Limit Properties In Calculus

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I am currently learning about limits in Khan academy. I've attached a screenshot below on the section that confuses me:
enter image description here



What confuses me is 3 things:



  1. What does it mean $lim_xto c f(x)+ g(x)$? Does it mean we add the values function f(x) and g(x) at c, and that the $lim_xto c f(x)+ g(x)$ would be L + M?


  2. What does it mean $lim_xto c f(x)$ + $lim_xto c g(x)$ = L+M? I don't understand what this means intuitively at all. How can we just add 2 separate functions? And what would the result be; especially because we aren't adding numbers, but numbers that are getting infinitely close to a number!


  3. What's the difference between $lim_xto c f(x)^r$ and ($lim_xto c fx$)$^r$? Aren't they the same thing? And again, what would the result be? What would a limit to the power r be? I can't make sense of it intuitively. Can someone please explain?







share|cite|improve this question
















  • 2




    It looks like you don't quite understand what the limit is. If limit exists, it is a particular number (or infinity).
    – Vasya
    Aug 21 at 12:41






  • 1




    Limits are numbers! See here, for example: math.stackexchange.com/questions/2491184/…
    – Hans Lundmark
    Aug 21 at 12:43










  • @Vasya Next question though. Why would anyone want to add together, divide, and square functions and limits though? What value would that give us, and what would that value represent?
    – Mathguy
    Aug 21 at 12:46










  • Suppose, $f(x)$ is a logarithmic function and $lim_x rightarrow c f(x)=P$ . Then , $$(lim_x rightarrow c f(x))^r=P^r$$ And... $$lim_x rightarrow c f(x)^r =Pr$$ (Taking r as a constant in both cases...)
    – Entrepreneur
    Aug 21 at 12:54











  • @Mathguy: You need to read about operations on functions. Functions can be added, subtracted, multiplied, just like numbers. Consider function $h(x)=f(x)+g(x)$.
    – Vasya
    Aug 21 at 12:54














up vote
1
down vote

favorite
1












I am currently learning about limits in Khan academy. I've attached a screenshot below on the section that confuses me:
enter image description here



What confuses me is 3 things:



  1. What does it mean $lim_xto c f(x)+ g(x)$? Does it mean we add the values function f(x) and g(x) at c, and that the $lim_xto c f(x)+ g(x)$ would be L + M?


  2. What does it mean $lim_xto c f(x)$ + $lim_xto c g(x)$ = L+M? I don't understand what this means intuitively at all. How can we just add 2 separate functions? And what would the result be; especially because we aren't adding numbers, but numbers that are getting infinitely close to a number!


  3. What's the difference between $lim_xto c f(x)^r$ and ($lim_xto c fx$)$^r$? Aren't they the same thing? And again, what would the result be? What would a limit to the power r be? I can't make sense of it intuitively. Can someone please explain?







share|cite|improve this question
















  • 2




    It looks like you don't quite understand what the limit is. If limit exists, it is a particular number (or infinity).
    – Vasya
    Aug 21 at 12:41






  • 1




    Limits are numbers! See here, for example: math.stackexchange.com/questions/2491184/…
    – Hans Lundmark
    Aug 21 at 12:43










  • @Vasya Next question though. Why would anyone want to add together, divide, and square functions and limits though? What value would that give us, and what would that value represent?
    – Mathguy
    Aug 21 at 12:46










  • Suppose, $f(x)$ is a logarithmic function and $lim_x rightarrow c f(x)=P$ . Then , $$(lim_x rightarrow c f(x))^r=P^r$$ And... $$lim_x rightarrow c f(x)^r =Pr$$ (Taking r as a constant in both cases...)
    – Entrepreneur
    Aug 21 at 12:54











  • @Mathguy: You need to read about operations on functions. Functions can be added, subtracted, multiplied, just like numbers. Consider function $h(x)=f(x)+g(x)$.
    – Vasya
    Aug 21 at 12:54












up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





I am currently learning about limits in Khan academy. I've attached a screenshot below on the section that confuses me:
enter image description here



What confuses me is 3 things:



  1. What does it mean $lim_xto c f(x)+ g(x)$? Does it mean we add the values function f(x) and g(x) at c, and that the $lim_xto c f(x)+ g(x)$ would be L + M?


