couples complexity theorem states that omega is complex. How? [closed]

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
-1
down vote

favorite
1












couples complexity theorem states that omega is complex. How?




probability-theory




share|cite|improve this question














closed as off-topic by John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy Aug 25 at 11:32


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
















    up vote
    -1
    down vote

    favorite
    1












    couples complexity theorem states that omega is complex. How?




    probability-theory




    share|cite|improve this question














    closed as off-topic by John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy Aug 25 at 11:32


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy
    If this question can be reworded to fit the rules in the help center, please edit the question.














      up vote
      -1
      down vote

      favorite
      1









      up vote
      -1
      down vote

      favorite
      1






      1





      couples complexity theorem states that omega is complex. How?




      probability-theory




      share|cite|improve this question














      couples complexity theorem states that omega is complex. How?





      probability-theory





      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited 2 days ago

























      asked Aug 25 at 2:46









      mathnewbie

      274




      274




      closed as off-topic by John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy Aug 25 at 11:32


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy
      If this question can be reworded to fit the rules in the help center, please edit the question.




      closed as off-topic by John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy Aug 25 at 11:32


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John Ma, Jendrik Stelzner, Brahadeesh, Pierre-Guy Plamondon, amWhy
      If this question can be reworded to fit the rules in the help center, please edit the question.




















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote













          There is no such probability measure.



          More generally, let $S$ be an uncountable sample space, and suppose $P$ is a probability measure such that all singleton subsets of $S$ have positive probability.



          For each integer $k > 1$, let
          $S_k=sin Smid P(s) > largefrac1k$.



          Then $S=displaystylebigcup_k=2^infty S_k$, hence $S_j$ is uncountable, for some $j$.



          In particular, $S_j$ has at least $j$ elements.



          But then, letting $A$ be a subset of $S_j$ with $j$ elements, we get
          $P(A) > (j)bigl(largefrac1jbigr) = 1$, contradiction.



          Thus, if $S$ is an uncountable sample space, there is no probability measure $P$ such that all singleton subsets of $S$ have positive probability.






          share|cite|improve this answer




















          • I have edited the question.
            – mathnewbie
            Aug 25 at 9:56










          • You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
            – quasi
            Aug 25 at 12:44











          • I apologise for the change.
            – mathnewbie
            Aug 25 at 12:46


















          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote













          There is no such probability measure.



          More generally, let $S$ be an uncountable sample space, and suppose $P$ is a probability measure such that all singleton subsets of $S$ have positive probability.



          For each integer $k > 1$, let
          $S_k=sin Smid P(s) > largefrac1k$.



          Then $S=displaystylebigcup_k=2^infty S_k$, hence $S_j$ is uncountable, for some $j$.



          In particular, $S_j$ has at least $j$ elements.



          But then, letting $A$ be a subset of $S_j$ with $j$ elements, we get
          $P(A) > (j)bigl(largefrac1jbigr) = 1$, contradiction.



          Thus, if $S$ is an uncountable sample space, there is no probability measure $P$ such that all singleton subsets of $S$ have positive probability.






          share|cite|improve this answer




















          • I have edited the question.
            – mathnewbie
            Aug 25 at 9:56










          • You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
            – quasi
            Aug 25 at 12:44











          • I apologise for the change.
            – mathnewbie
            Aug 25 at 12:46















          up vote
          0
          down vote













          There is no such probability measure.



          More generally, let $S$ be an uncountable sample space, and suppose $P$ is a probability measure such that all singleton subsets of $S$ have positive probability.



          For each integer $k > 1$, let
          $S_k=sin Smid P(s) > largefrac1k$.



          Then $S=displaystylebigcup_k=2^infty S_k$, hence $S_j$ is uncountable, for some $j$.



          In particular, $S_j$ has at least $j$ elements.



          But then, letting $A$ be a subset of $S_j$ with $j$ elements, we get
          $P(A) > (j)bigl(largefrac1jbigr) = 1$, contradiction.



          Thus, if $S$ is an uncountable sample space, there is no probability measure $P$ such that all singleton subsets of $S$ have positive probability.






          share|cite|improve this answer




















          • I have edited the question.
            – mathnewbie
            Aug 25 at 9:56










          • You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
            – quasi
            Aug 25 at 12:44











          • I apologise for the change.
            – mathnewbie
            Aug 25 at 12:46













          up vote
          0
          down vote










          up vote
          0
          down vote









          There is no such probability measure.



          More generally, let $S$ be an uncountable sample space, and suppose $P$ is a probability measure such that all singleton subsets of $S$ have positive probability.



          For each integer $k > 1$, let
          $S_k=sin Smid P(s) > largefrac1k$.



          Then $S=displaystylebigcup_k=2^infty S_k$, hence $S_j$ is uncountable, for some $j$.



          In particular, $S_j$ has at least $j$ elements.



          But then, letting $A$ be a subset of $S_j$ with $j$ elements, we get
          $P(A) > (j)bigl(largefrac1jbigr) = 1$, contradiction.



          Thus, if $S$ is an uncountable sample space, there is no probability measure $P$ such that all singleton subsets of $S$ have positive probability.






          share|cite|improve this answer












          There is no such probability measure.



          More generally, let $S$ be an uncountable sample space, and suppose $P$ is a probability measure such that all singleton subsets of $S$ have positive probability.



