Recurrence Relation, Compound Annually

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If I invest $$2000$/yr in a tax sheltered annuity at $7%$, where $A_n$ is the amount at $n$ years... what is the recurrence relation? I know my initial condition $A_0$ is $2000$. And for some reason the answer I got is $A_n = (1.12)^2 cdot A_0$.



Any help would be appreciated, I’m not sure where I went wrong!










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If I invest $$2000$/yr in a tax sheltered annuity at $7%$, where $A_n$ is the amount at $n$ years... what is the recurrence relation? I know my initial condition $A_0$ is $2000$. And for some reason the answer I got is $A_n = (1.12)^2 cdot A_0$.



Any help would be appreciated, I’m not sure where I went wrong!










share|cite|improve this question























  • Welcome to MathSE. Please read this MathJax tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Sep 10 at 7:39










  • This seems to be a geometric sum.
    – Matti P.
    Sep 10 at 7:58












up vote
0
down vote

favorite









up vote
0
down vote

favorite











If I invest $$2000$/yr in a tax sheltered annuity at $7%$, where $A_n$ is the amount at $n$ years... what is the recurrence relation? I know my initial condition $A_0$ is $2000$. And for some reason the answer I got is $A_n = (1.12)^2 cdot A_0$.



Any help would be appreciated, I’m not sure where I went wrong!










share|cite|improve this question















If I invest $$2000$/yr in a tax sheltered annuity at $7%$, where $A_n$ is the amount at $n$ years... what is the recurrence relation? I know my initial condition $A_0$ is $2000$. And for some reason the answer I got is $A_n = (1.12)^2 cdot A_0$.



Any help would be appreciated, I’m not sure where I went wrong!







discrete-mathematics recurrence-relations computer-science






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edited Sep 10 at 7:38









N. F. Taussig

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asked Sep 10 at 7:20









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  • Welcome to MathSE. Please read this MathJax tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Sep 10 at 7:39










  • This seems to be a geometric sum.
    – Matti P.
    Sep 10 at 7:58
















  • Welcome to MathSE. Please read this MathJax tutorial, which explains how to typeset mathematics on this site.
    – N. F. Taussig
    Sep 10 at 7:39










  • This seems to be a geometric sum.
    – Matti P.
    Sep 10 at 7:58















Welcome to MathSE. Please read this MathJax tutorial, which explains how to typeset mathematics on this site.
– N. F. Taussig
Sep 10 at 7:39




Welcome to MathSE. Please read this MathJax tutorial, which explains how to typeset mathematics on this site.
– N. F. Taussig
Sep 10 at 7:39












This seems to be a geometric sum.
– Matti P.
Sep 10 at 7:58




This seems to be a geometric sum.
– Matti P.
Sep 10 at 7:58










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At the end of the $n$th year, you invest $$2000$ and earn $7%$ interest on what you earned the previous year. Hence,
$$A_n = $2000 + 0.07A_n - 1, n geq 1$$
which is the recurrence relation. The initial value in your account is $A_0 = $2000$.



Let's examine what happens during the first few years.
beginalign*
A_0 & = $2000\
A_1 & = $2000 + 0.07A_0\
& = $2000 + 0.07 cdot $2000\
& = $2000(1 + 0.07)\
A_2 & = $2000 + 0.07A_1\
& = $2000 + 0.07[$2000(1 + 0.07)]\
& = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000\
& = $2000(1 + 0.07 + 0.07^2)\
A_3 & = $2000 + 0.07A_2\
& = $2000 + 0.07[$2000(1 + 0.07 + 0.07^2)]\
& = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000 + 0.07^3 cdot $2000\
& = $2000(1 + 0.07 + 0.07^2 + 0.07^3)
endalign*
which suggests that
$$A_n = $2000(1 + 0.07 + 0.07^2 + 0.07^3 + cdots + 0.07^n) = $2000sum_k = 0^n 0.07^k$$
which you can prove by induction.



As for finding an explicit formula, you can use the geometric series formula
$$A_n = a(1 + r + r^2 + cdots + r^n) = afrac1 - r^n + 11 - r, r neq 1$$
with $a = $2000$ and $r = 0.07$.






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    1 Answer
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    1 Answer
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    At the end of the $n$th year, you invest $$2000$ and earn $7%$ interest on what you earned the previous year. Hence,
    $$A_n = $2000 + 0.07A_n - 1, n geq 1$$
    which is the recurrence relation. The initial value in your account is $A_0 = $2000$.



    Let's examine what happens during the first few years.
    beginalign*
    A_0 & = $2000\
    A_1 & = $2000 + 0.07A_0\
    & = $2000 + 0.07 cdot $2000\
    & = $2000(1 + 0.07)\
    A_2 & = $2000 + 0.07A_1\
    & = $2000 + 0.07[$2000(1 + 0.07)]\
    & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000\
    & = $2000(1 + 0.07 + 0.07^2)\
    A_3 & = $2000 + 0.07A_2\
    & = $2000 + 0.07[$2000(1 + 0.07 + 0.07^2)]\
    & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000 + 0.07^3 cdot $2000\
    & = $2000(1 + 0.07 + 0.07^2 + 0.07^3)
    endalign*
    which suggests that
    $$A_n = $2000(1 + 0.07 + 0.07^2 + 0.07^3 + cdots + 0.07^n) = $2000sum_k = 0^n 0.07^k$$
    which you can prove by induction.



