If $C=A_5 times 3B$ be such that $textrank left( Aright)=3$, then Cx=0 and Bx=0 are equivalent systems.
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Prove or disprove- If $C=A_5 times 3B$ be such that $textrank left( Aright)=3$, then $Cx=0$ and $Bx=0$ are equivalent systems.
I do not know wether to prove or disprove it. If it is incorrect then can anyone give a counter example.
If it is true then please give a hint.
linear-algebra systems-of-equations
add a comment |Â
up vote
0
down vote
favorite
Prove or disprove- If $C=A_5 times 3B$ be such that $textrank left( Aright)=3$, then $Cx=0$ and $Bx=0$ are equivalent systems.
I do not know wether to prove or disprove it. If it is incorrect then can anyone give a counter example.
If it is true then please give a hint.
linear-algebra systems-of-equations
Hint: Rank of $A$ is 3, so columns of $A$ are linearly independent which means.....
â Anurag A
Aug 31 at 5:37
@AnuragA still insufficent
â Rakesh Bhatt
Aug 31 at 5:44
Think what can be said regarding the system $Amathbfx=mathbf0$? Can it have a non-zero solution?
â Anurag A
Aug 31 at 5:45
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Prove or disprove- If $C=A_5 times 3B$ be such that $textrank left( Aright)=3$, then $Cx=0$ and $Bx=0$ are equivalent systems.
I do not know wether to prove or disprove it. If it is incorrect then can anyone give a counter example.
If it is true then please give a hint.
linear-algebra systems-of-equations
Prove or disprove- If $C=A_5 times 3B$ be such that $textrank left( Aright)=3$, then $Cx=0$ and $Bx=0$ are equivalent systems.
I do not know wether to prove or disprove it. If it is incorrect then can anyone give a counter example.
If it is true then please give a hint.
linear-algebra systems-of-equations
linear-algebra systems-of-equations
asked Aug 31 at 5:22
Rakesh Bhatt
663112
663112
Hint: Rank of $A$ is 3, so columns of $A$ are linearly independent which means.....
â Anurag A
Aug 31 at 5:37
@AnuragA still insufficent
â Rakesh Bhatt
Aug 31 at 5:44
Think what can be said regarding the system $Amathbfx=mathbf0$? Can it have a non-zero solution?
â Anurag A
Aug 31 at 5:45
add a comment |Â
Hint: Rank of $A$ is 3, so columns of $A$ are linearly independent which means.....
â Anurag A
Aug 31 at 5:37
@AnuragA still insufficent
â Rakesh Bhatt
Aug 31 at 5:44
Think what can be said regarding the system $Amathbfx=mathbf0$? Can it have a non-zero solution?
â Anurag A
Aug 31 at 5:45
Hint: Rank of $A$ is 3, so columns of $A$ are linearly independent which means.....
â Anurag A
Aug 31 at 5:37
Hint: Rank of $A$ is 3, so columns of $A$ are linearly independent which means.....
â Anurag A
Aug 31 at 5:37
@AnuragA still insufficent
â Rakesh Bhatt
Aug 31 at 5:44
@AnuragA still insufficent
â Rakesh Bhatt
Aug 31 at 5:44
Think what can be said regarding the system $Amathbfx=mathbf0$? Can it have a non-zero solution?
â Anurag A
Aug 31 at 5:45
Think what can be said regarding the system $Amathbfx=mathbf0$? Can it have a non-zero solution?
â Anurag A
Aug 31 at 5:45
add a comment |Â
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Hint: Rank of $A$ is 3, so columns of $A$ are linearly independent which means.....
â Anurag A
Aug 31 at 5:37
@AnuragA still insufficent
â Rakesh Bhatt
Aug 31 at 5:44
Think what can be said regarding the system $Amathbfx=mathbf0$? Can it have a non-zero solution?
â Anurag A
Aug 31 at 5:45