  2. What does it mean $lim_xto c f(x)$ + $lim_xto c g(x)$ = L+M? I don't understand what this means intuitively at all. How can we just add 2 separate functions? And what would the result be; especially because we aren't adding numbers, but numbers that are getting infinitely close to a number!


  3. What's the difference between $lim_xto c f(x)^r$ and ($lim_xto c fx$)$^r$? Aren't they the same thing? And again, what would the result be? What would a limit to the power r be? I can't make sense of it intuitively. Can someone please explain?







share|cite|improve this question












I am currently learning about limits in Khan academy. I've attached a screenshot below on the section that confuses me:
enter image description here



What confuses me is 3 things:



  1. What does it mean $lim_xto c f(x)+ g(x)$? Does it mean we add the values function f(x) and g(x) at c, and that the $lim_xto c f(x)+ g(x)$ would be L + M?


  2. What does it mean $lim_xto c f(x)$ + $lim_xto c g(x)$ = L+M? I don't understand what this means intuitively at all. How can we just add 2 separate functions? And what would the result be; especially because we aren't adding numbers, but numbers that are getting infinitely close to a number!


  3. What's the difference between $lim_xto c f(x)^r$ and ($lim_xto c fx$)$^r$? Aren't they the same thing? And again, what would the result be? What would a limit to the power r be? I can't make sense of it intuitively. Can someone please explain?









share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Aug 21 at 12:33









Mathguy

1168




1168







  • 2




    It looks like you don't quite understand what the limit is. If limit exists, it is a particular number (or infinity).
    – Vasya
    Aug 21 at 12:41






  • 1




    Limits are numbers! See here, for example: math.stackexchange.com/questions/2491184/…
    – Hans Lundmark
    Aug 21 at 12:43










  • @Vasya Next question though. Why would anyone want to add together, divide, and square functions and limits though? What value would that give us, and what would that value represent?
    – Mathguy
    Aug 21 at 12:46










  • Suppose, $f(x)$ is a logarithmic function and $lim_x rightarrow c f(x)=P$ . Then , $$(lim_x rightarrow c f(x))^r=P^r$$ And... $$lim_x rightarrow c f(x)^r =Pr$$ (Taking r as a constant in both cases...)
    – Entrepreneur
    Aug 21 at 12:54











  • @Mathguy: You need to read about operations on functions. Functions can be added, subtracted, multiplied, just like numbers. Consider function $h(x)=f(x)+g(x)$.
    – Vasya
    Aug 21 at 12:54












  • 2




    It looks like you don't quite understand what the limit is. If limit exists, it is a particular number (or infinity).
    – Vasya
    Aug 21 at 12:41






  • 1




    Limits are numbers! See here, for example: math.stackexchange.com/questions/2491184/…
    – Hans Lundmark
    Aug 21 at 12:43










  • @Vasya Next question though. Why would anyone want to add together, divide, and square functions and limits though? What value would that give us, and what would that value represent?
    – Mathguy
    Aug 21 at 12:46










  • Suppose, $f(x)$ is a logarithmic function and $lim_x rightarrow c f(x)=P$ . Then , $$(lim_x rightarrow c f(x))^r=P^r$$ And... $$lim_x rightarrow c f(x)^r =Pr$$ (Taking r as a constant in both cases...)
    – Entrepreneur
    Aug 21 at 12:54











  • @Mathguy: You need to read about operations on functions. Functions can be added, subtracted, multiplied, just like numbers. Consider function $h(x)=f(x)+g(x)$.
    – Vasya
    Aug 21 at 12:54







