If $A = a $, $B = b, c $ and $C = d,e,f,g,h,i,j $, find (i) $P(A times B)$; (ii) $|P(B times C)|$.

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If $A = a $, $B = b, c $ and $C = d,e,f,g,h,i,j $, find



(i) $P(A times B)$;



(ii) $|P(B times C)|$.



$A times B = (a, b), (a, c) $



$P(A times B) = emptyset, (a, b) , (a, c) , (a, b), (a, c) $



$|B times C| = |B| times |C| = 14$. So I think that $|P(B times C)| = 2^14$.



Is this correct? Thank you.







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    down vote

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    If $A = a $, $B = b, c $ and $C = d,e,f,g,h,i,j $, find



    (i) $P(A times B)$;



    (ii) $|P(B times C)|$.



    $A times B = (a, b), (a, c) $



    $P(A times B) = emptyset, (a, b) , (a, c) , (a, b), (a, c) $



    $|B times C| = |B| times |C| = 14$. So I think that $|P(B times C)| = 2^14$.



    Is this correct? Thank you.







    share|cite|improve this question






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      If $A = a $, $B = b, c $ and $C = d,e,f,g,h,i,j $, find



      (i) $P(A times B)$;



      (ii) $|P(B times C)|$.



      $A times B = (a, b), (a, c) $



      $P(A times B) = emptyset, (a, b) , (a, c) , (a, b), (a, c) $



      $|B times C| = |B| times |C| = 14$. So I think that $|P(B times C)| = 2^14$.



      Is this correct? Thank you.







      share|cite|improve this question












      If $A = a $, $B = b, c $ and $C = d,e,f,g,h,i,j $, find



      (i) $P(A times B)$;



      (ii) $|P(B times C)|$.



      $A times B = (a, b), (a, c) $



      $P(A times B) = emptyset, (a, b) , (a, c) , (a, b), (a, c) $



      $|B times C| = |B| times |C| = 14$. So I think that $|P(B times C)| = 2^14$.



      Is this correct? Thank you.









      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Aug 26 at 13:59









      Wyuw

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          Yes, you have answered the question correctly.



          In general, $P(X)=2^$ where $P(X)$ denote the power set of $X$ because for each possible subset we decide if it is in that particular subset.






          share|cite|improve this answer






















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            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            2
            down vote



            accepted










            Yes, you have answered the question correctly.



            In general, $P(X)=2^$ where $P(X)$ denote the power set of $X$ because for each possible subset we decide if it is in that particular subset.






            share|cite|improve this answer


























              up vote
              2
              down vote



              accepted










              Yes, you have answered the question correctly.



              In general, $P(X)=2^$ where $P(X)$ denote the power set of $X$ because for each possible subset we decide if it is in that particular subset.






              share|cite|improve this answer
























                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                Yes, you have answered the question correctly.



                In general, $P(X)=2^$ where $P(X)$ denote the power set of $X$ because for each possible subset we decide if it is in that particular subset.






                share|cite|improve this answer














                Yes, you have answered the question correctly.



                In general, $P(X)=2^$ where $P(X)$ denote the power set of $X$ because for each possible subset we decide if it is in that particular subset.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Aug 26 at 14:15

























                answered Aug 26 at 14:02









                Siong Thye Goh

                80.7k1453102




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