          For each integer $k > 1$, let
          $S_k=sin Smid P(s) > largefrac1k$.



          Then $S=displaystylebigcup_k=2^infty S_k$, hence $S_j$ is uncountable, for some $j$.



          In particular, $S_j$ has at least $j$ elements.



          But then, letting $A$ be a subset of $S_j$ with $j$ elements, we get
          $P(A) > (j)bigl(largefrac1jbigr) = 1$, contradiction.



          Thus, if $S$ is an uncountable sample space, there is no probability measure $P$ such that all singleton subsets of $S$ have positive probability.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Aug 25 at 4:49









          quasi

          33.9k22461




          33.9k22461











          • I have edited the question.
            – mathnewbie
            Aug 25 at 9:56










          • You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
            – quasi
            Aug 25 at 12:44











          • I apologise for the change.
            – mathnewbie
            Aug 25 at 12:46

















          • I have edited the question.
            – mathnewbie
            Aug 25 at 9:56










          • You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
            – quasi
            Aug 25 at 12:44











          • I apologise for the change.
            – mathnewbie
            Aug 25 at 12:46
















          I have edited the question.
          – mathnewbie
          Aug 25 at 9:56




          I have edited the question.
          – mathnewbie
          Aug 25 at 9:56












          You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
          – quasi
          Aug 25 at 12:44





          You totally changed the question. Your previous title and question specified that the sample space was uncountable. My answer relates to that version.
          – quasi
          Aug 25 at 12:44













          I apologise for the change.
          – mathnewbie
          Aug 25 at 12:46





          I apologise for the change.
          – mathnewbie
          Aug 25 at 12:46



          -

          這個網誌中的熱門文章

          Is there any way to eliminate the singular point to solve this integral by hand or by approximations?

          圖片
          Clash Royale CLAN TAG #URR8PPP up vote 0 down vote favorite 1 $$int_0^1 (1+(x^-p-1)^1-p)^frac1pdx, pin mathbbR, pge 1$$ I find that $x=0,1$ are singular points(discontinuous points of this integral), is there a way to eliminate those singular points to make sure that this integral can be calculated by hand or by Taylor approximations. In either cases, what are those steps of calculating the integral? calculus real-analysis analysis approximation share | cite | improve this question edited Sep 11 at 5:07 asked Sep 11 at 4:48 Mclalalala 126 8 1 What is $p$? Please give more information to make it complete. – xbh Sep 11 at 5:02 @xbh already fixed it, thanks for reminding. – Mclalalala Sep 11 at 5:10 Seems that $0$ is not singular here… [I might compute wrong] – xbh Sep 11 at 5:30 @xbh can you show me how to get the close formula for the integral above? – Mclalalala Sep 11 at 5:33
          閱讀完整內容

          Why am i infinitely getting the same tweet with the Twitter Search API?

          圖片
          up vote 0 down vote favorite My code workes perfectly for other queries, but for one query I am infinitely getting the same tweet. I can't understand what the problem is. API call: query='Allergic asthma OR Nonallergic asthma OR Occupational asthma OR EIB OR Exercise-induced bronchoconstriction OR Nocturnal asthma OR Cough-variant asthma' new_tweets = api.search(q=searchQuery, count=100, since_id=since_id, lang='en',tweet_mode='extended') if not new_tweets: print("No more tweets found") break for tweet in new_tweets: if True: print(jsonpickle.encode(tweet._json, unpicklable=False)) my_file = open('searchTweets.txt','a') my_file.write(jsonpickle.encode(tweet._json, unpicklable=False)+'n') my_file.close() else: continue Output in file: https://pastebin.com/JmRCsTeE These are the JSONs of the same Tweet. Other queries that work: Breast cancer OR Prostate cancer OR Colon cancer OR Lung cancer Type 2 dia
          閱讀完整內容

          Carbon dioxide

          圖片
          "CO2" redirects here. For other uses, see CO2 (disambiguation). Carbon dioxide Names Other names Carbonic acid gas Carbonic anhydride Carbonic oxide Carbon oxide Carbon(IV) oxide Dry ice (solid phase) Identifiers CAS Number 124-38-9   Y 3D model (JSmol) Interactive image Interactive image 3DMet B01131 Beilstein Reference 1900390 ChEBI CHEBI:16526   Y ChEMBL ChEMBL1231871   N ChemSpider 274   Y ECHA InfoCard 100.004.271 EC Number 204-696-9 E number E290 (preservatives) Gmelin Reference 989 KEGG D00004   Y MeSH Carbon+dioxide PubChem CID 280 RTECS number FF6400000 UNII 142M471B3J   Y UN number 1013 (gas), 1845 (solid) InChI InChI=1S/CO2/c2-1-3   Y Key: CURLTUGMZLYLDI-UHFFFAOYSA-N   Y InChI=1/CO2/c2-1-3 Key: CURLTUGMZLYLDI-UHFFFAOYAO SMILES O=C=O C(=O)=O Properties Chemical formula C O 2 Molar mass 44.01 g·mol −1 Appearance Colorless gas Odor Low concentrations: none High concentrations: sharp; acidic [1] Density 1562 kg/m 3 (solid at 1 atm and −78.5 °C) 1101 kg/m 3 (liquid at
          閱讀完整內容