If I convert 10 V, 1 ampere to 5 V, do I get 5 V 2 ampere?
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I know the current in the circuit is the same.
And also,
Power = 10* 1 = 10 watts.
So,
10 = 5 V * (x) ampere,
X = 10/5,
X = 2 ampere,
With some loss while using a voltage regulator, I will get some loss in current also ... That's not a problem. All I need is: if I reduce the voltage, do I get the same 5 V 2 ampere?
voltage current transformer ampere-hour
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
asked Aug 30 at 4:06
praveen kumar
93
add a comment |Â
up vote
0
down vote
favorite
I know the current in the circuit is the same.
And also,
Power = 10* 1 = 10 watts.
So,
10 = 5 V * (x) ampere,
X = 10/5,
X = 2 ampere,
With some loss while using a voltage regulator, I will get some loss in current also ... That's not a problem. All I need is: if I reduce the voltage, do I get the same 5 V 2 ampere?
voltage current transformer ampere-hour
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
asked Aug 30 at 4:06
praveen kumar
93
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I know the current in the circuit is the same.
And also,
Power = 10* 1 = 10 watts.
So,
10 = 5 V * (x) ampere,
X = 10/5,
X = 2 ampere,
With some loss while using a voltage regulator, I will get some loss in current also ... That's not a problem. All I need is: if I reduce the voltage, do I get the same 5 V 2 ampere?
voltage current transformer ampere-hour
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
asked Aug 30 at 4:06
praveen kumar
93
I know the current in the circuit is the same.
And also,
Power = 10* 1 = 10 watts.
So,
10 = 5 V * (x) ampere,
X = 10/5,
X = 2 ampere,
With some loss while using a voltage regulator, I will get some loss in current also ... That's not a problem. All I need is: if I reduce the voltage, do I get the same 5 V 2 ampere?
voltage current transformer ampere-hour
voltage current transformer ampere-hour
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
asked Aug 30 at 4:06
praveen kumar
93
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
asked Aug 30 at 4:06
praveen kumar
93
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
edited Aug 30 at 14:04
Dave Tweed♦
108k9129231
108k9129231
asked Aug 30 at 4:06
praveen kumar
93
asked Aug 30 at 4:06
praveen kumar
93
asked Aug 30 at 4:06
praveen kumar
93
93
add a comment |Â
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
11
down vote
accepted
If you use a linear regulator, no. You get 5 V, 1 A.
If you use a buck converter, not quite. The converter is not 100% efficient. Maybe you get 8.5 or 9 W out, so 5 V, 1.7 or 1.8 A.
answered Aug 30 at 4:16
The Photon
79.5k394187
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
1
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
add a comment |Â
up vote
1
down vote
The short answer is yes, if you use the right type of converter, there is conservation of power between input and output. You cannot assume there will be no inefficiency, so output power = E * input power, where the efficiency is between 0.5 and 0.95, unless you've chosen the wrong converter for the job.
A transformer (for AC) or a buck converter (for DC) can step down voltage and increase available output current. A good efficiency to aim for is 0.8 or 0.85, and it will depend on the parts you choose. Converter chips are often flexible in what input and/or output voltages they can handle, as well as the max current. But they are targeted at a certain input and output, and they will be less efficient the further you deviate from this. Also, some chips will be made for a fixed output (e.g., always 5 V output), and others will need to be tuned based on which external components you attach. But I think all chips will need some external components added, if you plan to switch such a high current.
Don't go for "linear" converters, because they bleed off excess voltage (thus, power as well) as heat rather than converting it.
answered Aug 30 at 4:17
piojo
39339
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
11
down vote
accepted
If you use a linear regulator, no. You get 5 V, 1 A.
If you use a buck converter, not quite. The converter is not 100% efficient. Maybe you get 8.5 or 9 W out, so 5 V, 1.7 or 1.8 A.
answered Aug 30 at 4:16
The Photon
79.5k394187
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
1
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
add a comment |Â
up vote
11
down vote
accepted
If you use a linear regulator, no. You get 5 V, 1 A.
If you use a buck converter, not quite. The converter is not 100% efficient. Maybe you get 8.5 or 9 W out, so 5 V, 1.7 or 1.8 A.
answered Aug 30 at 4:16
The Photon
79.5k394187
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
1
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
add a comment |Â
up vote
11
down vote
accepted
up vote
11
down vote
accepted
If you use a linear regulator, no. You get 5 V, 1 A.
If you use a buck converter, not quite. The converter is not 100% efficient. Maybe you get 8.5 or 9 W out, so 5 V, 1.7 or 1.8 A.
answered Aug 30 at 4:16
The Photon
79.5k394187
If you use a linear regulator, no. You get 5 V, 1 A.
