Differentiable and continuous function [closed]

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Let $a,binmathbbR,a<b$ and let $f$ be a differentiable function $f:(a,b)rightarrowmathbbR$ with $f'$ continuous. Given $$f'(x)+(f(x))^2+1geq 0 forall xin(a,b), lim_xrightarrow a^+f(x)=+infty, lim_xrightarrow b^-f(x)=-infty,$$ how do we compute $b-a$?






calculus real-analysis limits derivatives







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closed as off-topic by Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500 Sep 5 at 10:43


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    Not only was your post totally unreadable, you didn't provide any attempts. Voting to close the question until attempts are provided.
    – Math_QED
    Sep 5 at 6:41






  • 4




    You can't. Take $-tan(x)$ over $left(-fracpi2, fracpi2right)$ and $-tanleft(fracx2right)$ over $(-pi, pi)$.
    – Theo Bendit
    Sep 5 at 6:56














up vote
1
down vote

favorite












Let $a,binmathbbR,a<b$ and let $f$ be a differentiable function $f:(a,b)rightarrowmathbbR$ with $f'$ continuous. Given $$f'(x)+(f(x))^2+1geq 0 forall xin(a,b), lim_xrightarrow a^+f(x)=+infty, lim_xrightarrow b^-f(x)=-infty,$$ how do we compute $b-a$?






calculus real-analysis limits derivatives







share|cite|improve this question















closed as off-topic by Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500 Sep 5 at 10:43


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    Not only was your post totally unreadable, you didn't provide any attempts. Voting to close the question until attempts are provided.
    – Math_QED
    Sep 5 at 6:41






  • 4




    You can't. Take $-tan(x)$ over $left(-fracpi2, fracpi2right)$ and $-tanleft(fracx2right)$ over $(-pi, pi)$.
    – Theo Bendit
    Sep 5 at 6:56












up vote
1
down vote

favorite









up vote
1
down vote

favorite











Let $a,binmathbbR,a<b$ and let $f$ be a differentiable function $f:(a,b)rightarrowmathbbR$ with $f'$ continuous. Given $$f'(x)+(f(x))^2+1geq 0 forall xin(a,b), lim_xrightarrow a^+f(x)=+infty, lim_xrightarrow b^-f(x)=-infty,$$ how do we compute $b-a$?






calculus real-analysis limits derivatives







share|cite|improve this question















Let $a,binmathbbR,a<b$ and let $f$ be a differentiable function $f:(a,b)rightarrowmathbbR$ with $f'$ continuous. Given $$f'(x)+(f(x))^2+1geq 0 forall xin(a,b), lim_xrightarrow a^+f(x)=+infty, lim_xrightarrow b^-f(x)=-infty,$$ how do we compute $b-a$?






calculus real-analysis limits derivatives




calculus real-analysis limits derivatives






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Sep 5 at 9:31









Bernard

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925




closed as off-topic by Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500 Sep 5 at 10:43


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500 Sep 5 at 10:43


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Math_QED, астон вілла олоф мэллбэрг, Theo Bendit, RRL, user91500
If this question can be reworded to fit the rules in the help center, please edit the question.







  • 2




    Not only was your post totally unreadable, you didn't provide any attempts. Voting to close the question until attempts are provided.
    – Math_QED
    Sep 5 at 6:41






  • 4




    You can't. Take $-tan(x)$ over $left(-fracpi2, fracpi2right)$ and $-tanleft(fracx2right)$ over $(-pi, pi)$.
    – Theo Bendit
    Sep 5 at 6:56












  • 2




    Not only was your post totally unreadable, you didn't provide any attempts. Voting to close the question until attempts are provided.
    – Math_QED
    Sep 5 at 6:41






  • 4




    You can't. Take $-tan(x)$ over $left(-fracpi2, fracpi2right)$ and $-tanleft(fracx2right)$ over $(-pi, pi)$.
    – Theo Bendit
    Sep 5 at 6:56







2




2




Not only was your post totally unreadable, you didn't provide any attempts. Voting to close the question until attempts are provided.
– Math_QED
Sep 5 at 6:41




Not only was your post totally unreadable, you didn't provide any attempts. Voting to close the question until attempts are provided.
– Math_QED
Sep 5 at 6:41




4




4




You can't. Take $-tan(x)$ over $left(-fracpi2, fracpi2right)$ and $-tanleft(fracx2right)$ over $(-pi, pi)$.
– Theo Bendit
Sep 5 at 6:56




You can't. Take $-tan(x)$ over $left(-fracpi2, fracpi2right)$ and $-tanleft(fracx2right)$ over $(-pi, pi)$.
– Theo Bendit
Sep 5 at 6:56















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