Using a continuous failure probability to get reliability $R(T) = exp(-int_t=0^T h(t) dt)$

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I have a continuous process for which I want to compute the probability that it did not fail until time $T$.



I tried the reliability / survival function:
$$ beginalign
R(T) = exp(-int_t=0^T h(t) dt)
endalign $$



I do not have a failure rate $h(t)$, but a failure probability given by a continuous but not necessarily monotonic function $p_fail(t)$, which gives the probability that the process fails at any time $t$ (with $t in R, t ge 0$).



Here, $p_fail(t)$ does not have a unit, which messes up the whole calculation. Therefore, I think my approach is wrong.



How can I calculate the reliability of the process?




To illustrate my problem:



Consider the simple function $p_1,fail(t [s]) = frac0.013600s cdot t$, for $t$ in seconds. This (in my opinion) is equal to $p_2,fail(t [h]) = frac0.011h cdot t$, for $t$ in hours.



With $T = 1h = 3600s$ the integration gives different results, depending on the unit of time:



beginarray c
hline & int_t=0^T p(t) dt \
hline p_1 & 18.00 \
hline p_2 & 0.005 \
hline
endarray







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    up vote
    0
    down vote

    favorite












    I have a continuous process for which I want to compute the probability that it did not fail until time $T$.



    I tried the reliability / survival function:
    $$ beginalign
    R(T) = exp(-int_t=0^T h(t) dt)
    endalign $$



    I do not have a failure rate $h(t)$, but a failure probability given by a continuous but not necessarily monotonic function $p_fail(t)$, which gives the probability that the process fails at any time $t$ (with $t in R, t ge 0$).



    Here, $p_fail(t)$ does not have a unit, which messes up the whole calculation. Therefore, I think my approach is wrong.



    How can I calculate the reliability of the process?




    To illustrate my problem:



    Consider the simple function $p_1,fail(t [s]) = frac0.013600s cdot t$, for $t$ in seconds. This (in my opinion) is equal to $p_2,fail(t [h]) = frac0.011h cdot t$, for $t$ in hours.



    With $T = 1h = 3600s$ the integration gives different results, depending on the unit of time:



    beginarray c
    hline & int_t=0^T p(t) dt \
    hline p_1 & 18.00 \
    hline p_2 & 0.005 \
    hline
    endarray







    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a continuous process for which I want to compute the probability that it did not fail until time $T$.



      I tried the reliability / survival function:
      $$ beginalign
      R(T) = exp(-int_t=0^T h(t) dt)
      endalign $$



      I do not have a failure rate $h(t)$, but a failure probability given by a continuous but not necessarily monotonic function $p_fail(t)$, which gives the probability that the process fails at any time $t$ (with $t in R, t ge 0$).



      Here, $p_fail(t)$ does not have a unit, which messes up the whole calculation. Therefore, I think my approach is wrong.



      How can I calculate the reliability of the process?




      To illustrate my problem:



      Consider the simple function $p_1,fail(t [s]) = frac0.013600s cdot t$, for $t$ in seconds. This (in my opinion) is equal to $p_2,fail(t [h]) = frac0.011h cdot t$, for $t$ in hours.



      With $T = 1h = 3600s$ the integration gives different results, depending on the unit of time:



      beginarray c
      hline & int_t=0^T p(t) dt \
      hline p_1 & 18.00 \
      hline p_2 & 0.005 \
      hline
      endarray







      share|cite|improve this question














      I have a continuous process for which I want to compute the probability that it did not fail until time $T$.



      I tried the reliability / survival function:
      $$ beginalign
      R(T) = exp(-int_t=0^T h(t) dt)
      endalign $$



      I do not have a failure rate $h(t)$, but a failure probability given by a continuous but not necessarily monotonic function $p_fail(t)$, which gives the probability that the process fails at any time $t$ (with $t in R, t ge 0$).



      Here, $p_fail(t)$ does not have a unit, which messes up the whole calculation. Therefore, I think my approach is wrong.



      How can I calculate the reliability of the process?




      To illustrate my problem:



      Consider the simple function $p_1,fail(t [s]) = frac0.013600s cdot t$, for $t$ in seconds. This (in my opinion) is equal to $p_2,fail(t [h]) = frac0.011h cdot t$, for $t$ in hours.



      With $T = 1h = 3600s$ the integration gives different results, depending on the unit of time:



      beginarray c
      hline & int_t=0^T p(t) dt \
      hline p_1 & 18.00 \
      hline p_2 & 0.005 \
      hline
      endarray









      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Aug 30 at 13:22

























      asked Aug 6 at 8:49









      Stanley F.

      1196




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