$BbbCP^1$ how many charts does it have?

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When we define $BbbCP^1$ as a complex $1$-manifold, we give it two charts $(U_0,gamma_0)$ and $(U_1,gamma_1)$. We also say it has a complex structure $Sigma$, which is an equivalence class of analytically compatible atlases.
Does this mean that $BbbCP^1$ has only two charts, or does it have every chart that is compatible with these two charts as well (surely infinitely many)?
algebraic-geometry complex-geometry riemann-surfaces
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When we define $BbbCP^1$ as a complex $1$-manifold, we give it two charts $(U_0,gamma_0)$ and $(U_1,gamma_1)$. We also say it has a complex structure $Sigma$, which is an equivalence class of analytically compatible atlases.
Does this mean that $BbbCP^1$ has only two charts, or does it have every chart that is compatible with these two charts as well (surely infinitely many)?
algebraic-geometry complex-geometry riemann-surfaces
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
When we define $BbbCP^1$ as a complex $1$-manifold, we give it two charts $(U_0,gamma_0)$ and $(U_1,gamma_1)$. We also say it has a complex structure $Sigma$, which is an equivalence class of analytically compatible atlases.
Does this mean that $BbbCP^1$ has only two charts, or does it have every chart that is compatible with these two charts as well (surely infinitely many)?
algebraic-geometry complex-geometry riemann-surfaces
When we define $BbbCP^1$ as a complex $1$-manifold, we give it two charts $(U_0,gamma_0)$ and $(U_1,gamma_1)$. We also say it has a complex structure $Sigma$, which is an equivalence class of analytically compatible atlases.
Does this mean that $BbbCP^1$ has only two charts, or does it have every chart that is compatible with these two charts as well (surely infinitely many)?
algebraic-geometry complex-geometry riemann-surfaces
algebraic-geometry complex-geometry riemann-surfaces
asked Sep 10 at 13:31
user591482
154
154
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1 Answer
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oldest
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up vote
3
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It has all the compatible charts - indeed infinitely many, and you can choose the ones you want to use in any particular computation.
The minimum number of charts that will cover the manifold is two. The two you name are the conventional ones.
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
It has all the compatible charts - indeed infinitely many, and you can choose the ones you want to use in any particular computation.
The minimum number of charts that will cover the manifold is two. The two you name are the conventional ones.
add a comment |Â
up vote
3
down vote
accepted
It has all the compatible charts - indeed infinitely many, and you can choose the ones you want to use in any particular computation.
The minimum number of charts that will cover the manifold is two. The two you name are the conventional ones.
add a comment |Â
up vote
3
down vote
accepted
up vote
3
down vote
accepted
It has all the compatible charts - indeed infinitely many, and you can choose the ones you want to use in any particular computation.
The minimum number of charts that will cover the manifold is two. The two you name are the conventional ones.
It has all the compatible charts - indeed infinitely many, and you can choose the ones you want to use in any particular computation.
The minimum number of charts that will cover the manifold is two. The two you name are the conventional ones.
answered Sep 10 at 13:33
Ethan Bolker
36.7k54299
36.7k54299
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add a comment |Â
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