How can we find the intersection points?
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We have the functions $f(x)=2sqrtx+3$ and $g(x)=-0.5(x-1)^3+2$. I want to calculate the area between the graphs of the two functions above. For that we have to calculate the intersection points of the functions, but how can we find them in this case where we have a root and a cubic power? Could you give me a hint?
calculus integration area
asked Aug 22 at 8:54
Mary Star
2,77682056
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We have the functions $f(x)=2sqrtx+3$ and $g(x)=-0.5(x-1)^3+2$. I want to calculate the area between the graphs of the two functions above. For that we have to calculate the intersection points of the functions, but how can we find them in this case where we have a root and a cubic power? Could you give me a hint?
calculus integration area
asked Aug 22 at 8:54
Mary Star
2,77682056
Wolfram alpha gives only one real intersection.
– Sobi
Aug 22 at 9:10
I find no intersections.
– stretch
Aug 22 at 9:40
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
We have the functions $f(x)=2sqrtx+3$ and $g(x)=-0.5(x-1)^3+2$. I want to calculate the area between the graphs of the two functions above. For that we have to calculate the intersection points of the functions, but how can we find them in this case where we have a root and a cubic power? Could you give me a hint?
calculus integration area
asked Aug 22 at 8:54
Mary Star
2,77682056
We have the functions $f(x)=2sqrtx+3$ and $g(x)=-0.5(x-1)^3+2$. I want to calculate the area between the graphs of the two functions above. For that we have to calculate the intersection points of the functions, but how can we find them in this case where we have a root and a cubic power? Could you give me a hint?
calculus integration area
asked Aug 22 at 8:54
Mary Star
2,77682056
asked Aug 22 at 8:54
Mary Star
2,77682056
asked Aug 22 at 8:54
Mary Star
2,77682056
asked Aug 22 at 8:54
Mary Star
2,77682056
2,77682056
Wolfram alpha gives only one real intersection.
– Sobi
Aug 22 at 9:10
I find no intersections.
– stretch
Aug 22 at 9:40
add a comment |Â
Wolfram alpha gives only one real intersection.
– Sobi
Aug 22 at 9:10
I find no intersections.
– stretch
Aug 22 at 9:40
Wolfram alpha gives only one real intersection.
– Sobi
Aug 22 at 9:10
Wolfram alpha gives only one real intersection.
– Sobi
Aug 22 at 9:10
I find no intersections.
– stretch
Aug 22 at 9:40
I find no intersections.
– stretch
Aug 22 at 9:40
add a comment |Â
2 Answers
2
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If you draw a graph of each function you will see there is just one intersection, around $x=-0.36$. I wonder if you don't actually mean a function $f(x)$ for if you mean the graph $y^2=4(x+3)$ you would have an area to calculate.
answered Aug 22 at 10:05
Bruce
525113
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1.Plot the two functions using graphic calculator
2.Find the intersection the functions around x = -.358
3.Find the x intersects for the 2 functions respectively in this case , for f(x) is x = -3 and g(x) is x = 2.587.
4.Integrate the functions, for f(x) ,range from x = -3 to -.358 (remember to modules) it because it is in the negative x range, for g(x) , range from x = -.358 to 0(remember to modules) and g(x) from x = 0 to 2.587.
5.Finally add them together to get answer.
answered Aug 22 at 11:42
Tensor Flow
11
1
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
If you draw a graph of each function you will see there is just one intersection, around $x=-0.36$. I wonder if you don't actually mean a function $f(x)$ for if you mean the graph $y^2=4(x+3)$ you would have an area to calculate.
answered Aug 22 at 10:05
Bruce
525113
add a comment |Â
up vote
0
down vote
If you draw a graph of each function you will see there is just one intersection, around $x=-0.36$. I wonder if you don't actually mean a function $f(x)$ for if you mean the graph $y^2=4(x+3)$ you would have an area to calculate.
