How to prove the following relation for rank of matrices?

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If $mathbbA$ and $mathbbB$ have same rows then how to show that the following relation holds $$rank([mathbbA~B])=rank(mathbbA)+dim(textProj_mathcalA^CmathcalB)$$ where $textProj_mathcalA^CmathcalB$ is the projection of span of $mathbbB$, denoted by $mathcalB$, on the orthogonal complement of the span of $mathbbA$, denoted by $mathcalA^c$. $dim$ denotes the number of dimension.
matrices matrix-rank dimension-theory
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If $mathbbA$ and $mathbbB$ have same rows then how to show that the following relation holds $$rank([mathbbA~B])=rank(mathbbA)+dim(textProj_mathcalA^CmathcalB)$$ where $textProj_mathcalA^CmathcalB$ is the projection of span of $mathbbB$, denoted by $mathcalB$, on the orthogonal complement of the span of $mathbbA$, denoted by $mathcalA^c$. $dim$ denotes the number of dimension.
matrices matrix-rank dimension-theory
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
If $mathbbA$ and $mathbbB$ have same rows then how to show that the following relation holds $$rank([mathbbA~B])=rank(mathbbA)+dim(textProj_mathcalA^CmathcalB)$$ where $textProj_mathcalA^CmathcalB$ is the projection of span of $mathbbB$, denoted by $mathcalB$, on the orthogonal complement of the span of $mathbbA$, denoted by $mathcalA^c$. $dim$ denotes the number of dimension.
matrices matrix-rank dimension-theory
If $mathbbA$ and $mathbbB$ have same rows then how to show that the following relation holds $$rank([mathbbA~B])=rank(mathbbA)+dim(textProj_mathcalA^CmathcalB)$$ where $textProj_mathcalA^CmathcalB$ is the projection of span of $mathbbB$, denoted by $mathcalB$, on the orthogonal complement of the span of $mathbbA$, denoted by $mathcalA^c$. $dim$ denotes the number of dimension.
matrices matrix-rank dimension-theory
matrices matrix-rank dimension-theory
asked Sep 10 at 8:53
Frank Moses
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1,129317
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