no clue which theorem I could use in this case in order to show this. I'd be thankful for any advice.







share|cite|improve this question






















  • (Terrible title.) No need for a "theorem" here, just find a lower bound for $|z_n|$ in terms of $|z_n-1|$ and iterate.
    – Did
    Aug 22 at 11:26






  • 2




    Please refer to "escape criterion" here.
    – Ng Chung Tak
    Aug 22 at 18:25















up vote
1
down vote

favorite
1












Let $c in mathbbC$ and $f(z)=z^2+c$. Then define a sequence: $z_0=0$, $z_n=f(z_n-1)$ for all $n in mathbbN$. Show that $|c|>2 Rightarrow z_n rightarrow infty$. I had no clue which theorem I could use in this case in order to show this. I'd be thankful for any advice.







share|cite|improve this question






















  • (Terrible title.) No need for a "theorem" here, just find a lower bound for $|z_n|$ in terms of $|z_n-1|$ and iterate.
    – Did
    Aug 22 at 11:26






  • 2




    Please refer to "escape criterion" here.
    – Ng Chung Tak
    Aug 22 at 18:25













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





Let $c in mathbbC$ and $f(z)=z^2+c$. Then define a sequence: $z_0=0$, $z_n=f(z_n-1)$ for all $n in mathbbN$. Show that $|c|>2 Rightarrow z_n rightarrow infty$. I had no clue which theorem I could use in this case in order to show this. I'd be thankful for any advice.







share|cite|improve this question














Let $c in mathbbC$ and $f(z)=z^2+c$. Then define a sequence: $z_0=0$, $z_n=f(z_n-1)$ for all $n in mathbbN$. Show that $|c|>2 Rightarrow z_n rightarrow infty$. I had no clue which theorem I could use in this case in order to show this. I'd be thankful for any advice.









share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Aug 22 at 11:26









Did

243k23208443




243k23208443










asked Aug 22 at 11:23









Thesinus

22629




22629











  • (Terrible title.) No need for a "theorem" here, just find a lower bound for $|z_n|$ in terms of $|z_n-1|$ and iterate.
    – Did
    Aug 22 at 11:26






  • 2




    Please refer to "escape criterion" here.
    – Ng Chung Tak
    Aug 22 at 18:25

















  • (Terrible title.) No need for a "theorem" here, just find a lower bound for $|z_n|$ in terms of $|z_n-1|$ and iterate.
    – Did
    Aug 22 at 11:26






  • 2




    Please refer to "escape criterion" here.
    – Ng Chung Tak
    Aug 22 at 18:25
















(Terrible title.) No need for a "theorem" here, just find a lower bound for $|z_n|$ in terms of $|z_n-1|$ and iterate.
– Did
Aug 22 at 11:26




(Terrible title.) No need for a "theorem" here, just find a lower bound for $|z_n|$ in terms of $|z_n-1|$ and iterate.
– Did
Aug 22 at 11:26




2




2




Please refer to "escape criterion" here.
– Ng Chung Tak
Aug 22 at 18:25





Please refer to "escape criterion" here.
– Ng Chung Tak
Aug 22 at 18:25
















active

oldest

votes











Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2890931%2fif-c2-and-z-n-z-n-12c-with-z-0-0-then-z-n-rightarrow-infty%23new-answer', 'question_page');

);

Post as a guest



































active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes










 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2890931%2fif-c2-and-z-n-z-n-12c-with-z-0-0-then-z-n-rightarrow-infty%23new-answer', 'question_page');

);

Post as a guest













































































這個網誌中的熱門文章

How to combine Bézier curves to a surface?

Mutual Information Always Non-negative

Why am i infinitely getting the same tweet with the Twitter Search API?