Marginal distribiution of X and Y

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"The joint density function of (X,Y) is given by: f(x,y)=2 for |x|<=0.5,|y|<=0.5 and xy>=0.Otherwise f(x,y) equals 0. Find the marginal distribitions of X and Y and check if they are independent. "
I was thinking about something like this,
$$fx(x)=int_0.5^0.5 2;mathrmdy=2$$
but the proper answer is supposed to be one(for X and Y).










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    You need to consider that $xygeq 0$. The limits will be from 0 to 0.5, or from -0.5 to 0. Either case will result in 1.
    – BlackMath
    Sep 10 at 7:17














up vote
1
down vote

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"The joint density function of (X,Y) is given by: f(x,y)=2 for |x|<=0.5,|y|<=0.5 and xy>=0.Otherwise f(x,y) equals 0. Find the marginal distribitions of X and Y and check if they are independent. "
I was thinking about something like this,
$$fx(x)=int_0.5^0.5 2;mathrmdy=2$$
but the proper answer is supposed to be one(for X and Y).










share|cite|improve this question

















  • 3




    You need to consider that $xygeq 0$. The limits will be from 0 to 0.5, or from -0.5 to 0. Either case will result in 1.
    – BlackMath
    Sep 10 at 7:17












up vote
1
down vote

favorite









up vote
1
down vote

favorite











"The joint density function of (X,Y) is given by: f(x,y)=2 for |x|<=0.5,|y|<=0.5 and xy>=0.Otherwise f(x,y) equals 0. Find the marginal distribitions of X and Y and check if they are independent. "
I was thinking about something like this,
$$fx(x)=int_0.5^0.5 2;mathrmdy=2$$
but the proper answer is supposed to be one(for X and Y).










share|cite|improve this question













"The joint density function of (X,Y) is given by: f(x,y)=2 for |x|<=0.5,|y|<=0.5 and xy>=0.Otherwise f(x,y) equals 0. Find the marginal distribitions of X and Y and check if they are independent. "
I was thinking about something like this,
$$fx(x)=int_0.5^0.5 2;mathrmdy=2$$
but the proper answer is supposed to be one(for X and Y).







probability marginal-distribution






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asked Sep 10 at 7:12









Adam Stawarek

61




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  • 3




    You need to consider that $xygeq 0$. The limits will be from 0 to 0.5, or from -0.5 to 0. Either case will result in 1.
    – BlackMath
    Sep 10 at 7:17












  • 3




    You need to consider that $xygeq 0$. The limits will be from 0 to 0.5, or from -0.5 to 0. Either case will result in 1.
    – BlackMath
    Sep 10 at 7:17







3




3




You need to consider that $xygeq 0$. The limits will be from 0 to 0.5, or from -0.5 to 0. Either case will result in 1.
– BlackMath
Sep 10 at 7:17




You need to consider that $xygeq 0$. The limits will be from 0 to 0.5, or from -0.5 to 0. Either case will result in 1.
– BlackMath
Sep 10 at 7:17










1 Answer
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Hints:



$$f_X(x)=int f_X,Y(x,y)dytext and f_Y(y)=int f_X,Y(x,y)dx$$



If there is independence then $f_X(x)f_Y(y)$ serves as PDF of $(X,Y)$, so check if that is indeed the case here and draw conclusions.






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    1 Answer
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    1 Answer
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    down vote













    Hints:



    $$f_X(x)=int f_X,Y(x,y)dytext and f_Y(y)=int f_X,Y(x,y)dx$$



    If there is independence then $f_X(x)f_Y(y)$ serves as PDF of $(X,Y)$, so check if that is indeed the case here and draw conclusions.






    share|cite|improve this answer
























      up vote
      0
      down vote













      Hints:



      $$f_X(x)=int f_X,Y(x,y)dytext and f_Y(y)=int f_X,Y(x,y)dx$$



      If there is independence then $f_X(x)f_Y(y)$ serves as PDF of $(X,Y)$, so check if that is indeed the case here and draw conclusions.






      share|cite|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        Hints:



        $$f_X(x)=int f_X,Y(x,y)dytext and f_Y(y)=int f_X,Y(x,y)dx$$



        If there is independence then $f_X(x)f_Y(y)$ serves as PDF of $(X,Y)$, so check if that is indeed the case here and draw conclusions.






        share|cite|improve this answer












        Hints:



        $$f_X(x)=int f_X,Y(x,y)dytext and f_Y(y)=int f_X,Y(x,y)dx$$



        If there is independence then $f_X(x)f_Y(y)$ serves as PDF of $(X,Y)$, so check if that is indeed the case here and draw conclusions.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Sep 10 at 7:47









        drhab

        89.4k541123




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