2




2




It looks like you don't quite understand what the limit is. If limit exists, it is a particular number (or infinity).
– Vasya
Aug 21 at 12:41




It looks like you don't quite understand what the limit is. If limit exists, it is a particular number (or infinity).
– Vasya
Aug 21 at 12:41




1




1




Limits are numbers! See here, for example: math.stackexchange.com/questions/2491184/…
– Hans Lundmark
Aug 21 at 12:43




Limits are numbers! See here, for example: math.stackexchange.com/questions/2491184/…
– Hans Lundmark
Aug 21 at 12:43












@Vasya Next question though. Why would anyone want to add together, divide, and square functions and limits though? What value would that give us, and what would that value represent?
– Mathguy
Aug 21 at 12:46




@Vasya Next question though. Why would anyone want to add together, divide, and square functions and limits though? What value would that give us, and what would that value represent?
– Mathguy
Aug 21 at 12:46












Suppose, $f(x)$ is a logarithmic function and $lim_x rightarrow c f(x)=P$ . Then , $$(lim_x rightarrow c f(x))^r=P^r$$ And... $$lim_x rightarrow c f(x)^r =Pr$$ (Taking r as a constant in both cases...)
– Entrepreneur
Aug 21 at 12:54





Suppose, $f(x)$ is a logarithmic function and $lim_x rightarrow c f(x)=P$ . Then , $$(lim_x rightarrow c f(x))^r=P^r$$ And... $$lim_x rightarrow c f(x)^r =Pr$$ (Taking r as a constant in both cases...)
– Entrepreneur
Aug 21 at 12:54













@Mathguy: You need to read about operations on functions. Functions can be added, subtracted, multiplied, just like numbers. Consider function $h(x)=f(x)+g(x)$.
– Vasya
Aug 21 at 12:54




@Mathguy: You need to read about operations on functions. Functions can be added, subtracted, multiplied, just like numbers. Consider function $h(x)=f(x)+g(x)$.
– Vasya
Aug 21 at 12:54










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










Functions can be combined using algebra, creating new functions.




How can we just add 2 separate functions?




If $f$ and $g$ are functions, we can create a new function $h$ by the rule $h(x) = f(x)+g(x)$. We might call this new function $f+g$.



[Note: Before we evaluate $f(x)$ and $g(x)$, we do have to assume that $x$ is in both the domain of $f$ and that of $g$. But I won't dwell on that because I don't think it's what you're confused about.]



A natural question is: If $f$ and $g$ each have a limit at a point $c$, does $h$? And would that limit depend on the limits of $f$ and $g$?



If you have an intuitive understanding of limit, you can work through this: If values of $f$ are close to $3$ (for instance), and values of $g$ are close to $7$, then values of $h$ ought to be close to $10$. To be a bit more precise, if values of $f$ can be made arbitrarily close to $L$ by taking $x$ sufficiently close to $c$, and values of $g$ can be mare arbitrarily close to $M$ by taking $x$ sufficiently close to $c$, then values of $h$ can be made arbitrarily close to $L+M$ by taking $x$ sufficiently close to $c$.



What this means is: If $lim_xto c f(x) = L$ and $lim_xto c g(x) = M$, then $lim_xto c h(x) = L+M$. Now if we just replace $h$ with $f+g$, we get
$$
lim_xto c(f(x)+g(x)) = lim_xto c f(x) + lim_xto c g(x)
$$
In other words, the limit of a sum of functions is the sum of the limits of those functions, provided the limits of the individual functions exist.



Similarly, we can create new functions from old by subtraction, multiplication, division, and exponentiation. The limit laws show that (with a few exceptions, like you can't divide by zero), limits play nicely with algebra.




Why would anyone want to add together, divide, and square functions and limits though?




