Proofs for series forms of $operatornameSi(x)$, $operatornameCi(x)$ and $operatornameLi(x)$
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I am studying the book Gamma by Julian Havil and there are three equations below stated without proofs:
beginalign
operatorname Si(x) & = sum_k = 1^infty (-1)^k - 1 fracx^2k - 1(2k-1)(2k-1)!, \[10pt]
operatornameCi(x) & = -gamma - ln x -sum_k=1^infty frac(-x^2)^k(2k)(2k)!, \[10pt]
operatornameLi(x) & = gamma + ln ln x + sum_k=1^infty fracln^r xkk!.
endalign
I couldn't find any proof for the three equations above.
A clear proof for each either in MSE or a book containing them would be much appreciated.
sequences-and-series
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I am studying the book Gamma by Julian Havil and there are three equations below stated without proofs:
beginalign
operatorname Si(x) & = sum_k = 1^infty (-1)^k - 1 fracx^2k - 1(2k-1)(2k-1)!, \[10pt]
operatornameCi(x) & = -gamma - ln x -sum_k=1^infty frac(-x^2)^k(2k)(2k)!, \[10pt]
operatornameLi(x) & = gamma + ln ln x + sum_k=1^infty fracln^r xkk!.
endalign
I couldn't find any proof for the three equations above.
A clear proof for each either in MSE or a book containing them would be much appreciated.
sequences-and-series
add a comment |Â
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am studying the book Gamma by Julian Havil and there are three equations below stated without proofs:
beginalign
operatorname Si(x) & = sum_k = 1^infty (-1)^k - 1 fracx^2k - 1(2k-1)(2k-1)!, \[10pt]
operatornameCi(x) & = -gamma - ln x -sum_k=1^infty frac(-x^2)^k(2k)(2k)!, \[10pt]
operatornameLi(x) & = gamma + ln ln x + sum_k=1^infty fracln^r xkk!.
endalign
I couldn't find any proof for the three equations above.
A clear proof for each either in MSE or a book containing them would be much appreciated.
sequences-and-series
I am studying the book Gamma by Julian Havil and there are three equations below stated without proofs:
beginalign
operatorname Si(x) & = sum_k = 1^infty (-1)^k - 1 fracx^2k - 1(2k-1)(2k-1)!, \[10pt]
operatornameCi(x) & = -gamma - ln x -sum_k=1^infty frac(-x^2)^k(2k)(2k)!, \[10pt]
operatornameLi(x) & = gamma + ln ln x + sum_k=1^infty fracln^r xkk!.
endalign
I couldn't find any proof for the three equations above.
A clear proof for each either in MSE or a book containing them would be much appreciated.
sequences-and-series
edited Aug 29 at 22:16
asked Aug 27 at 0:25
Edi
791829
791829
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1 Answer
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The only book I know of that directly derives these formulae is Theorie Des Integrallogarithmus Und Verwandter Transzendenten by Niels Nielsen. This is a German language book published in 1906. It is freely available online if I remember correctly.
But also note that one can alternatively define
$$operatornameSi(x) = int_0^x fracsintt , textdt$$
so that term-by-term integration of the Taylor series for $sin$ yields
$$operatornameSi(x) = sum_n=1^infty frac(-1)^n-1 x^2n-1(2n-1)(2n-1)!$$
The trickier part is to show that
$$operatornameCi(x) = -int_x^infty fraccos tt , textdt = gamma + log x + int_0^x fraccos t-1t , textdt$$
so that one can integrate term-by-term to arrive at
$$operatornameCi(x) = gamma + log x + sum_n=1^infty frac(-1)^n-1 x^2n2n(2n)!$$
But this is all done in Nielsen using $operatornameLi$.
Edit: I realize this book is not great for self-study, but it is truly a gem and if you are interested in this sort of mathematics it is a great resource.
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
The only book I know of that directly derives these formulae is Theorie Des Integrallogarithmus Und Verwandter Transzendenten by Niels Nielsen. This is a German language book published in 1906. It is freely available online if I remember correctly.
