Intersection of orbits is the orbit of intersection
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Let $G$ be a (topological) group acting on a space $X$. Let $xin X$ and $A,B$ be two subgroups of $G$. Is it true in general that $(Acdot x)cap (Bcdot x)= (Acap B)cdot x$?
group-theory topological-groups
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Let $G$ be a (topological) group acting on a space $X$. Let $xin X$ and $A,B$ be two subgroups of $G$. Is it true in general that $(Acdot x)cap (Bcdot x)= (Acap B)cdot x$?
group-theory topological-groups
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Let $G$ be a (topological) group acting on a space $X$. Let $xin X$ and $A,B$ be two subgroups of $G$. Is it true in general that $(Acdot x)cap (Bcdot x)= (Acap B)cdot x$?
group-theory topological-groups
Let $G$ be a (topological) group acting on a space $X$. Let $xin X$ and $A,B$ be two subgroups of $G$. Is it true in general that $(Acdot x)cap (Bcdot x)= (Acap B)cdot x$?
group-theory topological-groups
asked Aug 22 at 10:16
Amrat A
915
915
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1 Answer
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Let $G = C_2 times C_2$ and $X = Bbb Z/2Bbb Z$ and $(g^a,g^b) cdot overline n := overlinea + b + n$ and $A = (e,g), (e,e)$ and $B = (g,e), (e,e)$.
Then, LHS = $X$ and RHS = $overline 0$.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
accepted
Let $G = C_2 times C_2$ and $X = Bbb Z/2Bbb Z$ and $(g^a,g^b) cdot overline n := overlinea + b + n$ and $A = (e,g), (e,e)$ and $B = (g,e), (e,e)$.
Then, LHS = $X$ and RHS = $overline 0$.
add a comment |Â
up vote
2
down vote
accepted
Let $G = C_2 times C_2$ and $X = Bbb Z/2Bbb Z$ and $(g^a,g^b) cdot overline n := overlinea + b + n$ and $A = (e,g), (e,e)$ and $B = (g,e), (e,e)$.
Then, LHS = $X$ and RHS = $overline 0$.
add a comment |Â
up vote
2
down vote
accepted
up vote
2
down vote
accepted
Let $G = C_2 times C_2$ and $X = Bbb Z/2Bbb Z$ and $(g^a,g^b) cdot overline n := overlinea + b + n$ and $A = (e,g), (e,e)$ and $B = (g,e), (e,e)$.
Then, LHS = $X$ and RHS = $overline 0$.
Let $G = C_2 times C_2$ and $X = Bbb Z/2Bbb Z$ and $(g^a,g^b) cdot overline n := overlinea + b + n$ and $A = (e,g), (e,e)$ and $B = (g,e), (e,e)$.
Then, LHS = $X$ and RHS = $overline 0$.
answered Aug 22 at 10:38
Kenny Lau
19k2157
19k2157
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