Fair question. Many, many functions can be expressed in terms of a few basic functions and these limit laws. For instance, think about these two basic limit statements.

beginalign*
lim_xto c x &= c \
lim_xto c 1 &= 1
endalign*



Now what is $lim_xto 3(x^2-7)$? Using the limit laws, we can say:
beginalign*
lim_xto3(x^2-7)
&= lim_xto 3(x^2+(-7))
\&= lim_xto 3(x^2) + lim_xto 3(-7)
\&= lim_xto 3(xcdot x) + lim_xto 3(-7)cdot 1
\&= left(lim_xto 3 x right)left(lim_xto 3 x right) + (-7)lim_xto 3 1
\&= 3 cdot 3 + (-7)cdot 1 = 2
endalign*
You see how we didn't need anything other than the basic facts about the limits of $x$ and $1$, and the limit laws from the screenshot. And it feels right that the final limit is $(3)^2 - 7$; that is, the value of $f(x) = x^2-7$ at $x=3$. As we sometimes say, “plug in $3$” and you have the limit.



The functions that can be built from $x$, $1$, addition, scaling (multiplying by constants), and multiplication of functions is the set of polynomials. Using arguments generalizing the one above, we can now say that
$$
lim_xto cf(x) = f(c)
$$
when $f$ is any polynomial function. Cool trick!



We can throw in division with a slight caveat. A quotient of polynomials is called a rational function. We have to exclude from the domain of such a function any point which makes the denominator polynomial zero. But otherwise, we can use the limit laws again, and say $lim_xto cf(x) = f(c)$ when $f$ is any rational function and $c$ is in the domain of $f$.



This is a bit of a stretch, but one can argue that the rest of calculus is about limits of functions that can't be determined so easily with these limit laws.






share|cite|improve this answer



























    up vote
    0
    down vote













    $lim_xto c (f(x)+ g(x))$ and $ (lim_xto c f(x)) +(lim_xto c g(x))$ is basically

    the same thing.
    You are not adding 2 functions; but rather adding values of those functions at

    x tending towards c, which will be a number, not a function in x.


    They have mentioned $lim_xto c f(x)$=L and $lim_xto c g(x)$=M

    So, $lim_xto c f(x)+ g(x)$=L+M.

    Next u ask about $lim_xto c f(x)^r$ and $ (lim_xto c f(x)$)$^r$. $This$ is true for the same reason
    "limits are numbers and all operations applicable on numbers hold true for limits as well".






    share|cite|improve this answer




















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      Functions can be combined using algebra, creating new functions.




      How can we just add 2 separate functions?




      If $f$ and $g$ are functions, we can create a new function $h$ by the rule $h(x) = f(x)+g(x)$. We might call this new function $f+g$.



      [Note: Before we evaluate $f(x)$ and $g(x)$, we do have to assume that $x$ is in both the domain of $f$ and that of $g$. But I won't dwell on that because I don't think it's what you're confused about.]



      A natural question is: If $f$ and $g$ each have a limit at a point $c$, does $h$? And would that limit depend on the limits of $f$ and $g$?



      If you have an intuitive understanding of limit, you can work through this: If values of $f$ are close to $3$ (for instance), and values of $g$ are close to $7$, then values of $h$ ought to be close to $10$. To be a bit more precise, if values of $f$ can be made arbitrarily close to $L$ by taking $x$ sufficiently close to $c$, and values of $g$ can be mare arbitrarily close to $M$ by taking $x$ sufficiently close to $c$, then values of $h$ can be made arbitrarily close to $L+M$ by taking $x$ sufficiently close to $c$.



      What this means is: If $lim_xto c f(x) = L$ and $lim_xto c g(x) = M$, then $lim_xto c h(x) = L+M$. Now if we just replace $h$ with $f+g$, we get
      $$
      lim_xto c(f(x)+g(x)) = lim_xto c f(x) + lim_xto c g(x)
      $$
      In other words, the limit of a sum of functions is the sum of the limits of those functions, provided the limits of the individual functions exist.



      Similarly, we can create new functions from old by subtraction, multiplication, division, and exponentiation. The limit laws show that (with a few exceptions, like you can't divide by zero), limits play nicely with algebra.




