Determining the number of critical points of a PDE.

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Problem:



Consider the BVP:
beginequation
labeleq1
begincases
fracpartial^2Psipartialrho^2 + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)fracpartialPsipartialrho+frac1+h^2rho^2rho^2fracpartial^2Psipartialzeta^2 = frac-2hF_01+h^2rho^2,, & texton Omega,,\
Psi(rho,zeta) = 0,, & texton partialOmega,.
endcases
endequation
where $Omega$ is the ellipse $(x,y)inmathbbR^2mid (x-R_0)^2/a^2 + y^2/b^2leq 1$ with $R_0-a>0$ and $rho,zeta$ are polar coordinates. I am trying to determine the number of critical points the solution to the above equation has, and the nature of these critical points.
$$Omega$$



My Attempts:



Numerical Solutions using Mathematica:



The numerical solution to the PDE using NDSolveValue has a single critical point on the line $zeta= 0$. Moreover, along this line we find that $fracpartialPsipartialrho$ seems to be monotonically decreasing. Another point to note is that as $b/a$ increases past $1$, the location of the critical point shifts to the right of $R_0$. Shown below is the solution for $a=1,b=3$.



enter image description here



Analysis



The above question is equivalent to finding the zeroes of $Y =(fracpartialPsipartialrho,fracpartialPsipartialzeta)= (Y_1,Y_2)$ satisfying
beginequation
labeleq2
left[left(fracpartialpartialrho,frac1+h^2rho^2rho^2fracpartialpartialzetaright) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)left(1,0right)right]cdotleft(Y_1,Y_2right) = frac-2hF_01+h^2rho^2
endequation



By the symmetry of the PDE, we have that $Psi(rho, -zeta) = Psi(rho,zeta)$. Thus $Y_2(rho, -zeta) = -Y_2(rho, zeta)$ so $Y_2(rho,0) = 0$. The boundary condition $Psi = 0$ on $partialOmega$ implies that $nablaPsi$ points inwards on the boundary, so $Y_1(R_0-a,0)$ and $Y_1(R_0+a,0)$ are both non-zero and have opposite sign. Therefore at some point on the line $zeta=0$ we have $Y_1(rho,zeta)=0$ and so there is at least one critical point on the line $zeta = 0$.



Looking for solutions along $zeta=0$



points along $zeta = 0$:}
Along $zeta=0$, we can consider $Y_1$ as a function of only $rho$. So the above equation becomes
$$
Y_1'(rho) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)Y_1(rho) = frac-2hF_01+h^2rho^2 - frac1+h^2rho^2rho^2fracpartial Y_2partialzeta(rho,0)
$$
which implies,
$$
(IY_1)' = frac-2hrho F_0(1+h^2rho^2)^2 - frac1rhofracpartial Y_2partialzeta(rho,0)
$$
where $I = expleft(int_1^rhofrac1rholeft(frac1-h^2rho^21+h^2rho^2right),dsright) = fracrho1+h^2rho^2$. Since our numerical results suggest that $Y_1$ is monotonically decreasing, one approach would be to show that $(IY_1)' < 0$ everywhere on $zeta=0$. Unfortunately, $fracpartial Y_2partialzeta(rho,0)$ depends on boundary information not just on the line $zeta = 0$.



Does anyone have any advice for how I can further approach this problem?










share|cite|improve this question

























    up vote
    2
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    Problem:



    Consider the BVP:
    beginequation
    labeleq1
    begincases
    fracpartial^2Psipartialrho^2 + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)fracpartialPsipartialrho+frac1+h^2rho^2rho^2fracpartial^2Psipartialzeta^2 = frac-2hF_01+h^2rho^2,, & texton Omega,,\
    Psi(rho,zeta) = 0,, & texton partialOmega,.
    endcases
    endequation
    where $Omega$ is the ellipse $(x,y)inmathbbR^2mid (x-R_0)^2/a^2 + y^2/b^2leq 1$ with $R_0-a>0$ and $rho,zeta$ are polar coordinates. I am trying to determine the number of critical points the solution to the above equation has, and the nature of these critical points.
    $$Omega$$



    My Attempts:



    Numerical Solutions using Mathematica:



    The numerical solution to the PDE using NDSolveValue has a single critical point on the line $zeta= 0$. Moreover, along this line we find that $fracpartialPsipartialrho$ seems to be monotonically decreasing. Another point to note is that as $b/a$ increases past $1$, the location of the critical point shifts to the right of $R_0$. Shown below is the solution for $a=1,b=3$.