answered Aug 22 at 10:05
Bruce
525113
add a comment |Â
up vote
0
down vote
up vote
0
down vote
If you draw a graph of each function you will see there is just one intersection, around $x=-0.36$. I wonder if you don't actually mean a function $f(x)$ for if you mean the graph $y^2=4(x+3)$ you would have an area to calculate.
answered Aug 22 at 10:05
Bruce
525113
If you draw a graph of each function you will see there is just one intersection, around $x=-0.36$. I wonder if you don't actually mean a function $f(x)$ for if you mean the graph $y^2=4(x+3)$ you would have an area to calculate.
answered Aug 22 at 10:05
Bruce
525113
edited Aug 22 at 11:01
answered Aug 22 at 10:05
Bruce
525113
answered Aug 22 at 10:05
Bruce
525113
answered Aug 22 at 10:05
Bruce
525113
525113
add a comment |Â
add a comment |Â
up vote
0
down vote
1.Plot the two functions using graphic calculator
2.Find the intersection the functions around x = -.358
3.Find the x intersects for the 2 functions respectively in this case , for f(x) is x = -3 and g(x) is x = 2.587.
4.Integrate the functions, for f(x) ,range from x = -3 to -.358 (remember to modules) it because it is in the negative x range, for g(x) , range from x = -.358 to 0(remember to modules) and g(x) from x = 0 to 2.587.
5.Finally add them together to get answer.
answered Aug 22 at 11:42
Tensor Flow
11
1
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
add a comment |Â
up vote
0
down vote
1.Plot the two functions using graphic calculator
2.Find the intersection the functions around x = -.358
3.Find the x intersects for the 2 functions respectively in this case , for f(x) is x = -3 and g(x) is x = 2.587.
4.Integrate the functions, for f(x) ,range from x = -3 to -.358 (remember to modules) it because it is in the negative x range, for g(x) , range from x = -.358 to 0(remember to modules) and g(x) from x = 0 to 2.587.
5.Finally add them together to get answer.
answered Aug 22 at 11:42
Tensor Flow
11
1
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
add a comment |Â
up vote
0
down vote
up vote
0
down vote
1.Plot the two functions using graphic calculator
2.Find the intersection the functions around x = -.358
3.Find the x intersects for the 2 functions respectively in this case , for f(x) is x = -3 and g(x) is x = 2.587.
4.Integrate the functions, for f(x) ,range from x = -3 to -.358 (remember to modules) it because it is in the negative x range, for g(x) , range from x = -.358 to 0(remember to modules) and g(x) from x = 0 to 2.587.
5.Finally add them together to get answer.
answered Aug 22 at 11:42
Tensor Flow
11
1.Plot the two functions using graphic calculator
2.Find the intersection the functions around x = -.358
3.Find the x intersects for the 2 functions respectively in this case , for f(x) is x = -3 and g(x) is x = 2.587.
4.Integrate the functions, for f(x) ,range from x = -3 to -.358 (remember to modules) it because it is in the negative x range, for g(x) , range from x = -.358 to 0(remember to modules) and g(x) from x = 0 to 2.587.
5.Finally add them together to get answer.
answered Aug 22 at 11:42
Tensor Flow
11
edited Aug 22 at 11:48
answered Aug 22 at 11:42
Tensor Flow
11
answered Aug 22 at 11:42
Tensor Flow
11
answered Aug 22 at 11:42
Tensor Flow
11
11
1
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
add a comment |Â
1
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
1
1
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
Welcome to MSE. For some basic information about writing mathematics at this site see, e.g., basic help on mathjax notation, mathjax tutorial and quick reference, main meta site math tutorial and equation editing how-to.
– José Carlos Santos
Aug 22 at 11:46
add a comment |Â
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Wolfram alpha gives only one real intersection.
– Sobi
Aug 22 at 9:10
I find no intersections.
– stretch
Aug 22 at 9:40