      Why would anyone want to add together, divide, and square functions and limits though?




      Fair question. Many, many functions can be expressed in terms of a few basic functions and these limit laws. For instance, think about these two basic limit statements.

      beginalign*
      lim_xto c x &= c \
      lim_xto c 1 &= 1
      endalign*



      Now what is $lim_xto 3(x^2-7)$? Using the limit laws, we can say:
      beginalign*
      lim_xto3(x^2-7)
      &= lim_xto 3(x^2+(-7))
      \&= lim_xto 3(x^2) + lim_xto 3(-7)
      \&= lim_xto 3(xcdot x) + lim_xto 3(-7)cdot 1
      \&= left(lim_xto 3 x right)left(lim_xto 3 x right) + (-7)lim_xto 3 1
      \&= 3 cdot 3 + (-7)cdot 1 = 2
      endalign*
      You see how we didn't need anything other than the basic facts about the limits of $x$ and $1$, and the limit laws from the screenshot. And it feels right that the final limit is $(3)^2 - 7$; that is, the value of $f(x) = x^2-7$ at $x=3$. As we sometimes say, “plug in $3$” and you have the limit.



      The functions that can be built from $x$, $1$, addition, scaling (multiplying by constants), and multiplication of functions is the set of polynomials. Using arguments generalizing the one above, we can now say that
      $$
      lim_xto cf(x) = f(c)
      $$
      when $f$ is any polynomial function. Cool trick!



      We can throw in division with a slight caveat. A quotient of polynomials is called a rational function. We have to exclude from the domain of such a function any point which makes the denominator polynomial zero. But otherwise, we can use the limit laws again, and say $lim_xto cf(x) = f(c)$ when $f$ is any rational function and $c$ is in the domain of $f$.



      This is a bit of a stretch, but one can argue that the rest of calculus is about limits of functions that can't be determined so easily with these limit laws.






      share|cite|improve this answer
























        up vote
        3
        down vote



        accepted










        Functions can be combined using algebra, creating new functions.




        How can we just add 2 separate functions?




        If $f$ and $g$ are functions, we can create a new function $h$ by the rule $h(x) = f(x)+g(x)$. We might call this new function $f+g$.



        [Note: Before we evaluate $f(x)$ and $g(x)$, we do have to assume that $x$ is in both the domain of $f$ and that of $g$. But I won't dwell on that because I don't think it's what you're confused about.]



        A natural question is: If $f$ and $g$ each have a limit at a point $c$, does $h$? And would that limit depend on the limits of $f$ and $g$?



        If you have an intuitive understanding of limit, you can work through this: If values of $f$ are close to $3$ (for instance), and values of $g$ are close to $7$, then values of $h$ ought to be close to $10$. To be a bit more precise, if values of $f$ can be made arbitrarily close to $L$ by taking $x$ sufficiently close to $c$, and values of $g$ can be mare arbitrarily close to $M$ by taking $x$ sufficiently close to $c$, then values of $h$ can be made arbitrarily close to $L+M$ by taking $x$ sufficiently close to $c$.



        What this means is: If $lim_xto c f(x) = L$ and $lim_xto c g(x) = M$, then $lim_xto c h(x) = L+M$. Now if we just replace $h$ with $f+g$, we get
        $$
        lim_xto c(f(x)+g(x)) = lim_xto c f(x) + lim_xto c g(x)
        $$
        In other words, the limit of a sum of functions is the sum of the limits of those functions, provided the limits of the individual functions exist.



        Similarly, we can create new functions from old by subtraction, multiplication, division, and exponentiation. The limit laws show that (with a few exceptions, like you can't divide by zero), limits play nicely with algebra.




        Why would anyone want to add together, divide, and square functions and limits though?