    enter image description here



    Analysis



    The above question is equivalent to finding the zeroes of $Y =(fracpartialPsipartialrho,fracpartialPsipartialzeta)= (Y_1,Y_2)$ satisfying
    beginequation
    labeleq2
    left[left(fracpartialpartialrho,frac1+h^2rho^2rho^2fracpartialpartialzetaright) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)left(1,0right)right]cdotleft(Y_1,Y_2right) = frac-2hF_01+h^2rho^2
    endequation



    By the symmetry of the PDE, we have that $Psi(rho, -zeta) = Psi(rho,zeta)$. Thus $Y_2(rho, -zeta) = -Y_2(rho, zeta)$ so $Y_2(rho,0) = 0$. The boundary condition $Psi = 0$ on $partialOmega$ implies that $nablaPsi$ points inwards on the boundary, so $Y_1(R_0-a,0)$ and $Y_1(R_0+a,0)$ are both non-zero and have opposite sign. Therefore at some point on the line $zeta=0$ we have $Y_1(rho,zeta)=0$ and so there is at least one critical point on the line $zeta = 0$.



    Looking for solutions along $zeta=0$



    points along $zeta = 0$:}
    Along $zeta=0$, we can consider $Y_1$ as a function of only $rho$. So the above equation becomes
    $$
    Y_1'(rho) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)Y_1(rho) = frac-2hF_01+h^2rho^2 - frac1+h^2rho^2rho^2fracpartial Y_2partialzeta(rho,0)
    $$
    which implies,
    $$
    (IY_1)' = frac-2hrho F_0(1+h^2rho^2)^2 - frac1rhofracpartial Y_2partialzeta(rho,0)
    $$
    where $I = expleft(int_1^rhofrac1rholeft(frac1-h^2rho^21+h^2rho^2right),dsright) = fracrho1+h^2rho^2$. Since our numerical results suggest that $Y_1$ is monotonically decreasing, one approach would be to show that $(IY_1)' < 0$ everywhere on $zeta=0$. Unfortunately, $fracpartial Y_2partialzeta(rho,0)$ depends on boundary information not just on the line $zeta = 0$.



    Does anyone have any advice for how I can further approach this problem?










    share|cite|improve this question























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      Problem:



      Consider the BVP:
      beginequation
      labeleq1
      begincases
      fracpartial^2Psipartialrho^2 + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)fracpartialPsipartialrho+frac1+h^2rho^2rho^2fracpartial^2Psipartialzeta^2 = frac-2hF_01+h^2rho^2,, & texton Omega,,\
      Psi(rho,zeta) = 0,, & texton partialOmega,.
      endcases
      endequation
      where $Omega$ is the ellipse $(x,y)inmathbbR^2mid (x-R_0)^2/a^2 + y^2/b^2leq 1$ with $R_0-a>0$ and $rho,zeta$ are polar coordinates. I am trying to determine the number of critical points the solution to the above equation has, and the nature of these critical points.
      $$Omega$$



      My Attempts:



      Numerical Solutions using Mathematica:



      The numerical solution to the PDE using NDSolveValue has a single critical point on the line $zeta= 0$. Moreover, along this line we find that $fracpartialPsipartialrho$ seems to be monotonically decreasing. Another point to note is that as $b/a$ increases past $1$, the location of the critical point shifts to the right of $R_0$. Shown below is the solution for $a=1,b=3$.



      enter image description here



      Analysis



      The above question is equivalent to finding the zeroes of $Y =(fracpartialPsipartialrho,fracpartialPsipartialzeta)= (Y_1,Y_2)$ satisfying
      beginequation
      labeleq2
      left[left(fracpartialpartialrho,frac1+h^2rho^2rho^2fracpartialpartialzetaright) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)left(1,0right)right]cdotleft(Y_1,Y_2right) = frac-2hF_01+h^2rho^2
      endequation



      By the symmetry of the PDE, we have that $Psi(rho, -zeta) = Psi(rho,zeta)$. Thus $Y_2(rho, -zeta) = -Y_2(rho, zeta)$ so $Y_2(rho,0) = 0$. The boundary condition $Psi = 0$ on $partialOmega$ implies that $nablaPsi$ points inwards on the boundary, so $Y_1(R_0-a,0)$ and $Y_1(R_0+a,0)$ are both non-zero and have opposite sign. Therefore at some point on the line $zeta=0$ we have $Y_1(rho,zeta)=0$ and so there is at least one critical point on the line $zeta = 0$.



