Python 3.6 Runtime overflow encountered
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0
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This error happens, when I try to run this line in a loop:
sum((X@theta - y)**2)/2/len(X)
After the 5th loop, i start to get the error.
RuntimeWarning: overflow encountered in square
RuntimeWarning: overflow encountered in multiply
RuntimeWarning: overflow encountered in add
What to do, should I round the array or something? How?
If i try round(sum((X@theta - y)**2)/2/len(X),5)
, i get this error
TypeError: type numpy.ndarray doesn't define __ round__ method
python numpy spyder
New contributor
add a comment |
up vote
0
down vote
favorite
This error happens, when I try to run this line in a loop:
sum((X@theta - y)**2)/2/len(X)
After the 5th loop, i start to get the error.
RuntimeWarning: overflow encountered in square
RuntimeWarning: overflow encountered in multiply
RuntimeWarning: overflow encountered in add
What to do, should I round the array or something? How?
If i try round(sum((X@theta - y)**2)/2/len(X),5)
, i get this error
TypeError: type numpy.ndarray doesn't define __ round__ method
python numpy spyder
New contributor
Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday
A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday
or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday
A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
This error happens, when I try to run this line in a loop:
sum((X@theta - y)**2)/2/len(X)
After the 5th loop, i start to get the error.
RuntimeWarning: overflow encountered in square
RuntimeWarning: overflow encountered in multiply
RuntimeWarning: overflow encountered in add
What to do, should I round the array or something? How?
If i try round(sum((X@theta - y)**2)/2/len(X),5)
, i get this error
TypeError: type numpy.ndarray doesn't define __ round__ method
python numpy spyder
New contributor
This error happens, when I try to run this line in a loop:
sum((X@theta - y)**2)/2/len(X)
After the 5th loop, i start to get the error.
RuntimeWarning: overflow encountered in square
RuntimeWarning: overflow encountered in multiply
RuntimeWarning: overflow encountered in add
What to do, should I round the array or something? How?
If i try round(sum((X@theta - y)**2)/2/len(X),5)
, i get this error
TypeError: type numpy.ndarray doesn't define __ round__ method
python numpy spyder
python numpy spyder
New contributor
New contributor
New contributor
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john doe
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Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday
A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday
or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday
A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday
add a comment |
Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday
A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday
or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday
A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday
Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday
Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday
A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday
A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday
or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday
or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday
A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday
A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday
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john doe is a new contributor. Be nice, and check out our Code of Conduct.
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Overflow means your numbers are getting too large to be stored. You should either use a different number type to store your values, or rethink your algorithm. Rounding is not going to help.
– 9769953
yesterday
A single number is getting large? Like 0.2345324324342423424234424324242342342342 ?
– john doe
yesterday
or total numbers in the matrix is getting large @9769953? I am new to python
– john doe
yesterday
A single number is too large (of a few numbers are; that doesn't matter); not the matrix size. Side note: your example number is not large in the sense of overflow, just in the sense or precision. A too large number would be 10^310, which is larger than double precision can store. As another aside: this is not specific to Python, but goes for nearly every programming language.
– 9769953
yesterday