Solving $sectheta - 1 = left(sqrt2 - 1right) tantheta$
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Solve
$$sectheta - 1 = left(sqrt2 - 1right) tantheta$$
My try :
Is there any process possible for this equation? Please share it.
trigonometry
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up vote
-1
down vote
favorite
Solve
$$sectheta - 1 = left(sqrt2 - 1right) tantheta$$
My try :
Is there any process possible for this equation? Please share it.
trigonometry
1
Your solution is correct. Please read this tutorial on how to typeset mathematics on this site.
â N. F. Taussig
Aug 17 at 10:10
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up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Solve
$$sectheta - 1 = left(sqrt2 - 1right) tantheta$$
My try :
Is there any process possible for this equation? Please share it.
trigonometry
Solve
$$sectheta - 1 = left(sqrt2 - 1right) tantheta$$
My try :
Is there any process possible for this equation? Please share it.
trigonometry
edited Aug 17 at 5:31
Blue
43.8k868141
43.8k868141
asked Aug 17 at 5:17
user580093
6015
6015
1
Your solution is correct. Please read this tutorial on how to typeset mathematics on this site.
â N. F. Taussig
Aug 17 at 10:10
add a comment |Â
1
Your solution is correct. Please read this tutorial on how to typeset mathematics on this site.
â N. F. Taussig
Aug 17 at 10:10
1
1
Your solution is correct. Please read this tutorial on how to typeset mathematics on this site.
â N. F. Taussig
Aug 17 at 10:10
Your solution is correct. Please read this tutorial on how to typeset mathematics on this site.
â N. F. Taussig
Aug 17 at 10:10
add a comment |Â
2 Answers
2
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oldest
votes
up vote
1
down vote
accepted
Hint:
$$dfracsec2y-1tan2y=dfrac1-cos2ysin2y=tan y$$
Alternatively, $$sqrt2-1=dfracsec2y-1tan2y=csc2y-cot2y$$
$$iffcsc2y+cot2y=dfrac1csc2y-cot2y=?$$
add a comment |Â
up vote
2
down vote
HINT:
Dividing tan theta both side you get - $$frac1-cosxsinx= sqrt2-1$$ Now square it on both sides , and solving further you will reach the solution.
Additional hints: $$frac1-cosx1+cosx= 3-2sqrt2$$ $$cosx = frac1sqrt2 $$ and you are done.
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
3
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Hint:
$$dfracsec2y-1tan2y=dfrac1-cos2ysin2y=tan y$$
Alternatively, $$sqrt2-1=dfracsec2y-1tan2y=csc2y-cot2y$$
$$iffcsc2y+cot2y=dfrac1csc2y-cot2y=?$$
add a comment |Â
up vote
1
down vote
accepted
Hint:
$$dfracsec2y-1tan2y=dfrac1-cos2ysin2y=tan y$$
Alternatively, $$sqrt2-1=dfracsec2y-1tan2y=csc2y-cot2y$$
$$iffcsc2y+cot2y=dfrac1csc2y-cot2y=?$$
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Hint:
$$dfracsec2y-1tan2y=dfrac1-cos2ysin2y=tan y$$
Alternatively, $$sqrt2-1=dfracsec2y-1tan2y=csc2y-cot2y$$
$$iffcsc2y+cot2y=dfrac1csc2y-cot2y=?$$
Hint:
$$dfracsec2y-1tan2y=dfrac1-cos2ysin2y=tan y$$
Alternatively, $$sqrt2-1=dfracsec2y-1tan2y=csc2y-cot2y$$
$$iffcsc2y+cot2y=dfrac1csc2y-cot2y=?$$
answered Aug 17 at 5:21
lab bhattacharjee
215k14152264
215k14152264
add a comment |Â
add a comment |Â
up vote
2
down vote
HINT:
Dividing tan theta both side you get - $$frac1-cosxsinx= sqrt2-1$$ Now square it on both sides , and solving further you will reach the solution.
Additional hints: $$frac1-cosx1+cosx= 3-2sqrt2$$ $$cosx = frac1sqrt2 $$ and you are done.
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
3
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
add a comment |Â
up vote
2
down vote
HINT:
Dividing tan theta both side you get - $$frac1-cosxsinx= sqrt2-1$$ Now square it on both sides , and solving further you will reach the solution.
Additional hints: $$frac1-cosx1+cosx= 3-2sqrt2$$ $$cosx = frac1sqrt2 $$ and you are done.
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
3
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
add a comment |Â
up vote
2
down vote
up vote
2
down vote
HINT:
Dividing tan theta both side you get - $$frac1-cosxsinx= sqrt2-1$$ Now square it on both sides , and solving further you will reach the solution.
Additional hints: $$frac1-cosx1+cosx= 3-2sqrt2$$ $$cosx = frac1sqrt2 $$ and you are done.
HINT:
Dividing tan theta both side you get - $$frac1-cosxsinx= sqrt2-1$$ Now square it on both sides , and solving further you will reach the solution.
Additional hints: $$frac1-cosx1+cosx= 3-2sqrt2$$ $$cosx = frac1sqrt2 $$ and you are done.
answered Aug 17 at 5:35
Identicon
42015
42015
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
3
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
add a comment |Â
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
3
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
Are the answers of yours the same of main equation?
â Nosrati
Aug 17 at 5:41
3
3
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
two points: 1) division by tan theta deprived of one root; 2) squaring introduced extra root.
â farruhota
Aug 17 at 5:58
add a comment |Â
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1
Your solution is correct. Please read this tutorial on how to typeset mathematics on this site.
â N. F. Taussig
Aug 17 at 10:10