Python 3.6 Runtime overflow encountered









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0
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This error happens, when I try to run this line in a loop:



sum((X@theta - y)**2)/2/len(X)



After the 5th loop, i start to get the error.




RuntimeWarning: overflow encountered in square



RuntimeWarning: overflow encountered in multiply



RuntimeWarning: overflow encountered in add




What to do, should I round the array or something? How?



If i try round(sum((X@theta - y)**2)/2/len(X),5), i get this error




TypeError: type numpy.ndarray doesn't define __ round__ method







python numpy spyder







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  • Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
    – 9769953
    yesterday










  • A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
    – john doe
    yesterday











  • or total numbers in the matrix is getting large @9769953? I am new to python
    – john doe
    yesterday











  • A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
    – 9769953
    yesterday














up vote
0
down vote

favorite












This error happens, when I try to run this line in a loop:



sum((X@theta - y)**2)/2/len(X)



After the 5th loop, i start to get the error.




RuntimeWarning: overflow encountered in square



RuntimeWarning: overflow encountered in multiply



RuntimeWarning: overflow encountered in add




What to do, should I round the array or something? How?



If i try round(sum((X@theta - y)**2)/2/len(X),5), i get this error




TypeError: type numpy.ndarray doesn't define __ round__ method







python numpy spyder







share|improve this question







New contributor




john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
    – 9769953
    yesterday










  • A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
    – john doe
    yesterday











  • or total numbers in the matrix is getting large @9769953? I am new to python
    – john doe
    yesterday











  • A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
    – 9769953
    yesterday












up vote
0
down vote

favorite









up vote
0
down vote

favorite











This error happens, when I try to run this line in a loop:



sum((X@theta - y)**2)/2/len(X)



After the 5th loop, i start to get the error.




RuntimeWarning: overflow encountered in square



RuntimeWarning: overflow encountered in multiply



RuntimeWarning: overflow encountered in add




What to do, should I round the array or something? How?



If i try round(sum((X@theta - y)**2)/2/len(X),5), i get this error




TypeError: type numpy.ndarray doesn't define __ round__ method







python numpy spyder







share|improve this question







New contributor




john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











This error happens, when I try to run this line in a loop:



sum((X@theta - y)**2)/2/len(X)



After the 5th loop, i start to get the error.




RuntimeWarning: overflow encountered in square



RuntimeWarning: overflow encountered in multiply



RuntimeWarning: overflow encountered in add




What to do, should I round the array or something? How?



If i try round(sum((X@theta - y)**2)/2/len(X),5), i get this error




TypeError: type numpy.ndarray doesn't define __ round__ method







python numpy spyder




python numpy spyder






share|improve this question







New contributor




john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







New contributor




john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question






New contributor




john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









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New contributor




john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






john doe is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
    – 9769953
    yesterday










  • A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
    – john doe
    yesterday











  • or total numbers in the matrix is getting large @9769953? I am new to python
    – john doe
    yesterday











  • A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
    – 9769953
    yesterday
















  • Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
    – 9769953
    yesterday










  • A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
    – john doe
    yesterday











  • or total numbers in the matrix is getting large @9769953? I am new to python
    – john doe
    yesterday











  • A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
    – 9769953
    yesterday















Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday




Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday












A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday





A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday













or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday





or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday













A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday




A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday

















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