Writing the equation $r = theta$ in cartesian cordinates

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Trying to write the cartesian version of the equation $r = theta$ which looks like a spiral when graphed. How is the that going to look?



I have:
$$
sqrtx^2+y^2 = arctanleft( fracyx right)
$$
But this looks nothing like what I expected.



Please explain your reasoning.







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    up vote
    0
    down vote

    favorite












    Trying to write the cartesian version of the equation $r = theta$ which looks like a spiral when graphed. How is the that going to look?



    I have:
    $$
    sqrtx^2+y^2 = arctanleft( fracyx right)
    $$
    But this looks nothing like what I expected.



    Please explain your reasoning.







    share|cite|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Trying to write the cartesian version of the equation $r = theta$ which looks like a spiral when graphed. How is the that going to look?



      I have:
      $$
      sqrtx^2+y^2 = arctanleft( fracyx right)
      $$
      But this looks nothing like what I expected.



      Please explain your reasoning.







      share|cite|improve this question














      Trying to write the cartesian version of the equation $r = theta$ which looks like a spiral when graphed. How is the that going to look?



      I have:
      $$
      sqrtx^2+y^2 = arctanleft( fracyx right)
      $$
      But this looks nothing like what I expected.



      Please explain your reasoning.









      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Aug 27 at 18:58









      Christian Blatter

      165k7109311




      165k7109311










      asked Aug 27 at 0:57









      Ernest Barzaga

      133




      133




















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          This is the picture of $tan(sqrtx^2+y^2)=fracyx$



          enter image description here



          Note that your LHS is always nonnegative.






          share|cite|improve this answer




















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            1 Answer
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            up vote
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            This is the picture of $tan(sqrtx^2+y^2)=fracyx$



            enter image description here



            Note that your LHS is always nonnegative.






            share|cite|improve this answer
























              up vote
              0
              down vote













              This is the picture of $tan(sqrtx^2+y^2)=fracyx$



              enter image description here



              Note that your LHS is always nonnegative.






              share|cite|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                This is the picture of $tan(sqrtx^2+y^2)=fracyx$



                enter image description here



                Note that your LHS is always nonnegative.






                share|cite|improve this answer












                This is the picture of $tan(sqrtx^2+y^2)=fracyx$



                enter image description here



                Note that your LHS is always nonnegative.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Aug 27 at 1:12









                Siong Thye Goh

                80.8k1453102




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