        Fair question. Many, many functions can be expressed in terms of a few basic functions and these limit laws. For instance, think about these two basic limit statements.

        beginalign*
        lim_xto c x &= c \
        lim_xto c 1 &= 1
        endalign*



        Now what is $lim_xto 3(x^2-7)$? Using the limit laws, we can say:
        beginalign*
        lim_xto3(x^2-7)
        &= lim_xto 3(x^2+(-7))
        \&= lim_xto 3(x^2) + lim_xto 3(-7)
        \&= lim_xto 3(xcdot x) + lim_xto 3(-7)cdot 1
        \&= left(lim_xto 3 x right)left(lim_xto 3 x right) + (-7)lim_xto 3 1
        \&= 3 cdot 3 + (-7)cdot 1 = 2
        endalign*
        You see how we didn't need anything other than the basic facts about the limits of $x$ and $1$, and the limit laws from the screenshot. And it feels right that the final limit is $(3)^2 - 7$; that is, the value of $f(x) = x^2-7$ at $x=3$. As we sometimes say, “plug in $3$” and you have the limit.



        The functions that can be built from $x$, $1$, addition, scaling (multiplying by constants), and multiplication of functions is the set of polynomials. Using arguments generalizing the one above, we can now say that
        $$
        lim_xto cf(x) = f(c)
        $$
        when $f$ is any polynomial function. Cool trick!



        We can throw in division with a slight caveat. A quotient of polynomials is called a rational function. We have to exclude from the domain of such a function any point which makes the denominator polynomial zero. But otherwise, we can use the limit laws again, and say $lim_xto cf(x) = f(c)$ when $f$ is any rational function and $c$ is in the domain of $f$.



        This is a bit of a stretch, but one can argue that the rest of calculus is about limits of functions that can't be determined so easily with these limit laws.






        share|cite|improve this answer






















          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          Functions can be combined using algebra, creating new functions.




          How can we just add 2 separate functions?




          If $f$ and $g$ are functions, we can create a new function $h$ by the rule $h(x) = f(x)+g(x)$. We might call this new function $f+g$.



          [Note: Before we evaluate $f(x)$ and $g(x)$, we do have to assume that $x$ is in both the domain of $f$ and that of $g$. But I won't dwell on that because I don't think it's what you're confused about.]



          A natural question is: If $f$ and $g$ each have a limit at a point $c$, does $h$? And would that limit depend on the limits of $f$ and $g$?



          If you have an intuitive understanding of limit, you can work through this: If values of $f$ are close to $3$ (for instance), and values of $g$ are close to $7$, then values of $h$ ought to be close to $10$. To be a bit more precise, if values of $f$ can be made arbitrarily close to $L$ by taking $x$ sufficiently close to $c$, and values of $g$ can be mare arbitrarily close to $M$ by taking $x$ sufficiently close to $c$, then values of $h$ can be made arbitrarily close to $L+M$ by taking $x$ sufficiently close to $c$.



          What this means is: If $lim_xto c f(x) = L$ and $lim_xto c g(x) = M$, then $lim_xto c h(x) = L+M$. Now if we just replace $h$ with $f+g$, we get
          $$
          lim_xto c(f(x)+g(x)) = lim_xto c f(x) + lim_xto c g(x)
          $$
          In other words, the limit of a sum of functions is the sum of the limits of those functions, provided the limits of the individual functions exist.



          Similarly, we can create new functions from old by subtraction, multiplication, division, and exponentiation. The limit laws show that (with a few exceptions, like you can't divide by zero), limits play nicely with algebra.




          Why would anyone want to add together, divide, and square functions and limits though?




