Area enclosed by two curves.

Clash Royale CLAN TAG#URR8PPP
up vote
1
down vote
favorite
Find the area enclosed by two curves.
$y=x^2$ and $y=-x^2+x+1$
My answer:
$frac-12 le x le 1$
$x^2 le y le -x^2+x+1$
$int_^ int_^dxdy = int_- frac12 ^1 ( int_x^2^-x^2+x+1dy)dx$
$P= int_ frac-12 ^1left( (-x^2+x+1)-(x^2)right)= frac98$
Is that correct, because the answer in my excercice book is $frac sqrt5 6$
integration area curves
add a comment |Â
up vote
1
down vote
favorite
Find the area enclosed by two curves.
$y=x^2$ and $y=-x^2+x+1$
My answer:
$frac-12 le x le 1$
$x^2 le y le -x^2+x+1$
$int_^ int_^dxdy = int_- frac12 ^1 ( int_x^2^-x^2+x+1dy)dx$
$P= int_ frac-12 ^1left( (-x^2+x+1)-(x^2)right)= frac98$
Is that correct, because the answer in my excercice book is $frac sqrt5 6$
integration area curves
I got the same as you, you I'd say the book is wrong, you are right...probably.
â DonAntonio
Jan 11 '17 at 22:07
How about that one: Find the volume of the solid enclosed by : $z=7-x^2$, $z=-2$, $y=-1$, $y=4$. My answer is 180, the answer in the book is again totally different..
â M.Szostu
Jan 11 '17 at 22:12
Yep, I get the same $;180;$ : $$int_-3^3int_-1^4int_-2^7-x^2dzdydx=180$$ Are you sure you're looking at the solutions in the correct chapter, sections...*book* ?
â DonAntonio
Jan 11 '17 at 22:31
I am, I checked multiple times to be sure, to be precise it is not a book per se, these are the materials our lecturer prepared for us, attaching allegedly "correct" answers. Ugh.
â M.Szostu
Jan 11 '17 at 22:33
Well, those notes at least will make a nice bonfire...:)
â DonAntonio
Jan 11 '17 at 22:34
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Find the area enclosed by two curves.
$y=x^2$ and $y=-x^2+x+1$
My answer:
$frac-12 le x le 1$
$x^2 le y le -x^2+x+1$
$int_^ int_^dxdy = int_- frac12 ^1 ( int_x^2^-x^2+x+1dy)dx$
$P= int_ frac-12 ^1left( (-x^2+x+1)-(x^2)right)= frac98$
Is that correct, because the answer in my excercice book is $frac sqrt5 6$
integration area curves
Find the area enclosed by two curves.
$y=x^2$ and $y=-x^2+x+1$
My answer:
$frac-12 le x le 1$
$x^2 le y le -x^2+x+1$
$int_^ int_^dxdy = int_- frac12 ^1 ( int_x^2^-x^2+x+1dy)dx$
$P= int_ frac-12 ^1left( (-x^2+x+1)-(x^2)right)= frac98$
Is that correct, because the answer in my excercice book is $frac sqrt5 6$
integration area curves
edited Aug 23 at 3:28
HugoTeixeira
22129
22129
asked Jan 11 '17 at 22:02
M.Szostu
192
192
I got the same as you, you I'd say the book is wrong, you are right...probably.
â DonAntonio
Jan 11 '17 at 22:07
How about that one: Find the volume of the solid enclosed by : $z=7-x^2$, $z=-2$, $y=-1$, $y=4$. My answer is 180, the answer in the book is again totally different..
â M.Szostu
Jan 11 '17 at 22:12
Yep, I get the same $;180;$ : $$int_-3^3int_-1^4int_-2^7-x^2dzdydx=180$$ Are you sure you're looking at the solutions in the correct chapter, sections...*book* ?
â DonAntonio
Jan 11 '17 at 22:31
I am, I checked multiple times to be sure, to be precise it is not a book per se, these are the materials our lecturer prepared for us, attaching allegedly "correct" answers. Ugh.
