write a differential equation $(fracdydt = ay+b)$ whose solutions have the required behavior as t goes to infinity.

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Let all other solutions diverge from $y = frac34$. write a differential equation $(fracdydt = ay +b)$ whose solutions have the required behavior as t goes to infinity. Explain how you came up with the differential equation).



I think the answer is $y' = 4y - 3$ but I am not sure. Can someone help me produce the answer with complete working?










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    Let all other solutions diverge from $y = frac34$. write a differential equation $(fracdydt = ay +b)$ whose solutions have the required behavior as t goes to infinity. Explain how you came up with the differential equation).



    I think the answer is $y' = 4y - 3$ but I am not sure. Can someone help me produce the answer with complete working?










    share|cite|improve this question

























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Let all other solutions diverge from $y = frac34$. write a differential equation $(fracdydt = ay +b)$ whose solutions have the required behavior as t goes to infinity. Explain how you came up with the differential equation).



      I think the answer is $y' = 4y - 3$ but I am not sure. Can someone help me produce the answer with complete working?










      share|cite|improve this question















      Let all other solutions diverge from $y = frac34$. write a differential equation $(fracdydt = ay +b)$ whose solutions have the required behavior as t goes to infinity. Explain how you came up with the differential equation).



      I think the answer is $y' = 4y - 3$ but I am not sure. Can someone help me produce the answer with complete working?







      differential-equations






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      edited Sep 22 '16 at 12:42









      arash javan

      1306




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      asked Sep 22 '16 at 12:07









      Anonymous

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          well i think you are really close to the solution:



          $$y'=-4y-3$$



          Homogeneous part would be:
          $$y'+ 4y = 0$$
          which leads to:
          $$y0=Ce^-4t$$



          particular part would be (with initial assumption $yp=ax+b$):
          $$yp=3/4$$



          which leads to:
          $$y(t)=Ce^-4t+3/4$$



          $$limlimits_t to infty y(t)=3/4$$






          share|cite|improve this answer






















          • Is it y' = -4y - 3 or y' = 4y - 3
            – Anonymous
            Sep 22 '16 at 13:03











          • y'= -4y-3 try to solve some similar equations.
            – arash javan
            Sep 22 '16 at 13:07











          • @Anonymous mark the answer plz, if it was your solution
            – arash javan
            Sep 23 '16 at 14:09










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          up vote
          0
          down vote













          well i think you are really close to the solution:



          $$y'=-4y-3$$



          Homogeneous part would be:
          $$y'+ 4y = 0$$
          which leads to:
          $$y0=Ce^-4t$$



          particular part would be (with initial assumption $yp=ax+b$):
          $$yp=3/4$$



          which leads to:
          $$y(t)=Ce^-4t+3/4$$



          $$limlimits_t to infty y(t)=3/4$$






          share|cite|improve this answer






















          • Is it y' = -4y - 3 or y' = 4y - 3
            – Anonymous
            Sep 22 '16 at 13:03











          • y'= -4y-3 try to solve some similar equations.
            – arash javan
            Sep 22 '16 at 13:07











          • @Anonymous mark the answer plz, if it was your solution
            – arash javan
            Sep 23 '16 at 14:09














          up vote
          0
          down vote













          well i think you are really close to the solution:



          $$y'=-4y-3$$



          Homogeneous part would be:
          $$y'+ 4y = 0$$
          which leads to:
          $$y0=Ce^-4t$$



          particular part would be (with initial assumption $yp=ax+b$):
          $$yp=3/4$$



          which leads to:
          $$y(t)=Ce^-4t+3/4$$



          $$limlimits_t to infty y(t)=3/4$$






          share|cite|improve this answer






















          • Is it y' = -4y - 3 or y' = 4y - 3
            – Anonymous
            Sep 22 '16 at 13:03











          • y'= -4y-3 try to solve some similar equations.
            – arash javan
            Sep 22 '16 at 13:07











          • @Anonymous mark the answer plz, if it was your solution
            – arash javan
            Sep 23 '16 at 14:09












          up vote
          0
          down vote










          up vote
          0
          down vote









          well i think you are really close to the solution:



          $$y'=-4y-3$$



          Homogeneous part would be:
          $$y'+ 4y = 0$$
          which leads to:
          $$y0=Ce^-4t$$



          particular part would be (with initial assumption $yp=ax+b$):
          $$yp=3/4$$



          which leads to:
          $$y(t)=Ce^-4t+3/4$$



          $$limlimits_t to infty y(t)=3/4$$






          share|cite|improve this answer














          well i think you are really close to the solution:



          $$y'=-4y-3$$



          Homogeneous part would be:
          $$y'+ 4y = 0$$
          which leads to:
          $$y0=Ce^-4t$$



          particular part would be (with initial assumption $yp=ax+b$):
          $$yp=3/4$$



          which leads to:
          $$y(t)=Ce^-4t+3/4$$



          $$limlimits_t to infty y(t)=3/4$$







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Sep 22 '16 at 13:00

























          answered Sep 22 '16 at 12:46









          arash javan

          1306




          1306











          • Is it y' = -4y - 3 or y' = 4y - 3
            – Anonymous
            Sep 22 '16 at 13:03











          • y'= -4y-3 try to solve some similar equations.
            – arash javan
            Sep 22 '16 at 13:07











          • @Anonymous mark the answer plz, if it was your solution
            – arash javan
            Sep 23 '16 at 14:09
















          • Is it y' = -4y - 3 or y' = 4y - 3
            – Anonymous
            Sep 22 '16 at 13:03











          • y'= -4y-3 try to solve some similar equations.
            – arash javan
            Sep 22 '16 at 13:07











          • @Anonymous mark the answer plz, if it was your solution
            – arash javan
            Sep 23 '16 at 14:09















          Is it y' = -4y - 3 or y' = 4y - 3
          – Anonymous
          Sep 22 '16 at 13:03





          Is it y' = -4y - 3 or y' = 4y - 3
          – Anonymous
          Sep 22 '16 at 13:03













          y'= -4y-3 try to solve some similar equations.
          – arash javan
          Sep 22 '16 at 13:07





          y'= -4y-3 try to solve some similar equations.
          – arash javan
          Sep 22 '16 at 13:07













          @Anonymous mark the answer plz, if it was your solution
          – arash javan
          Sep 23 '16 at 14:09




          @Anonymous mark the answer plz, if it was your solution
          – arash javan
          Sep 23 '16 at 14:09

















           

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