          Fair question. Many, many functions can be expressed in terms of a few basic functions and these limit laws. For instance, think about these two basic limit statements.

          beginalign*
          lim_xto c x &= c \
          lim_xto c 1 &= 1
          endalign*



          Now what is $lim_xto 3(x^2-7)$? Using the limit laws, we can say:
          beginalign*
          lim_xto3(x^2-7)
          &= lim_xto 3(x^2+(-7))
          \&= lim_xto 3(x^2) + lim_xto 3(-7)
          \&= lim_xto 3(xcdot x) + lim_xto 3(-7)cdot 1
          \&= left(lim_xto 3 x right)left(lim_xto 3 x right) + (-7)lim_xto 3 1
          \&= 3 cdot 3 + (-7)cdot 1 = 2
          endalign*
          You see how we didn't need anything other than the basic facts about the limits of $x$ and $1$, and the limit laws from the screenshot. And it feels right that the final limit is $(3)^2 - 7$; that is, the value of $f(x) = x^2-7$ at $x=3$. As we sometimes say, “plug in $3$” and you have the limit.



          The functions that can be built from $x$, $1$, addition, scaling (multiplying by constants), and multiplication of functions is the set of polynomials. Using arguments generalizing the one above, we can now say that
          $$
          lim_xto cf(x) = f(c)
          $$
          when $f$ is any polynomial function. Cool trick!



          We can throw in division with a slight caveat. A quotient of polynomials is called a rational function. We have to exclude from the domain of such a function any point which makes the denominator polynomial zero. But otherwise, we can use the limit laws again, and say $lim_xto cf(x) = f(c)$ when $f$ is any rational function and $c$ is in the domain of $f$.



          This is a bit of a stretch, but one can argue that the rest of calculus is about limits of functions that can't be determined so easily with these limit laws.






          share|cite|improve this answer












          Functions can be combined using algebra, creating new functions.




          How can we just add 2 separate functions?




          If $f$ and $g$ are functions, we can create a new function $h$ by the rule $h(x) = f(x)+g(x)$. We might call this new function $f+g$.



          [Note: Before we evaluate $f(x)$ and $g(x)$, we do have to assume that $x$ is in both the domain of $f$ and that of $g$. But I won't dwell on that because I don't think it's what you're confused about.]



          A natural question is: If $f$ and $g$ each have a limit at a point $c$, does $h$? And would that limit depend on the limits of $f$ and $g$?



          If you have an intuitive understanding of limit, you can work through this: If values of $f$ are close to $3$ (for instance), and values of $g$ are close to $7$, then values of $h$ ought to be close to $10$. To be a bit more precise, if values of $f$ can be made arbitrarily close to $L$ by taking $x$ sufficiently close to $c$, and values of $g$ can be mare arbitrarily close to $M$ by taking $x$ sufficiently close to $c$, then values of $h$ can be made arbitrarily close to $L+M$ by taking $x$ sufficiently close to $c$.



          What this means is: If $lim_xto c f(x) = L$ and $lim_xto c g(x) = M$, then $lim_xto c h(x) = L+M$. Now if we just replace $h$ with $f+g$, we get
          $$
          lim_xto c(f(x)+g(x)) = lim_xto c f(x) + lim_xto c g(x)
          $$
          In other words, the limit of a sum of functions is the sum of the limits of those functions, provided the limits of the individual functions exist.



          Similarly, we can create new functions from old by subtraction, multiplication, division, and exponentiation. The limit laws show that (with a few exceptions, like you can't divide by zero), limits play nicely with algebra.




          Why would anyone want to add together, divide, and square functions and limits though?




          Fair question. Many, many functions can be expressed in terms of a few basic functions and these limit laws. For instance, think about these two basic limit statements.

          beginalign*
          lim_xto c x &= c \
          lim_xto c 1 &= 1
          endalign*



          Now what is $lim_xto 3(x^2-7)$? Using the limit laws, we can say:
          beginalign*
          lim_xto3(x^2-7)
          &= lim_xto 3(x^2+(-7))
          \&= lim_xto 3(x^2) + lim_xto 3(-7)
          \&= lim_xto 3(xcdot x) + lim_xto 3(-7)cdot 1
          \&= left(lim_xto 3 x right)left(lim_xto 3 x right) + (-7)lim_xto 3 1
          \&= 3 cdot 3 + (-7)cdot 1 = 2
          endalign*
          You see how we didn't need anything other than the basic facts about the limits of $x$ and $1$, and the limit laws from the screenshot. And it feels right that the final limit is $(3)^2 - 7$; that is, the value of $f(x) = x^2-7$ at $x=3$. As we sometimes say, “plug in $3$” and you have the limit.