    As for finding an explicit formula, you can use the geometric series formula
    $$A_n = a(1 + r + r^2 + cdots + r^n) = afrac1 - r^n + 11 - r, r neq 1$$
    with $a = $2000$ and $r = 0.07$.






    share|cite|improve this answer


























      up vote
      0
      down vote













      At the end of the $n$th year, you invest $$2000$ and earn $7%$ interest on what you earned the previous year. Hence,
      $$A_n = $2000 + 0.07A_n - 1, n geq 1$$
      which is the recurrence relation. The initial value in your account is $A_0 = $2000$.



      Let's examine what happens during the first few years.
      beginalign*
      A_0 & = $2000\
      A_1 & = $2000 + 0.07A_0\
      & = $2000 + 0.07 cdot $2000\
      & = $2000(1 + 0.07)\
      A_2 & = $2000 + 0.07A_1\
      & = $2000 + 0.07[$2000(1 + 0.07)]\
      & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000\
      & = $2000(1 + 0.07 + 0.07^2)\
      A_3 & = $2000 + 0.07A_2\
      & = $2000 + 0.07[$2000(1 + 0.07 + 0.07^2)]\
      & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000 + 0.07^3 cdot $2000\
      & = $2000(1 + 0.07 + 0.07^2 + 0.07^3)
      endalign*
      which suggests that
      $$A_n = $2000(1 + 0.07 + 0.07^2 + 0.07^3 + cdots + 0.07^n) = $2000sum_k = 0^n 0.07^k$$
      which you can prove by induction.



      As for finding an explicit formula, you can use the geometric series formula
      $$A_n = a(1 + r + r^2 + cdots + r^n) = afrac1 - r^n + 11 - r, r neq 1$$
      with $a = $2000$ and $r = 0.07$.






      share|cite|improve this answer
























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        At the end of the $n$th year, you invest $$2000$ and earn $7%$ interest on what you earned the previous year. Hence,
        $$A_n = $2000 + 0.07A_n - 1, n geq 1$$
        which is the recurrence relation. The initial value in your account is $A_0 = $2000$.



        Let's examine what happens during the first few years.
        beginalign*
        A_0 & = $2000\
        A_1 & = $2000 + 0.07A_0\
        & = $2000 + 0.07 cdot $2000\
        & = $2000(1 + 0.07)\
        A_2 & = $2000 + 0.07A_1\
        & = $2000 + 0.07[$2000(1 + 0.07)]\
        & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000\
        & = $2000(1 + 0.07 + 0.07^2)\
        A_3 & = $2000 + 0.07A_2\
        & = $2000 + 0.07[$2000(1 + 0.07 + 0.07^2)]\
        & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000 + 0.07^3 cdot $2000\
        & = $2000(1 + 0.07 + 0.07^2 + 0.07^3)
        endalign*
        which suggests that
        $$A_n = $2000(1 + 0.07 + 0.07^2 + 0.07^3 + cdots + 0.07^n) = $2000sum_k = 0^n 0.07^k$$
        which you can prove by induction.



        As for finding an explicit formula, you can use the geometric series formula
        $$A_n = a(1 + r + r^2 + cdots + r^n) = afrac1 - r^n + 11 - r, r neq 1$$
        with $a = $2000$ and $r = 0.07$.






        share|cite|improve this answer














        At the end of the $n$th year, you invest $$2000$ and earn $7%$ interest on what you earned the previous year. Hence,
        $$A_n = $2000 + 0.07A_n - 1, n geq 1$$
        which is the recurrence relation. The initial value in your account is $A_0 = $2000$.



        Let's examine what happens during the first few years.
        beginalign*
        A_0 & = $2000\
        A_1 & = $2000 + 0.07A_0\
        & = $2000 + 0.07 cdot $2000\
        & = $2000(1 + 0.07)\
        A_2 & = $2000 + 0.07A_1\
        & = $2000 + 0.07[$2000(1 + 0.07)]\
        & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000\
        & = $2000(1 + 0.07 + 0.07^2)\
        A_3 & = $2000 + 0.07A_2\
        & = $2000 + 0.07[$2000(1 + 0.07 + 0.07^2)]\
        & = $2000 + 0.07 cdot $2000 + 0.07^2 cdot $2000 + 0.07^3 cdot $2000\
        & = $2000(1 + 0.07 + 0.07^2 + 0.07^3)
        endalign*
        which suggests that
        $$A_n = $2000(1 + 0.07 + 0.07^2 + 0.07^3 + cdots + 0.07^n) = $2000sum_k = 0^n 0.07^k$$
        which you can prove by induction.



        As for finding an explicit formula, you can use the geometric series formula
        $$A_n = a(1 + r + r^2 + cdots + r^n) = afrac1 - r^n + 11 - r, r neq 1$$
        with $a = $2000$ and $r = 0.07$.







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        edited Sep 10 at 10:15

























        answered Sep 10 at 8:06









        N. F. Taussig

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