Coset of subgroup

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We are given the group $G=mathbbZ_8$ , an element $a$ of $G$ and a non-trivial subgroup $H$ of $G$ such that $Sigma=a,5 $ is a coset of $H$ in $G$. Then $a$ is one of these numbers:
$$7,0,5,6,1.$$
I think that $a$ is $5$ since a coset contains only numbers that are multiple the one to the other, am I right?
linear-algebra
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We are given the group $G=mathbbZ_8$ , an element $a$ of $G$ and a non-trivial subgroup $H$ of $G$ such that $Sigma=a,5 $ is a coset of $H$ in $G$. Then $a$ is one of these numbers:
$$7,0,5,6,1.$$
I think that $a$ is $5$ since a coset contains only numbers that are multiple the one to the other, am I right?
linear-algebra
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up vote
0
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We are given the group $G=mathbbZ_8$ , an element $a$ of $G$ and a non-trivial subgroup $H$ of $G$ such that $Sigma=a,5 $ is a coset of $H$ in $G$. Then $a$ is one of these numbers:
$$7,0,5,6,1.$$
I think that $a$ is $5$ since a coset contains only numbers that are multiple the one to the other, am I right?
linear-algebra
We are given the group $G=mathbbZ_8$ , an element $a$ of $G$ and a non-trivial subgroup $H$ of $G$ such that $Sigma=a,5 $ is a coset of $H$ in $G$. Then $a$ is one of these numbers:
$$7,0,5,6,1.$$
I think that $a$ is $5$ since a coset contains only numbers that are multiple the one to the other, am I right?
linear-algebra
linear-algebra
asked Sep 10 at 10:45
Evinda
552412
552412
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2 Answers
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No, you are not right. All cosets have the same number of elements. So, if $Sigma$ only has a single element, all other cosets have a single element too and that can only happen if $H=0$. But we are assuming that $H$ is a non-trivial subgroup.
Hint: The answer is $a=1$. Can you prove it?
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
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Here are the intermediate steps I would do to get through your problem:
- How many elements does $H$ have?
- Which subgroups of $G$ have that many elements?
- For each of those subgroups, what are all its cosets?
- Which of those cosets contain $5$?
- What other elements are together with $5$ in any of those cosets?
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
No, you are not right. All cosets have the same number of elements. So, if $Sigma$ only has a single element, all other cosets have a single element too and that can only happen if $H=0$. But we are assuming that $H$ is a non-trivial subgroup.
Hint: The answer is $a=1$. Can you prove it?
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
add a comment |Â
up vote
2
down vote
No, you are not right. All cosets have the same number of elements. So, if $Sigma$ only has a single element, all other cosets have a single element too and that can only happen if $H=0$. But we are assuming that $H$ is a non-trivial subgroup.
Hint: The answer is $a=1$. Can you prove it?
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
add a comment |Â
up vote
2
down vote
up vote
2
down vote
No, you are not right. All cosets have the same number of elements. So, if $Sigma$ only has a single element, all other cosets have a single element too and that can only happen if $H=0$. But we are assuming that $H$ is a non-trivial subgroup.
Hint: The answer is $a=1$. Can you prove it?
No, you are not right. All cosets have the same number of elements. So, if $Sigma$ only has a single element, all other cosets have a single element too and that can only happen if $H=0$. But we are assuming that $H$ is a non-trivial subgroup.
Hint: The answer is $a=1$. Can you prove it?
edited Sep 10 at 10:57
answered Sep 10 at 10:49


José Carlos Santos
124k17101186
124k17101186
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
add a comment |Â
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
$left|Sigmaright|=1$ only happens when $H=0$, not when $H=G$. So for $a=5$ we have a coset of the trivial subgroup.
– Christoph
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
@Christoph I've edited my answer. Thank you.
– José Carlos Santos
Sep 10 at 10:57
add a comment |Â
up vote
1
down vote
Here are the intermediate steps I would do to get through your problem:
- How many elements does $H$ have?
- Which subgroups of $G$ have that many elements?
- For each of those subgroups, what are all its cosets?
- Which of those cosets contain $5$?
- What other elements are together with $5$ in any of those cosets?
add a comment |Â
up vote
1
down vote
Here are the intermediate steps I would do to get through your problem:
- How many elements does $H$ have?
- Which subgroups of $G$ have that many elements?
- For each of those subgroups, what are all its cosets?
- Which of those cosets contain $5$?
- What other elements are together with $5$ in any of those cosets?
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Here are the intermediate steps I would do to get through your problem:
- How many elements does $H$ have?
- Which subgroups of $G$ have that many elements?
- For each of those subgroups, what are all its cosets?
- Which of those cosets contain $5$?
- What other elements are together with $5$ in any of those cosets?
Here are the intermediate steps I would do to get through your problem:
- How many elements does $H$ have?
- Which subgroups of $G$ have that many elements?
- For each of those subgroups, what are all its cosets?
- Which of those cosets contain $5$?
- What other elements are together with $5$ in any of those cosets?
answered Sep 10 at 11:02
Arthur
102k797178
102k797178
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