          The functions that can be built from $x$, $1$, addition, scaling (multiplying by constants), and multiplication of functions is the set of polynomials. Using arguments generalizing the one above, we can now say that
          $$
          lim_xto cf(x) = f(c)
          $$
          when $f$ is any polynomial function. Cool trick!



          We can throw in division with a slight caveat. A quotient of polynomials is called a rational function. We have to exclude from the domain of such a function any point which makes the denominator polynomial zero. But otherwise, we can use the limit laws again, and say $lim_xto cf(x) = f(c)$ when $f$ is any rational function and $c$ is in the domain of $f$.



          This is a bit of a stretch, but one can argue that the rest of calculus is about limits of functions that can't be determined so easily with these limit laws.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Aug 21 at 13:08









          Matthew Leingang

          15.5k12144




          15.5k12144




















              up vote
              0
              down vote













              $lim_xto c (f(x)+ g(x))$ and $ (lim_xto c f(x)) +(lim_xto c g(x))$ is basically

              the same thing.
              You are not adding 2 functions; but rather adding values of those functions at

              x tending towards c, which will be a number, not a function in x.


              They have mentioned $lim_xto c f(x)$=L and $lim_xto c g(x)$=M

              So, $lim_xto c f(x)+ g(x)$=L+M.

              Next u ask about $lim_xto c f(x)^r$ and $ (lim_xto c f(x)$)$^r$. $This$ is true for the same reason
              "limits are numbers and all operations applicable on numbers hold true for limits as well".






              share|cite|improve this answer
























                up vote
                0
                down vote













                $lim_xto c (f(x)+ g(x))$ and $ (lim_xto c f(x)) +(lim_xto c g(x))$ is basically

                the same thing.
                You are not adding 2 functions; but rather adding values of those functions at

                x tending towards c, which will be a number, not a function in x.


                They have mentioned $lim_xto c f(x)$=L and $lim_xto c g(x)$=M

                So, $lim_xto c f(x)+ g(x)$=L+M.

                Next u ask about $lim_xto c f(x)^r$ and $ (lim_xto c f(x)$)$^r$. $This$ is true for the same reason
                "limits are numbers and all operations applicable on numbers hold true for limits as well".






                share|cite|improve this answer






















                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  $lim_xto c (f(x)+ g(x))$ and $ (lim_xto c f(x)) +(lim_xto c g(x))$ is basically

                  the same thing.
                  You are not adding 2 functions; but rather adding values of those functions at

                  x tending towards c, which will be a number, not a function in x.


                  They have mentioned $lim_xto c f(x)$=L and $lim_xto c g(x)$=M

                  So, $lim_xto c f(x)+ g(x)$=L+M.

                  Next u ask about $lim_xto c f(x)^r$ and $ (lim_xto c f(x)$)$^r$. $This$ is true for the same reason
                  "limits are numbers and all operations applicable on numbers hold true for limits as well".






                  share|cite|improve this answer












                  $lim_xto c (f(x)+ g(x))$ and $ (lim_xto c f(x)) +(lim_xto c g(x))$ is basically

                  the same thing.
                  You are not adding 2 functions; but rather adding values of those functions at

                  x tending towards c, which will be a number, not a function in x.


                  They have mentioned $lim_xto c f(x)$=L and $lim_xto c g(x)$=M

                  So, $lim_xto c f(x)+ g(x)$=L+M.

                  Next u ask about $lim_xto c f(x)^r$ and $ (lim_xto c f(x)$)$^r$. $This$ is true for the same reason
                  "limits are numbers and all operations applicable on numbers hold true for limits as well".







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Aug 21 at 12:59









                  Idea

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                  4151816






















                       

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