If you use a buck converter, not quite. The converter is not 100% efficient. Maybe you get 8.5 or 9 W out, so 5 V, 1.7 or 1.8 A.
answered Aug 30 at 4:16
The Photon
79.5k394187
answered Aug 30 at 4:16
The Photon
79.5k394187
answered Aug 30 at 4:16
The Photon
79.5k394187
answered Aug 30 at 4:16
The Photon
79.5k394187
79.5k394187
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
1
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
add a comment |Â
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
1
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
A synchronous converter may get you 95% efficiency, but they often need specific MOSFET's and inductor per given PWM IC.
– Sparky256
Aug 30 at 4:25
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
And that's why I gave you a +1.
– Sparky256
Aug 30 at 4:36
1
1
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
Essentially you get 5V and (2 * (convertor_efficiency/100)) A.
– TomáÅ¡ Zato
Aug 30 at 9:03
add a comment |Â
up vote
1
down vote
The short answer is yes, if you use the right type of converter, there is conservation of power between input and output. You cannot assume there will be no inefficiency, so output power = E * input power, where the efficiency is between 0.5 and 0.95, unless you've chosen the wrong converter for the job.
A transformer (for AC) or a buck converter (for DC) can step down voltage and increase available output current. A good efficiency to aim for is 0.8 or 0.85, and it will depend on the parts you choose. Converter chips are often flexible in what input and/or output voltages they can handle, as well as the max current. But they are targeted at a certain input and output, and they will be less efficient the further you deviate from this. Also, some chips will be made for a fixed output (e.g., always 5 V output), and others will need to be tuned based on which external components you attach. But I think all chips will need some external components added, if you plan to switch such a high current.
Don't go for "linear" converters, because they bleed off excess voltage (thus, power as well) as heat rather than converting it.
answered Aug 30 at 4:17
piojo
39339
add a comment |Â
up vote
1
down vote
The short answer is yes, if you use the right type of converter, there is conservation of power between input and output. You cannot assume there will be no inefficiency, so output power = E * input power, where the efficiency is between 0.5 and 0.95, unless you've chosen the wrong converter for the job.
A transformer (for AC) or a buck converter (for DC) can step down voltage and increase available output current. A good efficiency to aim for is 0.8 or 0.85, and it will depend on the parts you choose. Converter chips are often flexible in what input and/or output voltages they can handle, as well as the max current. But they are targeted at a certain input and output, and they will be less efficient the further you deviate from this. Also, some chips will be made for a fixed output (e.g., always 5 V output), and others will need to be tuned based on which external components you attach. But I think all chips will need some external components added, if you plan to switch such a high current.
Don't go for "linear" converters, because they bleed off excess voltage (thus, power as well) as heat rather than converting it.
answered Aug 30 at 4:17
piojo
39339
add a comment |Â
up vote
1
down vote
up vote
1
down vote
The short answer is yes, if you use the right type of converter, there is conservation of power between input and output. You cannot assume there will be no inefficiency, so output power = E * input power, where the efficiency is between 0.5 and 0.95, unless you've chosen the wrong converter for the job.
A transformer (for AC) or a buck converter (for DC) can step down voltage and increase available output current. A good efficiency to aim for is 0.8 or 0.85, and it will depend on the parts you choose. Converter chips are often flexible in what input and/or output voltages they can handle, as well as the max current. But they are targeted at a certain input and output, and they will be less efficient the further you deviate from this. Also, some chips will be made for a fixed output (e.g., always 5 V output), and others will need to be tuned based on which external components you attach. But I think all chips will need some external components added, if you plan to switch such a high current.
Don't go for "linear" converters, because they bleed off excess voltage (thus, power as well) as heat rather than converting it.
answered Aug 30 at 4:17
piojo
39339
The short answer is yes, if you use the right type of converter, there is conservation of power between input and output. You cannot assume there will be no inefficiency, so output power = E * input power, where the efficiency is between 0.5 and 0.95, unless you've chosen the wrong converter for the job.
A transformer (for AC) or a buck converter (for DC) can step down voltage and increase available output current. A good efficiency to aim for is 0.8 or 0.85, and it will depend on the parts you choose. Converter chips are often flexible in what input and/or output voltages they can handle, as well as the max current. But they are targeted at a certain input and output, and they will be less efficient the further you deviate from this. Also, some chips will be made for a fixed output (e.g., always 5 V output), and others will need to be tuned based on which external components you attach. But I think all chips will need some external components added, if you plan to switch such a high current.
Don't go for "linear" converters, because they bleed off excess voltage (thus, power as well) as heat rather than converting it.
answered Aug 30 at 4:17
piojo
39339
edited Aug 30 at 8:47
answered Aug 30 at 4:17
piojo
39339
answered Aug 30 at 4:17
piojo
39339
answered Aug 30 at 4:17
piojo
39339
39339
add a comment |Â
add a comment |Â
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