If $Z_1,Z_2,â¦$ are i.i.d., $X_0$ is independent of $Z_1,Z_2,â¦$ and $X_n=ÃÂ(X_n-1,Z_n)$, then $X_0,â¦,X_n-1$ is independent of $ÃÂ(x,Z_n)$
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Let
- $(Omega,mathcal A),(D,mathcal D)$ and $(E,mathcal E)$ be measurable spaces
- $Z_1,Z_2,ldots:Omegato D$ be independent and identically distributed random variables
- $X_0:Omegato E$ be a random variable independent of $Z_1,Z_2,ldots$
- $varphi:Etimes Dto E$ be $(mathcal Eotimesmathcal D,mathcal E)$-measurable and $$X_n:=varphi(X_n-1,Z_n);;;textfor ninmathbb N$$
Fix $xin E$. How can we show that $X_0,ldots,X_n-1$ is independent of $varphi(x,Z_n)$ for all $ninmathbb N$?
Clearly, since $X_0$ is independent of $Z_1$, $X_0$ is independent of $varphi(x,Z_1)$. This follows from the fat that if $X,Y$ are independent and $f,g$ are measurable, then $fcirc X,gcirc Y$ are independent.
However, I don't see how I need to proceed for $n>1$. The problem is that $X$ being independent of $Y,Z$ doesn't imply independence of $X$ and $(Y,Z)$.
probability-theory independence
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Let
- $(Omega,mathcal A),(D,mathcal D)$ and $(E,mathcal E)$ be measurable spaces
- $Z_1,Z_2,ldots:Omegato D$ be independent and identically distributed random variables
- $X_0:Omegato E$ be a random variable independent of $Z_1,Z_2,ldots$
- $varphi:Etimes Dto E$ be $(mathcal Eotimesmathcal D,mathcal E)$-measurable and $$X_n:=varphi(X_n-1,Z_n);;;textfor ninmathbb N$$
Fix $xin E$. How can we show that $X_0,ldots,X_n-1$ is independent of $varphi(x,Z_n)$ for all $ninmathbb N$?
Clearly, since $X_0$ is independent of $Z_1$, $X_0$ is independent of $varphi(x,Z_1)$. This follows from the fat that if $X,Y$ are independent and $f,g$ are measurable, then $fcirc X,gcirc Y$ are independent.
However, I don't see how I need to proceed for $n>1$. The problem is that $X$ being independent of $Y,Z$ doesn't imply independence of $X$ and $(Y,Z)$.
probability-theory independence
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Let
- $(Omega,mathcal A),(D,mathcal D)$ and $(E,mathcal E)$ be measurable spaces
- $Z_1,Z_2,ldots:Omegato D$ be independent and identically distributed random variables
- $X_0:Omegato E$ be a random variable independent of $Z_1,Z_2,ldots$
- $varphi:Etimes Dto E$ be $(mathcal Eotimesmathcal D,mathcal E)$-measurable and $$X_n:=varphi(X_n-1,Z_n);;;textfor ninmathbb N$$
Fix $xin E$. How can we show that $X_0,ldots,X_n-1$ is independent of $varphi(x,Z_n)$ for all $ninmathbb N$?
Clearly, since $X_0$ is independent of $Z_1$, $X_0$ is independent of $varphi(x,Z_1)$. This follows from the fat that if $X,Y$ are independent and $f,g$ are measurable, then $fcirc X,gcirc Y$ are independent.
However, I don't see how I need to proceed for $n>1$. The problem is that $X$ being independent of $Y,Z$ doesn't imply independence of $X$ and $(Y,Z)$.
probability-theory independence
Let
- $(Omega,mathcal A),(D,mathcal D)$ and $(E,mathcal E)$ be measurable spaces
- $Z_1,Z_2,ldots:Omegato D$ be independent and identically distributed random variables
- $X_0:Omegato E$ be a random variable independent of $Z_1,Z_2,ldots$
- $varphi:Etimes Dto E$ be $(mathcal Eotimesmathcal D,mathcal E)$-measurable and $$X_n:=varphi(X_n-1,Z_n);;;textfor ninmathbb N$$
Fix $xin E$. How can we show that $X_0,ldots,X_n-1$ is independent of $varphi(x,Z_n)$ for all $ninmathbb N$?
Clearly, since $X_0$ is independent of $Z_1$, $X_0$ is independent of $varphi(x,Z_1)$. This follows from the fat that if $X,Y$ are independent and $f,g$ are measurable, then $fcirc X,gcirc Y$ are independent.
However, I don't see how I need to proceed for $n>1$. The problem is that $X$ being independent of $Y,Z$ doesn't imply independence of $X$ and $(Y,Z)$.
probability-theory independence
edited Aug 17 at 9:03
asked Aug 17 at 8:46
0xbadf00d
2,05941128
2,05941128
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1 Answer
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Each of the variables $X_0,X_1,...,X_n-1$ is measurable w.r..t $sigma X_0,Z_1,...,Z_n-1$ and $Z_n$ is independent of this sigma algebra. Hence $phi (x,Z_n)$ is independent of this sigma algebra which makes it independent of $X_0,X_1,...,X_n-1$.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Each of the variables $X_0,X_1,...,X_n-1$ is measurable w.r..t $sigma X_0,Z_1,...,Z_n-1$ and $Z_n$ is independent of this sigma algebra. Hence $phi (x,Z_n)$ is independent of this sigma algebra which makes it independent of $X_0,X_1,...,X_n-1$.
add a comment |Â
up vote
1
down vote
accepted
Each of the variables $X_0,X_1,...,X_n-1$ is measurable w.r..t $sigma X_0,Z_1,...,Z_n-1$ and $Z_n$ is independent of this sigma algebra. Hence $phi (x,Z_n)$ is independent of this sigma algebra which makes it independent of $X_0,X_1,...,X_n-1$.
add a comment |Â
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Each of the variables $X_0,X_1,...,X_n-1$ is measurable w.r..t $sigma X_0,Z_1,...,Z_n-1$ and $Z_n$ is independent of this sigma algebra. Hence $phi (x,Z_n)$ is independent of this sigma algebra which makes it independent of $X_0,X_1,...,X_n-1$.
Each of the variables $X_0,X_1,...,X_n-1$ is measurable w.r..t $sigma X_0,Z_1,...,Z_n-1$ and $Z_n$ is independent of this sigma algebra. Hence $phi (x,Z_n)$ is independent of this sigma algebra which makes it independent of $X_0,X_1,...,X_n-1$.
answered Aug 17 at 8:51
Kavi Rama Murthy
22.8k2933
22.8k2933
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