Infinite subgroups of elliptic curves and quotients
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Let $E_1$ be an elliptic curve over $Bbb Q$ and $S subset E_1(Bbb Q)$ be a subgroup.
Is there an elliptic curve $E_2$ with an algebraic group morphism $E_1 to E_2$, and such that $E_2(Bbb Q) cong E_1(Bbb Q) / S$ ?
Or such that
$E_2(overlineBbb Q) cong E_1(overlineBbb Q) / S$ (seeing $E_1(Bbb Q)$ as a subgroup $E_1(overlineBbb Q)$)?
According to Silverman's books on elliptic curves, this holds if $S$ is finite, but what if $S$ has rank $1$, for instance?
Thank you!
elliptic-curves arithmetic-geometry
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up vote
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favorite
Let $E_1$ be an elliptic curve over $Bbb Q$ and $S subset E_1(Bbb Q)$ be a subgroup.
Is there an elliptic curve $E_2$ with an algebraic group morphism $E_1 to E_2$, and such that $E_2(Bbb Q) cong E_1(Bbb Q) / S$ ?
Or such that
$E_2(overlineBbb Q) cong E_1(overlineBbb Q) / S$ (seeing $E_1(Bbb Q)$ as a subgroup $E_1(overlineBbb Q)$)?
According to Silverman's books on elliptic curves, this holds if $S$ is finite, but what if $S$ has rank $1$, for instance?
Thank you!
elliptic-curves arithmetic-geometry
2
A surjective algebraic map between elliptic curves will have a finite kernel.
â Lord Shark the Unknown
Aug 26 at 13:06
@LordSharktheUnknown: ok, but actually I don't need surjectivity for the map, I only need to have the $Bbb Q$-points (or the $overlineBbb Q$-points) of $E_2$ to be a quotient of those of $E_1$. What can we say then ?
â Alphonse
Aug 26 at 13:12
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $E_1$ be an elliptic curve over $Bbb Q$ and $S subset E_1(Bbb Q)$ be a subgroup.
Is there an elliptic curve $E_2$ with an algebraic group morphism $E_1 to E_2$, and such that $E_2(Bbb Q) cong E_1(Bbb Q) / S$ ?
Or such that
$E_2(overlineBbb Q) cong E_1(overlineBbb Q) / S$ (seeing $E_1(Bbb Q)$ as a subgroup $E_1(overlineBbb Q)$)?
According to Silverman's books on elliptic curves, this holds if $S$ is finite, but what if $S$ has rank $1$, for instance?
Thank you!
elliptic-curves arithmetic-geometry
Let $E_1$ be an elliptic curve over $Bbb Q$ and $S subset E_1(Bbb Q)$ be a subgroup.
Is there an elliptic curve $E_2$ with an algebraic group morphism $E_1 to E_2$, and such that $E_2(Bbb Q) cong E_1(Bbb Q) / S$ ?
Or such that
$E_2(overlineBbb Q) cong E_1(overlineBbb Q) / S$ (seeing $E_1(Bbb Q)$ as a subgroup $E_1(overlineBbb Q)$)?
According to Silverman's books on elliptic curves, this holds if $S$ is finite, but what if $S$ has rank $1$, for instance?
Thank you!
elliptic-curves arithmetic-geometry
edited Aug 26 at 13:11
asked Aug 26 at 13:02
Alphonse
1,815622
1,815622
2
A surjective algebraic map between elliptic curves will have a finite kernel.
â Lord Shark the Unknown
Aug 26 at 13:06
@LordSharktheUnknown: ok, but actually I don't need surjectivity for the map, I only need to have the $Bbb Q$-points (or the $overlineBbb Q$-points) of $E_2$ to be a quotient of those of $E_1$. What can we say then ?
â Alphonse
Aug 26 at 13:12
add a comment |Â
2
A surjective algebraic map between elliptic curves will have a finite kernel.
â Lord Shark the Unknown
Aug 26 at 13:06
@LordSharktheUnknown: ok, but actually I don't need surjectivity for the map, I only need to have the $Bbb Q$-points (or the $overlineBbb Q$-points) of $E_2$ to be a quotient of those of $E_1$. What can we say then ?
â Alphonse
Aug 26 at 13:12
2
2
A surjective algebraic map between elliptic curves will have a finite kernel.
â Lord Shark the Unknown
Aug 26 at 13:06
A surjective algebraic map between elliptic curves will have a finite kernel.
â Lord Shark the Unknown
Aug 26 at 13:06
@LordSharktheUnknown: ok, but actually I don't need surjectivity for the map, I only need to have the $Bbb Q$-points (or the $overlineBbb Q$-points) of $E_2$ to be a quotient of those of $E_1$. What can we say then ?
â Alphonse
Aug 26 at 13:12
@LordSharktheUnknown: ok, but actually I don't need surjectivity for the map, I only need to have the $Bbb Q$-points (or the $overlineBbb Q$-points) of $E_2$ to be a quotient of those of $E_1$. What can we say then ?
â Alphonse
Aug 26 at 13:12
add a comment |Â
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2
A surjective algebraic map between elliptic curves will have a finite kernel.
â Lord Shark the Unknown
Aug 26 at 13:06
@LordSharktheUnknown: ok, but actually I don't need surjectivity for the map, I only need to have the $Bbb Q$-points (or the $overlineBbb Q$-points) of $E_2$ to be a quotient of those of $E_1$. What can we say then ?
â Alphonse
Aug 26 at 13:12