â M.Szostu
Jan 11 '17 at 22:33
Well, those notes at least will make a nice bonfire...:)
â DonAntonio
Jan 11 '17 at 22:34
add a comment |Â
I got the same as you, you I'd say the book is wrong, you are right...probably.
â DonAntonio
Jan 11 '17 at 22:07
How about that one: Find the volume of the solid enclosed by : $z=7-x^2$, $z=-2$, $y=-1$, $y=4$. My answer is 180, the answer in the book is again totally different..
â M.Szostu
Jan 11 '17 at 22:12
Yep, I get the same $;180;$ : $$int_-3^3int_-1^4int_-2^7-x^2dzdydx=180$$ Are you sure you're looking at the solutions in the correct chapter, sections...*book* ?
â DonAntonio
Jan 11 '17 at 22:31
I am, I checked multiple times to be sure, to be precise it is not a book per se, these are the materials our lecturer prepared for us, attaching allegedly "correct" answers. Ugh.
â M.Szostu
Jan 11 '17 at 22:33
Well, those notes at least will make a nice bonfire...:)
â DonAntonio
Jan 11 '17 at 22:34
I got the same as you, you I'd say the book is wrong, you are right...probably.
â DonAntonio
Jan 11 '17 at 22:07
I got the same as you, you I'd say the book is wrong, you are right...probably.
â DonAntonio
Jan 11 '17 at 22:07
How about that one: Find the volume of the solid enclosed by : $z=7-x^2$, $z=-2$, $y=-1$, $y=4$. My answer is 180, the answer in the book is again totally different..
â M.Szostu
Jan 11 '17 at 22:12
How about that one: Find the volume of the solid enclosed by : $z=7-x^2$, $z=-2$, $y=-1$, $y=4$. My answer is 180, the answer in the book is again totally different..
â M.Szostu
Jan 11 '17 at 22:12
Yep, I get the same $;180;$ : $$int_-3^3int_-1^4int_-2^7-x^2dzdydx=180$$ Are you sure you're looking at the solutions in the correct chapter, sections...*book* ?
â DonAntonio
Jan 11 '17 at 22:31
Yep, I get the same $;180;$ : $$int_-3^3int_-1^4int_-2^7-x^2dzdydx=180$$ Are you sure you're looking at the solutions in the correct chapter, sections...*book* ?
â DonAntonio
Jan 11 '17 at 22:31
I am, I checked multiple times to be sure, to be precise it is not a book per se, these are the materials our lecturer prepared for us, attaching allegedly "correct" answers. Ugh.
â M.Szostu
Jan 11 '17 at 22:33
I am, I checked multiple times to be sure, to be precise it is not a book per se, these are the materials our lecturer prepared for us, attaching allegedly "correct" answers. Ugh.
â M.Szostu
Jan 11 '17 at 22:33
Well, those notes at least will make a nice bonfire...:)
â DonAntonio
Jan 11 '17 at 22:34
Well, those notes at least will make a nice bonfire...:)
â DonAntonio
Jan 11 '17 at 22:34
add a comment |Â
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2093971%2farea-enclosed-by-two-curves%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
I got the same as you, you I'd say the book is wrong, you are right...probably.
â DonAntonio
Jan 11 '17 at 22:07
How about that one: Find the volume of the solid enclosed by : $z=7-x^2$, $z=-2$, $y=-1$, $y=4$. My answer is 180, the answer in the book is again totally different..
â M.Szostu
Jan 11 '17 at 22:12
Yep, I get the same $;180;$ : $$int_-3^3int_-1^4int_-2^7-x^2dzdydx=180$$ Are you sure you're looking at the solutions in the correct chapter, sections...*book* ?
â DonAntonio
Jan 11 '17 at 22:31
I am, I checked multiple times to be sure, to be precise it is not a book per se, these are the materials our lecturer prepared for us, attaching allegedly "correct" answers. Ugh.
â M.Szostu
Jan 11 '17 at 22:33
Well, those notes at least will make a nice bonfire...:)
â DonAntonio
Jan 11 '17 at 22:34