      Looking for solutions along $zeta=0$



      points along $zeta = 0$:}
      Along $zeta=0$, we can consider $Y_1$ as a function of only $rho$. So the above equation becomes
      $$
      Y_1'(rho) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)Y_1(rho) = frac-2hF_01+h^2rho^2 - frac1+h^2rho^2rho^2fracpartial Y_2partialzeta(rho,0)
      $$
      which implies,
      $$
      (IY_1)' = frac-2hrho F_0(1+h^2rho^2)^2 - frac1rhofracpartial Y_2partialzeta(rho,0)
      $$
      where $I = expleft(int_1^rhofrac1rholeft(frac1-h^2rho^21+h^2rho^2right),dsright) = fracrho1+h^2rho^2$. Since our numerical results suggest that $Y_1$ is monotonically decreasing, one approach would be to show that $(IY_1)' < 0$ everywhere on $zeta=0$. Unfortunately, $fracpartial Y_2partialzeta(rho,0)$ depends on boundary information not just on the line $zeta = 0$.



      Does anyone have any advice for how I can further approach this problem?










      share|cite|improve this question













      Problem:



      Consider the BVP:
      beginequation
      labeleq1
      begincases
      fracpartial^2Psipartialrho^2 + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)fracpartialPsipartialrho+frac1+h^2rho^2rho^2fracpartial^2Psipartialzeta^2 = frac-2hF_01+h^2rho^2,, & texton Omega,,\
      Psi(rho,zeta) = 0,, & texton partialOmega,.
      endcases
      endequation
      where $Omega$ is the ellipse $(x,y)inmathbbR^2mid (x-R_0)^2/a^2 + y^2/b^2leq 1$ with $R_0-a>0$ and $rho,zeta$ are polar coordinates. I am trying to determine the number of critical points the solution to the above equation has, and the nature of these critical points.
      $$Omega$$



      My Attempts:



      Numerical Solutions using Mathematica:



      The numerical solution to the PDE using NDSolveValue has a single critical point on the line $zeta= 0$. Moreover, along this line we find that $fracpartialPsipartialrho$ seems to be monotonically decreasing. Another point to note is that as $b/a$ increases past $1$, the location of the critical point shifts to the right of $R_0$. Shown below is the solution for $a=1,b=3$.



      enter image description here



      Analysis



      The above question is equivalent to finding the zeroes of $Y =(fracpartialPsipartialrho,fracpartialPsipartialzeta)= (Y_1,Y_2)$ satisfying
      beginequation
      labeleq2
      left[left(fracpartialpartialrho,frac1+h^2rho^2rho^2fracpartialpartialzetaright) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)left(1,0right)right]cdotleft(Y_1,Y_2right) = frac-2hF_01+h^2rho^2
      endequation



      By the symmetry of the PDE, we have that $Psi(rho, -zeta) = Psi(rho,zeta)$. Thus $Y_2(rho, -zeta) = -Y_2(rho, zeta)$ so $Y_2(rho,0) = 0$. The boundary condition $Psi = 0$ on $partialOmega$ implies that $nablaPsi$ points inwards on the boundary, so $Y_1(R_0-a,0)$ and $Y_1(R_0+a,0)$ are both non-zero and have opposite sign. Therefore at some point on the line $zeta=0$ we have $Y_1(rho,zeta)=0$ and so there is at least one critical point on the line $zeta = 0$.



      Looking for solutions along $zeta=0$



      points along $zeta = 0$:}
      Along $zeta=0$, we can consider $Y_1$ as a function of only $rho$. So the above equation becomes
      $$
      Y_1'(rho) + frac1rholeft(frac1-h^2rho^21+h^2rho^2right)Y_1(rho) = frac-2hF_01+h^2rho^2 - frac1+h^2rho^2rho^2fracpartial Y_2partialzeta(rho,0)
      $$
      which implies,
      $$
      (IY_1)' = frac-2hrho F_0(1+h^2rho^2)^2 - frac1rhofracpartial Y_2partialzeta(rho,0)
      $$
      where $I = expleft(int_1^rhofrac1rholeft(frac1-h^2rho^21+h^2rho^2right),dsright) = fracrho1+h^2rho^2$. Since our numerical results suggest that $Y_1$ is monotonically decreasing, one approach would be to show that $(IY_1)' < 0$ everywhere on $zeta=0$. Unfortunately, $fracpartial Y_2partialzeta(rho,0)$ depends on boundary information not just on the line $zeta = 0$.



      Does anyone have any advice for how I can further approach this problem?







      analysis multivariable-calculus pde numerical-methods vector-analysis






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      asked Aug 30 at 7:33









      Vishnu M

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