But also note that one can alternatively define
$$operatornameSi(x) = int_0^x fracsintt , textdt$$
so that term-by-term integration of the Taylor series for $sin$ yields
$$operatornameSi(x) = sum_n=1^infty frac(-1)^n-1 x^2n-1(2n-1)(2n-1)!$$
The trickier part is to show that
$$operatornameCi(x) = -int_x^infty fraccos tt , textdt = gamma + log x + int_0^x fraccos t-1t , textdt$$
so that one can integrate term-by-term to arrive at
$$operatornameCi(x) = gamma + log x + sum_n=1^infty frac(-1)^n-1 x^2n2n(2n)!$$
But this is all done in Nielsen using $operatornameLi$.
Edit: I realize this book is not great for self-study, but it is truly a gem and if you are interested in this sort of mathematics it is a great resource.
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
add a comment |Â
up vote
0
down vote
The only book I know of that directly derives these formulae is Theorie Des Integrallogarithmus Und Verwandter Transzendenten by Niels Nielsen. This is a German language book published in 1906. It is freely available online if I remember correctly.
But also note that one can alternatively define
$$operatornameSi(x) = int_0^x fracsintt , textdt$$
so that term-by-term integration of the Taylor series for $sin$ yields
$$operatornameSi(x) = sum_n=1^infty frac(-1)^n-1 x^2n-1(2n-1)(2n-1)!$$
The trickier part is to show that
$$operatornameCi(x) = -int_x^infty fraccos tt , textdt = gamma + log x + int_0^x fraccos t-1t , textdt$$
so that one can integrate term-by-term to arrive at
$$operatornameCi(x) = gamma + log x + sum_n=1^infty frac(-1)^n-1 x^2n2n(2n)!$$
But this is all done in Nielsen using $operatornameLi$.
Edit: I realize this book is not great for self-study, but it is truly a gem and if you are interested in this sort of mathematics it is a great resource.
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
add a comment |Â
up vote
0
down vote
up vote
0
down vote
The only book I know of that directly derives these formulae is Theorie Des Integrallogarithmus Und Verwandter Transzendenten by Niels Nielsen. This is a German language book published in 1906. It is freely available online if I remember correctly.
But also note that one can alternatively define
$$operatornameSi(x) = int_0^x fracsintt , textdt$$
so that term-by-term integration of the Taylor series for $sin$ yields
$$operatornameSi(x) = sum_n=1^infty frac(-1)^n-1 x^2n-1(2n-1)(2n-1)!$$
The trickier part is to show that
$$operatornameCi(x) = -int_x^infty fraccos tt , textdt = gamma + log x + int_0^x fraccos t-1t , textdt$$
so that one can integrate term-by-term to arrive at
$$operatornameCi(x) = gamma + log x + sum_n=1^infty frac(-1)^n-1 x^2n2n(2n)!$$
But this is all done in Nielsen using $operatornameLi$.
Edit: I realize this book is not great for self-study, but it is truly a gem and if you are interested in this sort of mathematics it is a great resource.
The only book I know of that directly derives these formulae is Theorie Des Integrallogarithmus Und Verwandter Transzendenten by Niels Nielsen. This is a German language book published in 1906. It is freely available online if I remember correctly.
But also note that one can alternatively define
$$operatornameSi(x) = int_0^x fracsintt , textdt$$
so that term-by-term integration of the Taylor series for $sin$ yields
$$operatornameSi(x) = sum_n=1^infty frac(-1)^n-1 x^2n-1(2n-1)(2n-1)!$$
The trickier part is to show that
$$operatornameCi(x) = -int_x^infty fraccos tt , textdt = gamma + log x + int_0^x fraccos t-1t , textdt$$
so that one can integrate term-by-term to arrive at
$$operatornameCi(x) = gamma + log x + sum_n=1^infty frac(-1)^n-1 x^2n2n(2n)!$$
But this is all done in Nielsen using $operatornameLi$.
Edit: I realize this book is not great for self-study, but it is truly a gem and if you are interested in this sort of mathematics it is a great resource.
edited Aug 27 at 23:39
Michael Hardy
205k23187464
205k23187464
answered Aug 27 at 2:48
FofX
607416
607416
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
add a comment |Â
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
I don't know German and I couldn't find a pdf of it so I have to buy it I think..
â Edi
Aug 27 at 2:55
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
archive.org/details/theoriedesinteg00nielgoog You can find a pdf here. Also, I dont know German either but I still found it very helpful, it contains a lot of similar material.
â FofX
Aug 27 at 2:59
add a comment |Â
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